同一地址的Google标记未显示所有标记

我一直在制作这张地图-http: //www.mediwales.com/mapping/test/

它可以使公司处于良好状态并可以对其进行群集，但是位于同一建筑物中且地址相同的公司出现了问题。它仅显示一个公司，而不是全部。

如何获得在同一地址显示所有公司的信息？

标记按建筑物名称/编号，街道，城市，邮政编码进行地理编码。我猜标记在那里，因为有3家公司的建筑物在集群中显示3。但是，当您单击它时，它仅显示一个公司。

更新：

我设法使它们偏移，但是当我只希望有多个相同标记时才偏移所有标记时，就偏移所有标记。（感谢凯西的回答）。

   <script type="text/javascript">
    //<![CDATA[

    var customIcons = {
      restaurant: {
        icon: 'http://labs.google.com/ridefinder/images/mm_20_blue.png',
        shadow: 'http://labs.google.com/ridefinder/images/mm_20_shadow.png'
      },
      bar: {
        icon: 'http://labs.google.com/ridefinder/images/mm_20_red.png',
        shadow: 'http://labs.google.com/ridefinder/images/mm_20_shadow.png'
      }
    };

    function load() {
      var cluster = [];
      var map = new google.maps.Map(document.getElementById("map"), {
        center: new google.maps.LatLng(53.4788, -3.9551),
        zoom: 6,
        mapTypeId: 'roadmap'
      });
var infowindow = new google.maps.InfoWindow();
var min = .999999;
var max = 1.000001;

      // Change this depending on the name of your PHP file
      downloadUrl("<?php bloginfo('stylesheet_directory'); ?>/phpsqlajax_genxml.php ", function(data) {
        var xml = data.responseXML;
        var markers = xml.documentElement.getElementsByTagName("marker");
        for (var i = 0; i < markers.length; i++) {
          var name = markers[i].getAttribute("name");
          var address = markers[i].getAttribute("address");
          var type = markers[i].getAttribute("type");



          var offsetLat = markers[i].getAttribute("lat") * (Math.random() * (max - min) + min);
          var offsetLng = markers[i].getAttribute("lng") * (Math.random() * (max - min) + min);



          var point = new google.maps.LatLng(offsetLat, offsetLng);
          var html = "<b>" + name + "</b> <br/>" + address;
          var icon = customIcons[type] || {};
          var marker = new google.maps.Marker({
            map: map,
            position: point,
            icon: icon.icon,
            shadow: icon.shadow
          });
          google.maps.event.addListener(marker, 'click', (function(marker, i) {
                        return function() {
                            infowindow.setContent(markers[i].getAttribute("name"));
                            infowindow.open(map, marker);
                        }
                    })(marker, i));
          cluster.push(marker);
        }
        var mc = new MarkerClusterer(map,cluster);
      });
    }

    function bindInfoWindow(marker, map, infoWindow, html) {
      google.maps.event.addListener(marker, 'click', function() {
        infoWindow.setContent(html);
        infoWindow.open(map, marker);
      });
    }

    function downloadUrl(url, callback) {
      var request = window.ActiveXObject ?
          new ActiveXObject('Microsoft.XMLHTTP') :
          new XMLHttpRequest;

      request.onreadystatechange = function() {
        if (request.readyState == 4) {
          request.onreadystatechange = doNothing;
          callback(request, request.status);
        }
      };

      request.open('GET', url, true);
      request.send(null);
    }

    function doNothing() {}

    //]]>
  </script>

   <script type="text/javascript">
    //<![CDATA[

    var customIcons = {
      restaurant: {
        icon: 'http://labs.google.com/ridefinder/images/mm_20_blue.png',
        shadow: 'http://labs.google.com/ridefinder/images/mm_20_shadow.png'
      },
      bar: {
        icon: 'http://labs.google.com/ridefinder/images/mm_20_red.png',
        shadow: 'http://labs.google.com/ridefinder/images/mm_20_shadow.png'
      }
    };

    function load() {
      var cluster = [];
      var map = new google.maps.Map(document.getElementById("map"), {
        center: new google.maps.LatLng(53.4788, -3.9551),
        zoom: 6,
        mapTypeId: 'roadmap'
      });
var infowindow = new google.maps.InfoWindow();

      // Change this depending on the name of your PHP file
      downloadUrl("<?php bloginfo('stylesheet_directory'); ?>/phpsqlajax_genxml.php ", function(data) {
        var xml = data.responseXML;
        var markers = xml.documentElement.getElementsByTagName("marker");
        for (var i = 0; i < markers.length; i++) {
          var name = markers[i].getAttribute("name");
          var address = markers[i].getAttribute("address");
          var type = markers[i].getAttribute("type");
          var point = new google.maps.LatLng(
              parseFloat(markers[i].getAttribute("lat")),
              parseFloat(markers[i].getAttribute("lng")));
          var html = "<b>" + name + "</b> <br/>" + address;
          var icon = customIcons[type] || {};
          var marker = new google.maps.Marker({
            map: map,
            position: point,
            icon: icon.icon,
            shadow: icon.shadow
          });
          google.maps.event.addListener(marker, 'click', (function(marker, i) {
                        return function() {
                            infowindow.setContent(markers[i].getAttribute("name"));
                            infowindow.open(map, marker);
                        }
                    })(marker, i));
          cluster.push(marker);
        }
        var mc = new MarkerClusterer(map,cluster);
      });
    }

    function bindInfoWindow(marker, map, infoWindow, html) {
      google.maps.event.addListener(marker, 'click', function() {
        infoWindow.setContent(html);
        infoWindow.open(map, marker);
      });
    }

    function downloadUrl(url, callback) {
      var request = window.ActiveXObject ?
          new ActiveXObject('Microsoft.XMLHTTP') :
          new XMLHttpRequest;

      request.onreadystatechange = function() {
        if (request.readyState == 4) {
          request.onreadystatechange = doNothing;
          callback(request, request.status);
        }
      };

      request.open('GET', url, true);
      request.send(null);
    }

    function doNothing() {}

    //]]>
  </script>

群集显示正确。所有标记都在绘制中。问题在于您只能单击最上面的标记，从而似乎只有一个标记。

要查看重合标记的内容，您必须将基础标记的信息窗口内容传递给最上面的标记。

为此，首先要跟踪每个标记。您正在使用MarkerClusterer，因此markerClusterer实例将保存每个标记。当每个地址解析结果返回时，将该请求的延迟与所有已绘制的标记进行比较。您可以使用latlng对象的equals方法比较位置。

如果新标记与现有标记的位置匹配，请从第一个标记中获取信息窗口内容，并将其附加到新标记的信息窗口内容中。这样，当您单击最上面的标记（第二家公司）时，它将显示来自两家公司的信息。如果有两家以上的公司，则需要获取所有匹配标记的信息窗口内容。此方法还将允许标记聚类器仍然显示正确数量的标记。

这是一个工作示例和javascript代码。第一个和第二个地址相同。单击2的标记时，它将显示“ 2＆1”。

<script type="text/javascript"> 
var map;

//marker clusterer
var mc;
var mcOptions = {gridSize: 20, maxZoom: 17};

//global infowindow
var infowindow = new google.maps.InfoWindow();

//geocoder
var geocoder = new google.maps.Geocoder(); 

var address = new Array("1000 Market St, Philadelphia, PA","1000 Market St, Philadelphia, PA","1002 Market St, Philadelphia, PA","1004 Market St, Philadelphia, PA");
var content = new Array("1","2","3","4");

function createMarker(latlng,text) {

    var marker = new google.maps.Marker({
        position: latlng
    });

    ///get array of markers currently in cluster
    var allMarkers = mc.getMarkers();

    //check to see if any of the existing markers match the latlng of the new marker
    if (allMarkers.length != 0) {
        for (i=0; i < allMarkers.length; i++) {
            var currentMarker = allMarkers[i];
            var pos = currentMarker.getPosition();

            if (latlng.equals(pos)) {
                text = text + " & " + content[i];
            }

        }
    }

    google.maps.event.addListener(marker, 'click', function() {
        infowindow.close();
        infowindow.setContent(text);
        infowindow.open(map,marker);
    });

    return marker;
}

function geocodeAddress(address,i) {

    geocoder.geocode( {'address': address}, function(results, status) {

        if (status == google.maps.GeocoderStatus.OK) {

            var marker = createMarker(results[0].geometry.location,content[i]);
            mc.addMarker(marker);

        } else { 
            alert("Geocode was not successful for the following reason: " + status); 
        } 
    });
}

function initialize(){

    var options = { 
        zoom: 13, 
        center: new google.maps.LatLng(39.96225,-75.13222), 
        mapTypeId: google.maps.MapTypeId.ROADMAP 
    }; 

    map = new google.maps.Map(document.getElementById('map'), options); 

    //marker cluster
    mc = new MarkerClusterer(map, [], mcOptions);

    for (i=0; i<address.length; i++) { 
        geocodeAddress(address[i],i);
    }

}       
</script> 

编辑：回应评论

另外，您可以通过对每个重合标记的位置应用较小的乘数（例如，介于.999999和1.000001之间的随机数）来微调重合标记。这是一个例子。这使用的是与第一个示例相同的数据，除了标记1和2彼此重叠并共享一个信息窗口外，标记2与标记1偏移。请注意，地理编码结果将是精度稍差。相关代码如下：

//min and max limits for multiplier, for random numbers
//keep the range pretty small, so markers are kept close by
var min = .999999;
var max = 1.000001;

    function createMarker(latlng,text) {

        ///get array of markers currently in cluster
        var allMarkers = mc.getMarkers();

        //final position for marker, could be updated if another marker already exists in same position
        var finalLatLng = latlng;

        //check to see if any of the existing markers match the latlng of the new marker
        if (allMarkers.length != 0) {
            for (i=0; i < allMarkers.length; i++) {
                var existingMarker = allMarkers[i];
                var pos = existingMarker.getPosition();

                //if a marker already exists in the same position as this marker
                if (latlng.equals(pos)) {

                    //update the position of the coincident marker by applying a small multipler to its coordinates
                    var newLat = latlng.lat() * (Math.random() * (max - min) + min);
                    var newLng = latlng.lng() * (Math.random() * (max - min) + min);

                    finalLatLng = new google.maps.LatLng(newLat,newLng);

                }                   
            }
        }

        var marker = new google.maps.Marker({
            position: finalLatLng
        });     

        google.maps.event.addListener(marker, 'click', function() {
            infowindow.close();
            infowindow.setContent(text);
            infowindow.open(map,marker);
        });

        return marker;
    }

对于销售区域应用程序，在完全相同的经/纬度时，我遇到了几个标记存在相同的问题。在我的应用程序中，这是一个常见的场景，其中有多个客户位于同一地址，例如，同一摩天大楼中的客户，因此位于同一物理街道地址。

我找到了一个替代答案，对于重叠的标记，也许可以提供更好的用户体验（UX）。感谢George MacKerron创建了OverlappingMarkerSpiderfier库。此Google Maps v3的JavaScript库会覆盖重叠标记的默认点击行为。该库使您可以配置重叠的偏移半径（默认为20像素）。

来自http://jawj.github.io/OverlappingMarkerSpiderfier/demo.html的示例屏幕截图：

我建议按如下方式更改上述功能，因为所获得的结果对我而言似乎更好。

function adjustMarkerPlace(latlng) {
  ///get array of markers currently in cluster 
  //final position for marker, could be updated if another marker already exists in same position
  var finalLatLng = latlng;

  //check to see if any of the existing markers match the latlng of the new marker
  if (markers.length !== 0) {
      for (let i=0; i < markers.length; i++) {
          var existingMarker = markers[i];
          var pos = existingMarker.getPosition();

          //check if a marker already exists in the same position as this marker
          if (latlng.equals(pos)) {

              //update the position of the coincident marker by applying a small multipler to its coordinates
              var newLat = latlng.lat() + (Math.random() / 10000);
              var newLng = latlng.lng() + (Math.random() / 10000);

              finalLatLng = new google.maps.LatLng(newLat,newLng);

          }
      }
  }

  return finalLatLng;

}