将列表列表转换为Pandas Dataframe

30

我正在尝试将如下所示的列表列表转换为Pandas Dataframe

[['New York Yankees ', '"Acevedo Juan"  ', 900000, ' Pitcher\n'], 
['New York Yankees ', '"Anderson Jason"', 300000, ' Pitcher\n'], 
['New York Yankees ', '"Clemens Roger" ', 10100000, ' Pitcher\n'], 
['New York Yankees ', '"Contreras Jose"', 5500000, ' Pitcher\n']]

我基本上是试图将数组中的每个项目转换为具有四列的pandas数据框。最好的方法是pd.Dataframe并不能完全满足我的需求。

pandas

— 阿拉维德·维鲁查米（Aravind Veluchamy）
source

在堆栈溢出中看到以下问题：stackoverflow.com/questions

— /.../…

36

import pandas as pd

data = [['New York Yankees', 'Acevedo Juan', 900000, 'Pitcher'], 
        ['New York Yankees', 'Anderson Jason', 300000, 'Pitcher'], 
        ['New York Yankees', 'Clemens Roger', 10100000, 'Pitcher'], 
        ['New York Yankees', 'Contreras Jose', 5500000, 'Pitcher']]

df = pd.DataFrame.from_records(data)

— 埃姆雷
source

4

您可以使用以下方法进一步完善它：DataFrame.from_records（data，columns = ['Team'，'Player'，'whatever-stat-is-that'，'position']）

— Juan Ignacio Gil

1

有没有一种方法可以更具体地指定进口？例如，我想指定DataFrame["Team"]必须引用每个子列表的第一项（即data[i][0]），并DataFrame["Position"]引用每个子列表的最后一项（即data[i][-1]）？

— 伊沃

@Ivo：使用columns的参数DataFrame.from_records。

— Emre

14

获得数据后：

import pandas as pd

data = [['New York Yankees ', '"Acevedo Juan"  ', 900000, ' Pitcher\n'], 
        ['New York Yankees ', '"Anderson Jason"', 300000, ' Pitcher\n'], 
        ['New York Yankees ', '"Clemens Roger" ', 10100000, ' Pitcher\n'], 
        ['New York Yankees ', '"Contreras Jose"', 5500000, ' Pitcher\n']]

您可以通过转置数据来创建数据框：

data_transposed = zip(data)
df = pd.DataFrame(data_transposed, columns=["Team", "Player", "Salary", "Role"])

其它的办法：

df = pd.DataFrame(data)
df = df.transpose()
df.columns = ["Team", "Player", "Salary", "Role"]

— 帕洛玛·曼萨诺（Paloma Manzano）
source

5

您可以将其直接定义为数据框，如下所示：

import pandas as pd

data = [['New York Yankees', 'Acevedo Juan', 900000, 'Pitcher'], 
        ['New York Yankees', 'Anderson Jason', 300000, 'Pitcher'], 
        ['New York Yankees', 'Clemens Roger', 10100000, 'Pitcher'], 
        ['New York Yankees', 'Contreras Jose', 5500000, 'Pitcher']]

data = pd.DataFrame(data)

— LUSAQX
source

1

import pandas as pd

data = [['New York Yankees', 'Acevedo Juan', 900000, 'Pitcher'],
        ['New York Yankees', 'Anderson Jason', 300000, 'Pitcher'], 
        ['New York Yankees', 'Clemens Roger', 10100000, 'Pitcher'], 
        ['New York Yankees', 'Contreras Jose', 5500000, 'Pitcher']]

df = pd.DataFrame(data)

— tharun___数据爱好者
source

0

到目前为止，这是最简单的：

import pandas as pd

data = [['New York Yankees', 'Acevedo Juan', 900000, 'Pitcher'], 
        ['New York Yankees', 'Anderson Jason', 300000, 'Pitcher'], 
        ['New York Yankees', 'Clemens Roger', 10100000, 'Pitcher'], 
        ['New York Yankees', 'Contreras Jose', 5500000, 'Pitcher']]

data = pd.DataFrame(data)

现在，如果键是列表列表中的第一个列表（数据[0]），则可以将其分配给数据框中的列标题，如下所示：

import pandas as pd

data = [['key1', 'key2', key3, 'key4'], 
    ['New York Yankees', 'Anderson Jason', 300000, 'Pitcher'], 
    ['New York Yankees', 'Clemens Roger', 10100000, 'Pitcher'], 
    ['New York Yankees', 'Contreras Jose', 5500000, 'Pitcher']]

data = pd.DataFrame(data[1:], columns=data[0])

— 甘蔗糖
source