Answers:
杰克已经证明了要走的路。但是,我觉得还有改进的余地。
我将所有内容都放在架构中x
以方便测试。测试设置:
DROP SCHEMA x CASCADE;
CREATE SCHEMA x;
-- meta tables for schema and table name
CREATE TABLE x.schma(schma_id int, schma text);
INSERT INTO x.schma VALUES (1, 'x');
CREATE TABLE x.tbl(tbl_id int, tbl text);
INSERT INTO x.tbl VALUES (1, 't1'), (2, 't2');
-- dummy tables to be used in example query:
CREATE TABLE x.t1(id int);
INSERT INTO x.t1 VALUES (1),(2);
CREATE TABLE x.t2(foo text);
INSERT INTO x.t2 VALUES ('some text'), ('some more text');
旧功能(原始答案):
CREATE OR REPLACE FUNCTION x.f_dynaquery_old(int, int, _col text, _type anyelement, OUT col anyelement)
RETURNS SETOF anyelement AS
$func$
BEGIN
RETURN QUERY EXECUTE '
SELECT ' || quote_ident(_col) || '
FROM ' || (
(SELECT schma FROM schma WHERE schma_id = $1) || '.' ||
(SELECT tbl FROM tbl WHERE tbl_id = $2))::regclass;
END
$func$ LANGUAGE plpgsql;
较干净的版本format()
(更新于2017年):
CREATE OR REPLACE FUNCTION x.f_dynaquery(_schma_id int, _tbl_id int
, _col text, _type anyelement)
RETURNS TABLE(col anyelement) AS
$func$
BEGIN
RETURN QUERY EXECUTE format(
'SELECT %I FROM %I.%I'
, _col
, (SELECT schma FROM schma WHERE schma_id = _schma_id)
, (SELECT tbl FROM tbl WHERE tbl_id = _tbl_id)
);
END
$func$ LANGUAGE plpgsql;
COMMENT ON FUNCTION x.f_dynaquery(int, int, text, anyelement)
IS 'Query any column from a dynamically assembled tablename.
$1 .. id of schema
$2 .. id of table
$3 .. name of column
$4 .. type of column (only data type matters, not the value)';
呼叫:
SELECT col FROM x.f_dynaquery(1, 1, 'id', NULL::int);
col
-----
1
2
SELECT col FROM x.f_dynaquery(1, 2, 'foo', NULL::text);
col
----------------
some text
some more text
通过在旧版本或新版本中使用quote_ident()
和强制转换为regclass
SQL防御format()
。有关:
通过查询请求OP检索表名。例子是通过查询,id
但是一切皆有可能。
为返回的列命名,因此更易于引用。
您需要动态SQL-也许像这样:
create role stack;
create schema authorization stack;
set role stack;
create or replace function f(p_schema in text, p_table in text)
returns setof integer language plpgsql immutable as $$
begin
return query execute 'select value from '||p_schema||'.'||p_table;
end;$$;
create table t1(value integer);
insert into t1(value) values (1);
insert into t1(value) values (2);
create table t2(value integer);
insert into t2(value) values (1);
create table schemas(schema_name text);
insert into schemas(schema_name) values ('stack');
create table tables(table_name text);
insert into tables(table_name) values ('t1');
insert into tables(table_name) values ('t2');
insert into tables(table_name) values ('t1');
insert into tables(table_name) values ('t2');
select f(schema_name, table_name) from schemas cross join tables;
f
---
1
2
1
(3 rows)
我假设问题暗示每个表都存在于每个模式中