AppleScript获得激活的应用程序

display dialog("test")仅当“ Finder”应用程序当前处于焦点/活动状态时，才可以使用AppleScript 运行代码（例如）。

如果从脚本编辑器中调用了脚本，这将起作用，因为它会“跳开”以检查下一个应用程序，但是如果双击Finder则将失败，因为Finder将始终排在最后一行。

tell application "System Events"
    set frontmostProcess to first process where it is frontmost
    set visible of frontmostProcess to false
    repeat while (frontmostProcess is frontmost)
        delay 0.2
    end repeat
    set secondFrontmost to name of first process where it is frontmost
    set frontmost of frontmostProcess to true
end tell

tell application (path to frontmost application as text)
    if "Finder" is in secondFrontmost then
        display dialog ("Finder was last in front")
    else
        display dialog (secondFrontmost & " was last in front")
    end if
end tell

_{为后代在此留下先前的答案}

最初没有正确阅读问题后，重新调整了整个答案；-)

tell application "System Events"
    set activeApp to name of first application process whose frontmost is true
    if "Finder" is in activeApp then
        display dialog ("test")
    else
        display dialog ("test2")
    end if
end tell