我在Web应用程序中使用Spring Security,现在我想获得一个已登录程序的所有用户的列表。
我如何访问该列表?他们不是已经在Spring框架中保留了什么吗?像SecurityContextHolder或SecurityContextRepository吗?
Answers:
要访问所有已登录用户的列表,需要将SessionRegistry实例注入到bean中。
@Autowired
@Qualifier("sessionRegistry")
private SessionRegistry sessionRegistry;
然后使用注入的SessionRegistry您可以访问所有主体的列表:
List<Object> principals = sessionRegistry.getAllPrincipals();
List<String> usersNamesList = new ArrayList<String>();
for (Object principal: principals) {
if (principal instanceof User) {
usersNamesList.add(((User) principal).getUsername());
}
}
但是在注入会话注册表之前,您需要在spring-security.xml中定义会话管理部分(请参阅Spring Security参考文档中的“会话管理”部分),并在并发控制部分中,应为会话注册表对象设置别名(session-registry-别名),您将通过它注入。
<security:http access-denied-page="/error403.jsp" use-expressions="true" auto-config="false">
<security:session-management session-fixation-protection="migrateSession" session-authentication-error-url="/login.jsp?authFailed=true">
<security:concurrency-control max-sessions="1" error-if-maximum-exceeded="true" expired-url="/login.html" session-registry-alias="sessionRegistry"/>
</security:session-management>
...
</security:http>
在JavaConfig中,它看起来像这样:
@Configuration
@EnableWebSecurity
public class SecurityConfig extends WebSecurityConfigurerAdapter {
@Override
protected void configure(final HttpSecurity http) throws Exception {
// ...
http.sessionManagement().maximumSessions(1).sessionRegistry(sessionRegistry());
}
@Bean
public SessionRegistry sessionRegistry() {
return new SessionRegistryImpl();
}
@Bean
public ServletListenerRegistrationBean<HttpSessionEventPublisher> httpSessionEventPublisher() {
return new ServletListenerRegistrationBean<HttpSessionEventPublisher>(new HttpSessionEventPublisher());
}
}
调用代码如下所示:
public class UserController {
@Autowired
private SessionRegistry sessionRegistry;
public void listLoggedInUsers() {
final List<Object> allPrincipals = sessionRegistry.getAllPrincipals();
for(final Object principal : allPrincipals) {
if(principal instanceof SecurityUser) {
final SecurityUser user = (SecurityUser) principal;
// Do something with user
System.out.println(user);
}
}
}
}
请注意,这SecurityUser
是我自己实现的类UserDetails
。
如果我错了,请纠正我。
我认为@Adam的答案不完整。我注意到列表中已经过期的会话再次出现。
public class UserController {
@Autowired
private SessionRegistry sessionRegistry;
public void listLoggedInUsers() {
final List<Object> allPrincipals = sessionRegistry.getAllPrincipals();
for (final Object principal : allPrincipals) {
if (principal instanceof SecurityUser) {
final SecurityUser user = (SecurityUser) principal;
List<SessionInformation> activeUserSessions =
sessionRegistry.getAllSessions(principal,
/* includeExpiredSessions */ false); // Should not return null;
if (!activeUserSessions.isEmpty()) {
// Do something with user
System.out.println(user);
}
}
}
}
}
希望能帮助到你。
如果我也错了,请纠正我。
我认为@Adam和@elysch的答案不完整。我注意到需要添加侦听器:
servletContext.addListener(HttpSessionEventPublisher.class);
至
public class AppInitializer implements WebApplicationInitializer {
@Override
public void onStartup(ServletContext servletContext) {
...
servletContext.addListener(HttpSessionEventPublisher.class);
}
使用安全配置:
@Configuration
@EnableWebSecurity
public class SecurityConfig extends WebSecurityConfigurerAdapter {
@Override
protected void configure(final HttpSecurity http) throws Exception {
// ...
http.sessionManagement().maximumSessions(1).sessionRegistry(sessionRegistry());
}
@Bean
public SessionRegistry sessionRegistry() {
return new SessionRegistryImpl();
}
@Bean
public HttpSessionEventPublisher httpSessionEventPublisher() {
return new HttpSessionEventPublisher();
}
}
然后,您将获得当前的在线用户!
发现此注释非常重要且相关:
“ [21]通过在身份验证后执行重定向的机制(例如,表单登录)进行的身份验证将不会被SessionManagementFilter检测到,因为在身份验证请求期间不会调用该过滤器。会话管理功能必须在这些请求中分别处理案件。”
https://docs.spring.io/spring-security/site/docs/3.1.x/reference/session-mgmt.html#d0e4399
同样,很显然,很多人在让sessionRegistry.getAllPrincipals()返回不同于空数组的内容时遇到麻烦。就我而言,我通过将sessionAuthenticationStrategy添加到我的自定义authenticationFilter来解决此问题:
@Bean
public CustomUsernamePasswordAuthenticationFilter authenticationFilter() throws Exception {
...
authenticationFilter.setSessionAuthenticationStrategy(sessionAuthenticationStrategy());
}
@Bean
public SessionRegistry sessionRegistry() {
return new SessionRegistryImpl();
}
//cf. /programming/32463022/sessionregistry-is-empty-when-i-use-concurrentsessioncontrolauthenticationstrate
public SessionAuthenticationStrategy sessionAuthenticationStrategy() {
List<SessionAuthenticationStrategy> stratList = new ArrayList<>();
SessionFixationProtectionStrategy concStrat = new SessionFixationProtectionStrategy();
stratList.add(concStrat);
RegisterSessionAuthenticationStrategy regStrat = new RegisterSessionAuthenticationStrategy(sessionRegistry());
stratList.add(regStrat);
CompositeSessionAuthenticationStrategy compStrat = new CompositeSessionAuthenticationStrategy(stratList);
return compStrat;
}
与@rolyanos解决方案类似,对我来说,我的作品始终有效:
-对于控制器
@RequestMapping(value = "/admin")
public String admin(Map<String, Object> model) {
if(sessionRegistry.getAllPrincipals().size() != 0) {
logger.info("ACTIVE USER: " + sessionRegistry.getAllPrincipals().size());
model.put("activeuser", sessionRegistry.getAllPrincipals().size());
}
else
logger.warn("EMPTY" );
logger.debug(log_msg_a + " access ADMIN page. Access granted." + ANSI_RESET);
return "admin";
}
-对于前端
<tr th:each="activeuser, iterStat: ${activeuser}">
<th><b>Active users: </b></th> <td align="center" th:text="${activeuser}"></td>
</tr>
-用于春季发泄
@Bean
public SessionRegistry sessionRegistry() {
return new SessionRegistryImpl();
}
@Bean
public ServletListenerRegistrationBean<HttpSessionEventPublisher> httpSessionEventPublisher() {
return new ServletListenerRegistrationBean<HttpSessionEventPublisher>(new HttpSessionEventPublisher());
}
@Override
protected void configure(HttpSecurity http) throws Exception {
http.logout()
.logoutSuccessUrl("/home")
.logoutUrl("/logout")
.invalidateHttpSession(true)
.deleteCookies("JSESSIONID");
http.authorizeRequests()
.antMatchers("/", "/home")
.permitAll()
.antMatchers("/admin")
.hasRole("ADMIN")
.anyRequest()
.authenticated()
.and()
.formLogin()
.loginPage("/home")
.defaultSuccessUrl("/main")
.permitAll()
.and()
.logout()
.permitAll();
http.sessionManagement().maximumSessions(1).sessionRegistry(sessionRegistry());
http.authorizeRequests().antMatchers("/webjars/**").permitAll();
http.exceptionHandling().accessDeniedPage("/403");
}