接受的答案通常涵盖了一切,但我想补充一点,只是柜面你打算工作,像更新的方式模型,您检索一条记录(其id
不知道),然后find_by
是的方式,因为它检索记录并且不将其放入数组中
irb(main):037:0> @kit = Kit.find_by(number: "3456")
Kit Load (0.9ms) SELECT "kits".* FROM "kits" WHERE "kits"."number" =
'3456' LIMIT 1
=> #<Kit id: 1, number: "3456", created_at: "2015-05-12 06:10:56",
updated_at: "2015-05-12 06:10:56", job_id: nil>
irb(main):038:0> @kit.update(job_id: 2)
(0.2ms) BEGIN Kit Exists (0.4ms) SELECT 1 AS one FROM "kits" WHERE
("kits"."number" = '3456' AND "kits"."id" != 1) LIMIT 1 SQL (0.5ms)
UPDATE "kits" SET "job_id" = $1, "updated_at" = $2 WHERE "kits"."id" =
1 [["job_id", 2], ["updated_at", Tue, 12 May 2015 07:16:58 UTC +00:00]]
(0.6ms) COMMIT => true
但是如果使用,where
则无法直接更新
irb(main):039:0> @kit = Kit.where(number: "3456")
Kit Load (1.2ms) SELECT "kits".* FROM "kits" WHERE "kits"."number" =
'3456' => #<ActiveRecord::Relation [#<Kit id: 1, number: "3456",
created_at: "2015-05-12 06:10:56", updated_at: "2015-05-12 07:16:58",
job_id: 2>]>
irb(main):040:0> @kit.update(job_id: 3)
ArgumentError: wrong number of arguments (1 for 2)
在这种情况下,您必须像这样指定它
irb(main):043:0> @kit[0].update(job_id: 3)
(0.2ms) BEGIN Kit Exists (0.6ms) SELECT 1 AS one FROM "kits" WHERE
("kits"."number" = '3456' AND "kits"."id" != 1) LIMIT 1 SQL (0.6ms)
UPDATE "kits" SET "job_id" = $1, "updated_at" = $2 WHERE "kits"."id" = 1
[["job_id", 3], ["updated_at", Tue, 12 May 2015 07:28:04 UTC +00:00]]
(0.5ms) COMMIT => true
find_by
未弃用,但语法有所变化。从find_by_name("Bob")
到find_by(:name, "Bob")
。