SQL Server返回“将表达式转换为数据类型int的算术溢出错误”。

当我用 SUM()

SELECT COUNT(*) AS [Records], SUM(t.Amount) AS [Total]
FROM   dbo.t1 AS t
WHERE  t.Id > 0
       AND t.Id < 101;

我越来越，

Arithmetic overflow error converting expression to data type int.

知道是什么原因造成的吗？

我只是按照此答案中的说明进行操作。

对于大于INT最大值（2,147,483,647）的值，您将要使用COUNT_BIG（*）。

SELECT COUNT_BIG(*) AS [Records], SUM(t.Amount) AS [Total]
FROM   dbo.t1 AS t
WHERE  t.Id > 0
       AND t.Id < 101;

如果发生在中SUM，则需要转换Amount为BIGINT。

SELECT COUNT(*) AS [Records], SUM(CONVERT(BIGINT, t.Amount)) AS [Total]
FROM   dbo.t1 AS t
WHERE  t.Id > 0
       AND t.Id < 101;

此问题是由SUM()功能引起的

你要投t.Amount的BIGINT

SELECT COUNT(*) AS [Records], SUM(CAST(t.Amount AS BIGINT)) AS [Total]
FROM   dbo.t1 AS t
WHERE  t.Id > 0
       AND t.Id < 101;

参考

• /programming/8289310/how-to-prevent-arithmetic-overflow-error-when-using-sum-on-int-column