遍历值一次剥离1个字符

我想遍历值并一次从值中删除1个字符并显示结果。

因此，如果我有一个带有值的表：

ID
___
34679
13390
89906

我希望结果看起来像这样

Id
----
4679
679
79
9
3390
390
90
0
9906
906
06
6

请不要对这样的事情使用循环（我也将递归CTE保留给您对事物（例如层次结构）的控制要少得多的场景。循环在SQL中是不好的。SQL已优化为可按集合工作。

DECLARE @foo TABLE(ID INT);

INSERT @foo VALUES(34679),(13390),(89906);

;WITH x AS 
(
  SELECT TOP (2048) n = ROW_NUMBER() OVER (ORDER BY Number)
  FROM master.dbo.spt_values ORDER BY Number
)
SELECT RIGHT(f.ID, x.n) FROM x
INNER JOIN @foo AS f
ON x.n < LEN(f.ID);

结果：

9
79
679
4679
0
90
390
3390
6
06
906
9906

• http://sqlperformance.com/generate-a-set-1
• http://sqlperformance.com/generate-a-set-2
• http://sqlperformance.com/generate-a-set-3

declare @MyString varchar(500)

set MyString = '1,2.3#45.#,.6'

select dbo.RemoveChars(MyString, '#,.')

create function [dbo].[RemoveChars] (
    @InputString varchar(MAX)
    ,@CharsToRemove varchar(500)
    )
returns varchar(MAX)
as
begin
    declare @len int
        ,@Counter int
        ,@OneChar char(1)

    set @Counter = 1
    set @len = LEN(@CharsToRemove);

    while (1 = 1)
    begin
        set @OneChar = SUBSTRING(@CharsToRemove, @Counter, 1)
        set @InputString = REPLACE(@InputString, @OneChar, '')
        set @Counter = @Counter + 1

        if (
                @Counter > @len
                or @Counter > 20
                )
            break;
    end

    return @InputString
end

CREATE PROC udploop (@num varchar(10))
AS
       BEGIN 
             DECLARE @len int; 
             SET @len = LEN(@num); 
             WHILE (@len > 1)
                   BEGIN    
                         SELECT
                            @num = RIGHT(@num, @len - 1); 
                         PRINT @num;
                         SET @len = LEN(@num);
                   END 
       END

执行：

EXEC udploop 34679 
EXEC udploop 13390 
EXEC udploop 89906

结果：

4679 
679 
79 
9 
3390 
390 
90 
0 
9906 
906 
06 
6