列出给定角色的所有权限?


23

我到处搜索,还没有找到这个问题的最终答案。

我需要一个可以为关联角色提供所有权限的脚本。

有什么想法,甚至有可能吗?

这让我很接近-但我似乎无法将其翻转并给出角色而不是用户的摘要。

http://consultingblogs.emc.com/jamiethomson/archive/2007/02/09/SQL-Server-2005_3A00_-View-all-permissions--_2800_2_2900_.aspx

 WITH    perms_cte as
(
        select USER_NAME(p.grantee_principal_id) AS principal_name,
                dp.principal_id,
                dp.type_desc AS principal_type_desc,
                p.class_desc,
                OBJECT_NAME(p.major_id) AS object_name,
                p.permission_name,
                p.state_desc AS permission_state_desc
        from    sys.database_permissions p
        inner   JOIN sys.database_principals dp
        on     p.grantee_principal_id = dp.principal_id
)
--role members
SELECT rm.member_principal_name, rm.principal_type_desc, p.class_desc, 
    p.object_name, p.permission_name, p.permission_state_desc,rm.role_name
FROM    perms_cte p
right outer JOIN (
    select role_principal_id, dp.type_desc as principal_type_desc, 
   member_principal_id,user_name(member_principal_id) as member_principal_name,
   user_name(role_principal_id) as role_name--,*
    from    sys.database_role_members rm
    INNER   JOIN sys.database_principals dp
    ON     rm.member_principal_id = dp.principal_id
) rm
ON     rm.role_principal_id = p.principal_id
order by 1

Answers:


19

我们想出了这个方法,它似乎有效:

SELECT DISTINCT rp.name, 
                ObjectType = rp.type_desc, 
                PermissionType = pm.class_desc, 
                pm.permission_name, 
                pm.state_desc, 
                ObjectType = CASE 
                               WHEN obj.type_desc IS NULL 
                                     OR obj.type_desc = 'SYSTEM_TABLE' THEN 
                               pm.class_desc 
                               ELSE obj.type_desc 
                             END, 
                s.Name as SchemaName,
                [ObjectName] = Isnull(ss.name, Object_name(pm.major_id)) 
FROM   sys.database_principals rp 
       INNER JOIN sys.database_permissions pm 
               ON pm.grantee_principal_id = rp.principal_id 
       LEFT JOIN sys.schemas ss 
              ON pm.major_id = ss.schema_id 
       LEFT JOIN sys.objects obj 
              ON pm.[major_id] = obj.[object_id] 
       LEFT JOIN sys.schemas s
              ON s.schema_id = obj.schema_id
WHERE  rp.type_desc = 'DATABASE_ROLE' 
       AND pm.class_desc <> 'DATABASE' 
ORDER  BY rp.name, 
          rp.type_desc, 
          pm.class_desc 

添加了字段SchemaName以及从对象向架构的左连接。我不了解对方案的第一个左联接的目的,这里始终为null。
crokusek '16

但是,如果数据库角色被授予对某种类型(例如“ GRANT SELECT TO Some_DB_Role”)的所有对象的权限,该脚本将不会显示?
Jhunter1

14

我找不到参考资料,但这是一个描述性很强的脚本(我已经在我的存储库中使用了多年,对审核非常有用):

/*


--Script source found at :  http://stackoverflow.com/a/7059579/1387418
Security Audit Report
1) List all access provisioned to a sql user or windows user/group directly 
2) List all access provisioned to a sql user or windows user/group through a database or application role
3) List all access provisioned to the public role

Columns Returned:
UserName        : SQL or Windows/Active Directory user cccount.  This could also be an Active Directory group.
UserType        : Value will be either 'SQL User' or 'Windows User'.  This reflects the type of user defined for the 
                  SQL Server user account.
DatabaseUserName: Name of the associated user as defined in the database user account.  The database user may not be the
                  same as the server user.
Role            : The role name.  This will be null if the associated permissions to the object are defined at directly
                  on the user account, otherwise this will be the name of the role that the user is a member of.
PermissionType  : Type of permissions the user/role has on an object. Examples could include CONNECT, EXECUTE, SELECT
                  DELETE, INSERT, ALTER, CONTROL, TAKE OWNERSHIP, VIEW DEFINITION, etc.
                  This value may not be populated for all roles.  Some built in roles have implicit permission
                  definitions.
PermissionState : Reflects the state of the permission type, examples could include GRANT, DENY, etc.
                  This value may not be populated for all roles.  Some built in roles have implicit permission
                  definitions.
ObjectType      : Type of object the user/role is assigned permissions on.  Examples could include USER_TABLE, 
                  SQL_SCALAR_FUNCTION, SQL_INLINE_TABLE_VALUED_FUNCTION, SQL_STORED_PROCEDURE, VIEW, etc.   
                  This value may not be populated for all roles.  Some built in roles have implicit permission
                  definitions.          
ObjectName      : Name of the object that the user/role is assigned permissions on.  
                  This value may not be populated for all roles.  Some built in roles have implicit permission
                  definitions.
ColumnName      : Name of the column of the object that the user/role is assigned permissions on. This value
                  is only populated if the object is a table, view or a table value function.                 
*/

--List all access provisioned to a sql user or windows user/group directly 
SELECT  
    [UserName] = CASE princ.[type] 
                    WHEN 'S' THEN princ.[name]
                    WHEN 'U' THEN ulogin.[name] COLLATE Latin1_General_CI_AI
                 END,
    [UserType] = CASE princ.[type]
                    WHEN 'S' THEN 'SQL User'
                    WHEN 'U' THEN 'Windows User'
                 END,  
    [DatabaseUserName] = princ.[name],       
    [Role] = null,      
    [PermissionType] = perm.[permission_name],       
    [PermissionState] = perm.[state_desc],       
    [ObjectType] = obj.type_desc,--perm.[class_desc],       
    [ObjectName] = OBJECT_NAME(perm.major_id),
    [ColumnName] = col.[name]
FROM    
    --database user
    sys.database_principals princ  
LEFT JOIN
    --Login accounts
    sys.login_token ulogin on princ.[sid] = ulogin.[sid]
LEFT JOIN        
    --Permissions
    sys.database_permissions perm ON perm.[grantee_principal_id] = princ.[principal_id]
LEFT JOIN
    --Table columns
    sys.columns col ON col.[object_id] = perm.major_id 
                    AND col.[column_id] = perm.[minor_id]
LEFT JOIN
    sys.objects obj ON perm.[major_id] = obj.[object_id]
WHERE 
    princ.[type] in ('S','U')
UNION
--List all access provisioned to a sql user or windows user/group through a database or application role
SELECT  
    [UserName] = CASE memberprinc.[type] 
                    WHEN 'S' THEN memberprinc.[name]
                    WHEN 'U' THEN ulogin.[name] COLLATE Latin1_General_CI_AI
                 END,
    [UserType] = CASE memberprinc.[type]
                    WHEN 'S' THEN 'SQL User'
                    WHEN 'U' THEN 'Windows User'
                 END, 
    [DatabaseUserName] = memberprinc.[name],   
    [Role] = roleprinc.[name],      
    [PermissionType] = perm.[permission_name],       
    [PermissionState] = perm.[state_desc],       
    [ObjectType] = obj.type_desc,--perm.[class_desc],   
    [ObjectName] = OBJECT_NAME(perm.major_id),
    [ColumnName] = col.[name]
FROM    
    --Role/member associations
    sys.database_role_members members
JOIN
    --Roles
    sys.database_principals roleprinc ON roleprinc.[principal_id] = members.[role_principal_id]
JOIN
    --Role members (database users)
    sys.database_principals memberprinc ON memberprinc.[principal_id] = members.[member_principal_id]
LEFT JOIN
    --Login accounts
    sys.login_token ulogin on memberprinc.[sid] = ulogin.[sid]
LEFT JOIN        
    --Permissions
    sys.database_permissions perm ON perm.[grantee_principal_id] = roleprinc.[principal_id]
LEFT JOIN
    --Table columns
    sys.columns col on col.[object_id] = perm.major_id 
                    AND col.[column_id] = perm.[minor_id]
LEFT JOIN
    sys.objects obj ON perm.[major_id] = obj.[object_id]
UNION
--List all access provisioned to the public role, which everyone gets by default
SELECT  
    [UserName] = '{All Users}',
    [UserType] = '{All Users}', 
    [DatabaseUserName] = '{All Users}',       
    [Role] = roleprinc.[name],      
    [PermissionType] = perm.[permission_name],       
    [PermissionState] = perm.[state_desc],       
    [ObjectType] = obj.type_desc,--perm.[class_desc],  
    [ObjectName] = OBJECT_NAME(perm.major_id),
    [ColumnName] = col.[name]
FROM    
    --Roles
    sys.database_principals roleprinc
LEFT JOIN        
    --Role permissions
    sys.database_permissions perm ON perm.[grantee_principal_id] = roleprinc.[principal_id]
LEFT JOIN
    --Table columns
    sys.columns col on col.[object_id] = perm.major_id 
                    AND col.[column_id] = perm.[minor_id]                   
JOIN 
    --All objects   
    sys.objects obj ON obj.[object_id] = perm.[major_id]
WHERE
    --Only roles
    roleprinc.[type] = 'R' AND
    --Only public role
    roleprinc.[name] = 'public' AND
    --Only objects of ours, not the MS objects
    obj.is_ms_shipped = 0
ORDER BY
    princ.[Name],
    OBJECT_NAME(perm.major_id),
    col.[name],
    perm.[permission_name],
    perm.[state_desc],
    obj.type_desc--perm.[class_desc] 

10

我认为应该这样做,用您的角色名称或数据库用户替换“ blah”(请注意,内置角色不会显示为具有任何权限):

SELECT DB_NAME() AS 'DBName'
      ,p.[name] AS 'PrincipalName'
      ,p.[type_desc] AS 'PrincipalType'
      ,p2.[name] AS 'GrantedBy'
      ,dbp.[permission_name]
      ,dbp.[state_desc]
      ,so.[Name] AS 'ObjectName'
      ,so.[type_desc] AS 'ObjectType'
  FROM [sys].[database_permissions] dbp LEFT JOIN [sys].[objects] so
    ON dbp.[major_id] = so.[object_id] LEFT JOIN [sys].[database_principals] p
    ON dbp.[grantee_principal_id] = p.[principal_id] LEFT JOIN [sys].[database_principals] p2
    ON dbp.[grantor_principal_id] = p2.[principal_id]

WHERE p.[name] = 'blah'

有点...似乎不包含对象名称/类型。对于我正在查看的特定角色,该角色已经执行,并且对模式具有其他几个权限,它显示为null。两行显示ObjectName为sysrowsets和ObjectType为SYSTEM_TABLE。

4

只是添加到列表中,我有几个SPs sp_dbpermissionssp_srvpermissions可用于返回相同类型的信息。

你可以跑

EXEC sp_dbpermissions 'dbname','rolename (or any other principal really)'

并得到这个

在此处输入图片说明

(您看不到它,但是授权脚本位于第三个数据集的右侧,而拖放/创建脚本位于第一个数据集的右侧。)


3

这是我的努力。我有一个较长的脚本,它也可以遍历所有数据库,请让我知道它是否更有用:

SELECT 
@@Servername as ServerName
,DB_NAME() AS DatabaseName
,d.name AS DatabaseUser
,ISNULL(dr.name, 'Public') AS DatabaseRole
,dp.permission_name as AdditionalPermission
,dp.state_desc AS PermissionState
,ISNULL(o.type_desc, 'N/A')  AS ObjectType
,ISNULL(o.name, 'N/A') AS ObjectName
FROM sys.database_principals d
    LEFT JOIN sys.database_role_members r
        ON d.principal_id = r.member_principal_id 
    LEFT JOIN sys.database_principals dr
        ON r.role_principal_id = dr.principal_id 
    left JOIN   sys.database_permissions dp
        ON d.principal_id = dp.grantee_principal_id
    LEFT JOIN sys.objects o
        ON dp.major_id = o.object_id 

我删除了临时表。对于那个很抱歉!
JYatesDBA'17年

这对于一个数据库非常有用,我可以看看您如何遍历所有数据库吗?

3

添加到已接受的答案中一个角色有时可以属于另一个角色。

DECLARE @ROLE VARCHAR(108)
select @role = 'db_BodenProcessor'

;WITH theRoles (member_principal_id, role_principal_id) 
AS 
(
  SELECT 
   r.member_principal_id, 
   r.role_principal_id
  FROM sys.database_role_members r 
   UNION ALL
  SELECT 
   tr.member_principal_id, 
   rm.role_principal_id
  FROM sys.database_role_members rm 
            INNER JOIN theRoles tr 
                    ON rm.member_principal_id = tr.role_principal_id
)

--select * from theRoles


select  the_role=A.name
       ,A.is_fixed_role
       ,role_member=B.name
       ,B.type_desc
from theRoles tr
        INNER JOIN sys.database_principals A 
                ON tr.role_principal_id = A.principal_id
        INNER JOIN sys.database_principals B 
                ON tr.member_principal_id = B.principal_id
WHERE A.NAME = @ROLE
   OR B.name = @ROLE
GROUP BY A.name
       ,A.is_fixed_role
       ,B.name
       ,B.type_desc
order by a.is_fixed_role DESC
        ,a.name

在此处输入图片说明


3

由于此消息是通过社区机器人弹出的,因此我将抛出脚本放到帽子里,因为它很详尽,而且我还没有遇到任何无法识别的东西。额外的好处是输出的格式很好,并且还允许大量的数据库角色:

/********************************************************************
 *                                                                  *
 * Author: John Eisbrener                                           *
 * Script Purpose: Script out Database Role Definition              *
 * Notes: Please report any bugs to http://www.dbaeyes.com/         *
 *                                                                  *
 * Update: 2014-03-03 - Adjusted output to accommodate Role         *
 *                      definitions that are longer than 8000 chars *
 * Update: 2013-09-03 - Added user output per Joe Spivey's comment  *
 *                    - Modified formatting for oddly named objects *
 *                    - Included support for Grants on DMVs         *
 ********************************************************************/
DECLARE @roleName VARCHAR(255)
SET @roleName = 'DatabaseRoleName'

-- Script out the Role
DECLARE @roleDesc VARCHAR(MAX), @crlf VARCHAR(2)
SET @crlf = CHAR(13) + CHAR(10)
SET @roleDesc = 'CREATE ROLE [' + @roleName + ']' + @crlf + 'GO' + @crlf + @crlf

SELECT    @roleDesc = @roleDesc +
        CASE dp.state
            WHEN 'D' THEN 'DENY '
            WHEN 'G' THEN 'GRANT '
            WHEN 'R' THEN 'REVOKE '
            WHEN 'W' THEN 'GRANT '
        END + 
        dp.permission_name + ' ' +
        CASE dp.class
            WHEN 0 THEN ''
            WHEN 1 THEN --table or column subset on the table
                CASE WHEN dp.major_id < 0 THEN
                    + 'ON [sys].[' + OBJECT_NAME(dp.major_id) + '] '
                ELSE
                    + 'ON [' +
                    (SELECT SCHEMA_NAME(schema_id) + '].[' + name FROM sys.objects WHERE object_id = dp.major_id)
                        + -- optionally concatenate column names
                    CASE WHEN MAX(dp.minor_id) > 0 
                         THEN '] ([' + REPLACE(
                                        (SELECT name + '], [' 
                                         FROM sys.columns 
                                         WHERE object_id = dp.major_id 
                                            AND column_id IN (SELECT minor_id 
                                                              FROM sys.database_permissions 
                                                              WHERE major_id = dp.major_id
                                                                AND USER_NAME(grantee_principal_id) IN (@roleName)
                                                             )
                                         FOR XML PATH('')
                                        ) --replace final square bracket pair
                                    + '])', ', []', '')
                         ELSE ']'
                    END + ' '
                END
            WHEN 3 THEN 'ON SCHEMA::[' + SCHEMA_NAME(dp.major_id) + '] '
            WHEN 4 THEN 'ON ' + (SELECT RIGHT(type_desc, 4) + '::[' + name FROM sys.database_principals WHERE principal_id = dp.major_id) + '] '
            WHEN 5 THEN 'ON ASSEMBLY::[' + (SELECT name FROM sys.assemblies WHERE assembly_id = dp.major_id) + '] '
            WHEN 6 THEN 'ON TYPE::[' + (SELECT name FROM sys.types WHERE user_type_id = dp.major_id) + '] '
            WHEN 10 THEN 'ON XML SCHEMA COLLECTION::[' + (SELECT SCHEMA_NAME(schema_id) + '.' + name FROM sys.xml_schema_collections WHERE xml_collection_id = dp.major_id) + '] '
            WHEN 15 THEN 'ON MESSAGE TYPE::[' + (SELECT name FROM sys.service_message_types WHERE message_type_id = dp.major_id) + '] '
            WHEN 16 THEN 'ON CONTRACT::[' + (SELECT name FROM sys.service_contracts WHERE service_contract_id = dp.major_id) + '] '
            WHEN 17 THEN 'ON SERVICE::[' + (SELECT name FROM sys.services WHERE service_id = dp.major_id) + '] '
            WHEN 18 THEN 'ON REMOTE SERVICE BINDING::[' + (SELECT name FROM sys.remote_service_bindings WHERE remote_service_binding_id = dp.major_id) + '] '
            WHEN 19 THEN 'ON ROUTE::[' + (SELECT name FROM sys.routes WHERE route_id = dp.major_id) + '] '
            WHEN 23 THEN 'ON FULLTEXT CATALOG::[' + (SELECT name FROM sys.fulltext_catalogs WHERE fulltext_catalog_id = dp.major_id) + '] '
            WHEN 24 THEN 'ON SYMMETRIC KEY::[' + (SELECT name FROM sys.symmetric_keys WHERE symmetric_key_id = dp.major_id) + '] '
            WHEN 25 THEN 'ON CERTIFICATE::[' + (SELECT name FROM sys.certificates WHERE certificate_id = dp.major_id) + '] '
            WHEN 26 THEN 'ON ASYMMETRIC KEY::[' + (SELECT name FROM sys.asymmetric_keys WHERE asymmetric_key_id = dp.major_id) + '] '
         END COLLATE SQL_Latin1_General_CP1_CI_AS
         + 'TO [' + @roleName + ']' + 
         CASE dp.state WHEN 'W' THEN ' WITH GRANT OPTION' ELSE '' END + @crlf
FROM    sys.database_permissions dp
WHERE    USER_NAME(dp.grantee_principal_id) IN (@roleName)
GROUP BY dp.state, dp.major_id, dp.permission_name, dp.class

SELECT @roleDesc = @roleDesc + 'GO' + @crlf + @crlf      

-- Display users within Role.  Code stubbed by Joe Spivey
SELECT  @roleDesc = @roleDesc + 'EXECUTE sp_AddRoleMember ''' + roles.name + ''', ''' + users.name + '''' + @crlf
FROM    sys.database_principals users
        INNER JOIN sys.database_role_members link 
            ON link.member_principal_id = users.principal_id
        INNER JOIN sys.database_principals roles 
            ON roles.principal_id = link.role_principal_id
WHERE   roles.name = @roleName

-- PRINT out in blocks of up to 8000 based on last \r\n
DECLARE @printCur INT
SET @printCur = 8000

WHILE LEN(@roleDesc) > 8000
BEGIN
    -- Reverse first 8000 characters and look for first lf cr (reversed crlf) as delimiter
    SET @printCur = 8000 - CHARINDEX(CHAR(10) + CHAR(13), REVERSE(SUBSTRING(@roleDesc, 0, 8000)))

    PRINT LEFT(@roleDesc, @printCur)
    SELECT @roleDesc = RIGHT(@roleDesc, LEN(@roleDesc) - @printCur)
END

-- Output new permissions
PRINT @roleDesc + 'GO'
By using our site, you acknowledge that you have read and understand our Cookie Policy and Privacy Policy.
Licensed under cc by-sa 3.0 with attribution required.