如何在字符串中找到给定的文本?之后,我想在此与其他之间创建一个新字符串。例如,如果字符串是:
This is an example string and my data is here
我想创建一个字符串,其中“ my”和“ is”之间应该是什么?这是很伪的,但希望它是有道理的。
如何在字符串中找到给定的文本?之后,我想在此与其他之间创建一个新字符串。例如,如果字符串是:
This is an example string and my data is here
我想创建一个字符串,其中“ my”和“ is”之间应该是什么?这是很伪的,但希望它是有道理的。
string
或String
的.Contains()
唯一.Concat...
选项,请保存,关闭,重新启动并为自己节省一些痛苦。
Answers:
使用此方法:
public static string getBetween(string strSource, string strStart, string strEnd)
{
if (strSource.Contains(strStart) && strSource.Contains(strEnd))
{
int Start, End;
Start = strSource.IndexOf(strStart, 0) + strStart.Length;
End = strSource.IndexOf(strEnd, Start);
return strSource.Substring(Start, End - Start);
}
return "";
}
如何使用它:
string source = "This is an example string and my data is here";
string data = getBetween(source, "my", "is");
strSource.IndexOf(strStart, 0)
为strSource.IndexOf(strStart)
。您不必声明int start, end
,只需编写即可int start = strSource.IndexOf....
这是最简单的方法:
if(str.Contains("hello"))
您可以使用正则表达式:
var regex = new Regex(".*my (.*) is.*");
if (regex.IsMatch("This is an example string and my data is here"))
{
var myCapturedText = regex.Match("This is an example string and my data is here").Groups[1].Value;
Console.WriteLine("This is my captured text: {0}", myCapturedText);
}
string string1 = "This is an example string and my data is here";
string toFind1 = "my";
string toFind2 = "is";
int start = string1.IndexOf(toFind1) + toFind1.Length;
int end = string1.IndexOf(toFind2, start); //Start after the index of 'my' since 'is' appears twice
string string2 = string1.Substring(start, end - start);
这是我使用Oscar Jara函数作为模型的函数。
public static string getBetween(string strSource, string strStart, string strEnd) {
const int kNotFound = -1;
var startIdx = strSource.IndexOf(strStart);
if (startIdx != kNotFound) {
startIdx += strStart.Length;
var endIdx = strSource.IndexOf(strEnd, startIdx);
if (endIdx > startIdx) {
return strSource.Substring(startIdx, endIdx - startIdx);
}
}
return String.Empty;
}
此版本最多可进行两次文本搜索。当搜索仅在开始字符串之前出现的结束字符串时,它避免了Oscar版本引发的异常getBetween(text, "my", "and");
。
用法是相同的:
string text = "This is an example string and my data is here";
string data = getBetween(text, "my", "is");
您可以像这样紧凑地进行操作:
string abc = abc.Replace(abc.Substring(abc.IndexOf("me"), (abc.IndexOf("is", abc.IndexOf("me")) + 1) - abc.IndexOf("size")), string.Empty);
除@Prashant的答案外,以上答案均已错误回答。答案的“替换”功能在哪里?OP询问:“此后,我想在该字符串与其他字符串之间创建一个新字符串”。
基于@Oscar的出色响应,我将其功能扩展为一个"Search And Replace"
功能。
我认为@Prashant的答案应该是OP接受的答案,因为它可以代替。
无论如何,我将其称为- ReplaceBetween()
。
public static string ReplaceBetween(string strSource, string strStart, string strEnd, string strReplace)
{
int Start, End;
if (strSource.Contains(strStart) && strSource.Contains(strEnd))
{
Start = strSource.IndexOf(strStart, 0) + strStart.Length;
End = strSource.IndexOf(strEnd, Start);
string strToReplace = strSource.Substring(Start, End - Start);
string newString = strSource.Concat(Start,strReplace,End - Start);
return newString;
}
else
{
return string.Empty;
}
}
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
using System.Threading;
using System.Diagnostics;
namespace oops3
{
public class Demo
{
static void Main(string[] args)
{
Console.WriteLine("Enter the string");
string x = Console.ReadLine();
Console.WriteLine("enter the string to be searched");
string SearchText = Console.ReadLine();
string[] myarr = new string[30];
myarr = x.Split(' ');
int i = 0;
foreach(string s in myarr)
{
i = i + 1;
if (s==SearchText)
{
Console.WriteLine("The string found at position:" + i);
}
}
Console.ReadLine();
}
}
}
static void Main(string[] args)
{
int f = 0;
Console.WriteLine("enter the string");
string s = Console.ReadLine();
Console.WriteLine("enter the word to be searched");
string a = Console.ReadLine();
int l = s.Length;
int c = a.Length;
for (int i = 0; i < l; i++)
{
if (s[i] == a[0])
{
for (int K = i + 1, j = 1; j < c; j++, K++)
{
if (s[K] == a[j])
{
f++;
}
}
}
}
if (f == c - 1)
{
Console.WriteLine("matching");
}
else
{
Console.WriteLine("not found");
}
Console.ReadLine();
}
这是替换字符串中的一部分文本的正确方法(基于Oscar Jara的getBetween方法):
public static string ReplaceTextBetween(string strSource, string strStart, string strEnd, string strReplace)
{
int Start, End, strSourceEnd;
if (strSource.Contains(strStart) && strSource.Contains(strEnd))
{
Start = strSource.IndexOf(strStart, 0) + strStart.Length;
End = strSource.IndexOf(strEnd, Start);
strSourceEnd = strSource.Length - 1;
string strToReplace = strSource.Substring(Start, End - Start);
string newString = string.Concat(strSource.Substring(0, Start), strReplace, strSource.Substring(Start + strToReplace.Length, strSourceEnd - Start));
return newString;
}
else
{
return string.Empty;
}
}
该string.Concat
串接3个字符串:
strSource.Substring(0, Start)
strReplace
strSource.Substring(Start + strToReplace.Length, strSourceEnd - Start)
如果您知道始终需要“ my”和“ is”之间的字符串,则可以始终执行以下操作:
string message = "This is an example string and my data is here";
//Get the string position of the first word and add two (for it's length)
int pos1 = message.IndexOf("my") + 2;
//Get the string position of the next word, starting index being after the first position
int pos2 = message.IndexOf("is", pos1);
//use substring to obtain the information in between and store in a new string
string data = message.Substring(pos1, pos2 - pos1).Trim();
只需添加以下代码:
如果(string.Contains(“ search_text”)){MessageBox.Show(“ Message。”); }
IndexOf
和Substring
。