从Apple Script获取两个具有相同名称的实例的当前应用程序

当运行同一个应用程序的两个实例时，AppleScript如何处理活动应用程序的活动窗口？

下面的脚本解决了其他应用程序。可能是因为应用程序的名称和ID是相同的，它只按名称从列表中选择第一个。

tell application (path to frontmost application as text) to tell front window...

我使用该脚本来最大化当前窗口，但它不适用于同一个应用程序的两个实例：

tell application "Finder" to set {0, 0, dtw, dth} to bounds of window of desktop
try
    tell application (path to frontmost application as text) to tell front window
        set bounds to {0, 0, dtw, dth}
    end tell
on error
    tell application "System Events" to tell (process 1 where it is frontmost)
        try
            click (button 1 of window 1 where subrole is "AXZoomButton")
        end try
    end tell
end try

获取最前端应用程序的正确实例是不可能的，因为这两个实例具有相同的路径和相同的包标识符，应用程序将始终是第一个打开的实例。

你必须使用 最前面 process， 像这样：

tell application "System Events"
    tell (first process whose frontmost is true) to tell front window to if exists then
        set position to {0, 0}
        set size to {dtw, dth}
    end if
end tell