在SQL Server 2012中,我具有连接到另一个表的表值函数,我需要为此“表值函数”计算行数。检查执行计划时,可以看到左侧的联接表。为什么?左连接表如何影响返回的行数?我希望数据库引擎不需要在SELECT count(..)查询中评估左联合表。
Select count(realtyId) FROM [dbo].[GetFilteredRealtyFulltext]('"praha"')
执行计划:
表值函数:
CREATE FUNCTION [dbo].[GetFilteredRealtyFulltext]
(@criteria nvarchar(4000))
RETURNS TABLE
AS
RETURN (SELECT
realty.Id AS realtyId,
realty.OwnerId,
realty.Caption AS realtyCaption,
realty.BusinessCategory,
realty.Created,
realty.LastChanged,
realty.LastChangedType,
realty.Price,
realty.Pricing,
realty.PriceCurrency,
realty.PriceNote,
realty.PricePlus,
realty.OfferState,
realty.OrderCode,
realty.PublishAddress,
realty.PublishMap,
realty.AreaLand,
realty.AreaCover,
realty.AreaFloor,
realty.Views,
realty.TopPoints,
realty.Radius,
COALESCE(realty.Wgs84X, ruian_cobce.Wgs84X, ruian_obec.Wgs84X) as Wgs84X,
COALESCE(realty.Wgs84Y, ruian_cobce.Wgs84Y, ruian_obec.Wgs84Y) as Wgs84Y,
realty.krajId,
realty.okresId,
realty.obecId,
realty.cobceId,
IsNull(CONVERT(int,realty.Ranking),0) as Ranking,
realty.energy_efficiency_rating,
realty.energy_performance_attachment,
realty.energy_performance_certificate,
realty.energy_performance_summary,
Category.Id AS CategoryId,
Category.ParentCategoryId,
Category.WholeName,
okres.nazev AS okres,
ruian_obec.nazev AS obec,
ruian_cobce.nazev AS cobce,
ExternFile.ServerPath,
Person.ParentPersonId,
( COALESCE(ftR.Rank,0) + COALESCE(ftObec.Rank,0) + COALESCE(ftOkres.Rank,0) + COALESCE(ftpobvod.Rank,0)) AS FtRank
FROM realty
JOIN Category ON realty.CategoryId = Category.Id
LEFT JOIN ruian_cobce ON realty.cobceId = ruian_cobce.cobce_kod
LEFT JOIN ruian_obec ON realty.obecId = ruian_obec.obec_kod
LEFT JOIN okres ON realty.okresId = okres.okres_kod
LEFT JOIN ExternFile ON realty.Id = ExternFile.ForeignId AND ExternFile.IsMain = 1 AND ExternFile.ForeignTable = 5
INNER JOIN Person ON realty.OwnerId = Person.Id
Left JOIN CONTAINSTABLE(Realty, *, @criteria) ftR ON realty.Id = ftR.[Key]
Left JOIN CONTAINSTABLE(ruian_obec, *, @criteria) ftObec ON realty.obecId = ftObec.[Key]
Left JOIN CONTAINSTABLE(Okres, *, @criteria) ftOkres ON realty.okresId = ftOkres.[Key]
Left JOIN CONTAINSTABLE(pobvod, *, @criteria) ftpobvod ON realty.pobvodId = ftpobvod.[Key]
WHERE Person.ConfirmStatus = 1
AND ( COALESCE(ftR.Rank,0) + COALESCE(ftObec.Rank,0) + COALESCE(ftOkres.Rank,0) + COALESCE(ftpobvod.Rank,0)) > 0
)
更新:
我添加唯一索引来遵循Rob Farley的想法:
Create unique nonclustered index ExternFileIsMainUnique ON ExternFile(ForeignId) WHERE IsMain = 1 AND ForeignTable = 5
并由数据库引擎建议索引:
CREATE NONCLUSTERED INDEX [RealtyOwnerLocation] ON [dbo].[Realty]
([OwnerId] ASC)包括([Id],[okresId],[obecId],[pobvodId])GO
为简单起见,我删除了条件
WHERE Person.ConfirmStatus = 1
来自上面的表值函数。
现在执行计划要简单得多,但仍然可以使用表ExternFile:
也许SQL Server不够聪明?