如何使用AppleScript从其POSIX路径中显示Finder中的文件？

6

我正在尝试创建一个AppleScript代码段，用于查找当前的随机壁纸并在Finder中显示它。我有以下代码片段，它将当前壁纸的POSIX路径作为字符串找到：

set plistFolderPath to path to preferences folder from user domain as string
set plistPath to plistFolderPath & "com.apple.desktop.plist"
tell application "System Events"
    tell property list file plistPath
        tell contents
            set thePath to value of property list item "NewChangePath" of property list item "default" of property list item "Background" & "/" & value of property list item "LastName" of property list item "default" of property list item "Background"
        end tell
    end tell
end tell

thePath 现在是一个形式的字符串：

/ Volumes / Archive / Widescreen wallpaper / 12345_Name_2560x1440.jpg

（注意空格）

我尝试在FInder中显示此路径，但我尝试过的所有内容都会导致错误：

tell application "Finder"
    reveal POSIX file of quoted form of thePath (* Error: "Can't get POSIX file of (blah)" *)
end tell

当我拥有的是POSIX路径时，如何在AppleScript中显示Finder中的路径名？

applescript

— 布兰特鲍比
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9

我认为你的问题是这样的quoted form。尝试这样的事情：

set thePath to POSIX file "/Volumes/Lion HD/Users/ngreenst/Desktop/image.jpg"
tell application "Finder" to reveal thePath

所以就 reveal thePath

— 内森格林斯坦
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如果我像你一样直接将路径粘贴到脚本中，这是有效的，但如果我使用reveal POSIX file thePath它，则返回“无法获取POSIX文件<路径>”错误。

— Brant Bobby

1

@BrantBobby这意味着当你收到它时路径有问题。尝试将其转换为字符串（set thePath to ... as string）。如果这不起作用，我将需要确切地看到输出是什么帮助（我无法测试;你的脚本不工作OMM）

— Nathan Greenstein

啊，添加as string了诀窍！我想我的假设thePath已经是一个字符串是错误的。

— Brant Bobby

4

set p to "/Applications/Utilities/AppleScript Editor.app"

# uses an existing window or makes a new window with your default settings
tell application "Finder"
    reopen # makes a new window if there are no open windows
    activate
    set target of window 1 to (POSIX file p as text)
end tell

# makes a new window that doesn't use your default bounds or view settings
tell application "Finder"
    reveal POSIX file p as text
    activate # focuses the window
end tell

— LRI
source