将响应发送给除发件人以外的所有客户端


226

要将内容发送给所有客户,请使用:

io.sockets.emit('response', data);

要从客户那里接收,您可以使用:

socket.on('cursor', function(data) {
  ...
});

如何将两者结合起来,以便在从客户端接收服务器上的消息时,将消息发送给除发送消息的用户之外的所有用户?

socket.on('cursor', function(data) {
  io.sockets.emit('response', data);
});

我是否需要通过发送带有消息的客户端ID,然后在客户端进行检查来破解它,还是有一种更简单的方法?

Answers:


840

这是我的列表(已更新为1.0)

// sending to sender-client only
socket.emit('message', "this is a test");

// sending to all clients, include sender
io.emit('message', "this is a test");

// sending to all clients except sender
socket.broadcast.emit('message', "this is a test");

// sending to all clients in 'game' room(channel) except sender
socket.broadcast.to('game').emit('message', 'nice game');

// sending to all clients in 'game' room(channel), include sender
io.in('game').emit('message', 'cool game');

// sending to sender client, only if they are in 'game' room(channel)
socket.to('game').emit('message', 'enjoy the game');

// sending to all clients in namespace 'myNamespace', include sender
io.of('myNamespace').emit('message', 'gg');

// sending to individual socketid
socket.broadcast.to(socketid).emit('message', 'for your eyes only');

// list socketid
for (var socketid in io.sockets.sockets) {}
 OR
Object.keys(io.sockets.sockets).forEach((socketid) => {});

14
你想贡献给这个常见问题?还是我可以为您做?(我将在此处提供反向链接)
Kos 2012年

1
我没有' iohere.only'– socket
chovy

2
作为补充// sending to all clients except sender,用途是// sending a response to sender client only 什么?
Basj 2014年

4
您可以根据socket#in补充一下,socket.to('others').emit('an event', { some: 'data' });也可以在一个房间播放
gongzhitaao

119
这比socket.io文档中的所有内容
乔纳森)合

43

来自@LearnRPG答案,但带有1.0:

 // send to current request socket client
 socket.emit('message', "this is a test");

 // sending to all clients, include sender
 io.sockets.emit('message', "this is a test"); //still works
 //or
 io.emit('message', 'this is a test');

 // sending to all clients except sender
 socket.broadcast.emit('message', "this is a test");

 // sending to all clients in 'game' room(channel) except sender
 socket.broadcast.to('game').emit('message', 'nice game');

 // sending to all clients in 'game' room(channel), include sender
 // docs says "simply use to or in when broadcasting or emitting"
 io.in('game').emit('message', 'cool game');

 // sending to individual socketid, socketid is like a room
 socket.broadcast.to(socketid).emit('message', 'for your eyes only');

要回答@Crashalot的评论,socketid来自:

var io = require('socket.io')(server);
io.on('connection', function(socket) { console.log(socket.id); })

3
太棒了!如何获得socketid发送到单个套接字的信息?
Crashalot

2
用您的问题的答案进行编辑。基本上,它socket.id来自您的套接字对象。
soyuka

发送给个人,您可以使用socket.emit发回给谁,也可以将连接的客户分组并进行@Crashalot
ujwal dhakal 2015年

12

关于从0.9.x更改为1.x的内容,这是一个更完整的答案。

 // send to current request socket client
 socket.emit('message', "this is a test");// Hasn't changed

 // sending to all clients, include sender
 io.sockets.emit('message', "this is a test"); // Old way, still compatible
 io.emit('message', 'this is a test');// New way, works only in 1.x

 // sending to all clients except sender
 socket.broadcast.emit('message', "this is a test");// Hasn't changed

 // sending to all clients in 'game' room(channel) except sender
 socket.broadcast.to('game').emit('message', 'nice game');// Hasn't changed

 // sending to all clients in 'game' room(channel), include sender
 io.sockets.in('game').emit('message', 'cool game');// Old way, DOES NOT WORK ANYMORE
 io.in('game').emit('message', 'cool game');// New way
 io.to('game').emit('message', 'cool game');// New way, "in" or "to" are the exact same: "And then simply use to or in (they are the same) when broadcasting or emitting:" from http://socket.io/docs/rooms-and-namespaces/

 // sending to individual socketid, socketid is like a room
 io.sockets.socket(socketid).emit('message', 'for your eyes only');// Old way, DOES NOT WORK ANYMORE
 socket.broadcast.to(socketid).emit('message', 'for your eyes only');// New way

我想编辑@soyuka的帖子,但我的编辑被同行评审拒绝。



6

散发备忘单

io.on('connect', onConnect);

function onConnect(socket){

  // sending to the client
  socket.emit('hello', 'can you hear me?', 1, 2, 'abc');

  // sending to all clients except sender
  socket.broadcast.emit('broadcast', 'hello friends!');

  // sending to all clients in 'game' room except sender
  socket.to('game').emit('nice game', "let's play a game");

  // sending to all clients in 'game1' and/or in 'game2' room, except sender
  socket.to('game1').to('game2').emit('nice game', "let's play a game (too)");

  // sending to all clients in 'game' room, including sender
  io.in('game').emit('big-announcement', 'the game will start soon');

  // sending to all clients in namespace 'myNamespace', including sender
  io.of('myNamespace').emit('bigger-announcement', 'the tournament will start soon');

  // sending to individual socketid (private message)
  socket.to(<socketid>).emit('hey', 'I just met you');

  // sending with acknowledgement
  socket.emit('question', 'do you think so?', function (answer) {});

  // sending without compression
  socket.compress(false).emit('uncompressed', "that's rough");

  // sending a message that might be dropped if the client is not ready to receive messages
  socket.volatile.emit('maybe', 'do you really need it?');

  // sending to all clients on this node (when using multiple nodes)
  io.local.emit('hi', 'my lovely babies');

};

4

对于房间内的名称空间,循环搜索房间中的客户列表(类似于Nav的答案)是我发现可以使用的仅有的两种方法之一。另一种是使用排除。例如

socket.on('message',function(data) {
    io.of( 'namespace' ).in( data.roomID ).except( socket.id ).emit('message',data);
}

7
除了已从1.x中删除:/
coulix 2014年

1

其他情况

io.of('/chat').on('connection', function (socket) {
    //sending to all clients in 'room' and you
    io.of('/chat').in('room').emit('message', "data");
};

1

更新了列表以获取更多文档。

socket.emit('message', "this is a test"); //sending to sender-client only
socket.broadcast.emit('message', "this is a test"); //sending to all clients except sender
socket.broadcast.to('game').emit('message', 'nice game'); //sending to all clients in 'game' room(channel) except sender
socket.to('game').emit('message', 'enjoy the game'); //sending to sender client, only if they are in 'game' room(channel)
socket.broadcast.to(socketid).emit('message', 'for your eyes only'); //sending to individual socketid
io.emit('message', "this is a test"); //sending to all clients, include sender
io.in('game').emit('message', 'cool game'); //sending to all clients in 'game' room(channel), include sender
io.of('myNamespace').emit('message', 'gg'); //sending to all clients in namespace 'myNamespace', include sender
socket.emit(); //send to all connected clients
socket.broadcast.emit(); //send to all connected clients except the one that sent the message
socket.on(); //event listener, can be called on client to execute on server
io.sockets.socket(); //for emiting to specific clients
io.sockets.emit(); //send to all connected clients (same as socket.emit)
io.sockets.on() ; //initial connection from a client.

希望这可以帮助。


“ io.sockets.emit”与“ io.emit”相同,而不是“ socket.emit”
Doctor.Who。

'socket.to('game')。emit'等于'socket.broadcast.to('game')。emit',因此以上注释是错误的
Doctor.Who。

0

使用此编码

io.sockets.on('connection', function (socket) {

    socket.on('mousemove', function (data) {

        socket.broadcast.emit('moving', data);
    });

该socket.broadcast.emit()将在函数中发出所有内容,但发出该消息的服务器除外


1
io如果在花药文件中定义了回调,您将如何进入此状态
chovy 2013年

我的应用有多个文件,可以与PrePros或Koala结合使用,而不必要求它们,它使我可以共享所有变量
Steel Brain

1
或者具有io全球
Vadorequest

0

我正在使用名称空间和房间-我发现

socket.broadcast.to('room1').emit('event', 'hi');

在哪里工作

namespace.broadcast.to('room1').emit('event', 'hi');

没有

(其他人应该面对这个问题)

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