SQL查询中分组的COUNT的总和

我有一个包含2个字段的表格：

身份证名
--------
1个Alpha
2 Beta
3 Beta
4 Beta
5查理
6查理

我想按名称将其分组，并带有“计数”和一行“ SUM”

名字计数
------- -----
阿尔法1
Beta 3
查理2
总和6

如何编写查询以在表下方添加SUM行？

SELECT name, COUNT(name) AS count
FROM table
GROUP BY name

UNION ALL

SELECT 'SUM' name, COUNT(name)
FROM table

输出：

name                                               count
-------------------------------------------------- -----------
alpha                                              1
beta                                               3
Charlie                                            2
SUM                                                6

SELECT name, COUNT(name) AS count, SUM(COUNT(name)) OVER() AS total_count
FROM Table GROUP BY name

没有指定您正在使用哪个rdbms

看看这个演示

SQL小提琴演示

SELECT Name, COUNT(1) as Cnt
FROM Table1
GROUP BY Name
UNION ALL
SELECT 'SUM' Name, COUNT(1)
FROM Table1

就是说，我建议您将总数添加到您的表示层而不是数据库中。

这是使用ROLLUP汇总数据的SQL SERVER版本的更多内容

SQL小提琴演示

SELECT CASE WHEN (GROUPING(NAME) = 1) THEN 'SUM'
            ELSE ISNULL(NAME, 'UNKNOWN')
       END Name, 
      COUNT(1) as Cnt
FROM Table1
GROUP BY NAME
WITH ROLLUP

尝试这个：

SELECT  ISNULL(Name,'SUM'), count(*) as Count
FROM table_name
Group By Name
WITH ROLLUP

请按以下方式运行：

Select sum(count) 
  from (select Name, 
               count(Name) as Count 
          from YourTable
      group by Name);  -- 6

您可以使用联合来联接行。

select Name, count(*) as Count from yourTable group by Name
union all
select "SUM" as Name, count(*) as Count from yourTable

对于Sql Server，您可以尝试这一方法。

SELECT ISNULL([NAME],'SUM'),Count([NAME]) AS COUNT
FROM TABLENAME
GROUP BY [NAME] WITH CUBE

这里的所有解决方案都很棒，但不一定可以针对旧的mysql服务器实现（至少就我而言）。因此您可以使用子查询（我认为它不那么复杂）。

 select sum(t1.cnt) from 
        (SELECT column, COUNT(column) as cnt
            FROM
            table 
            GROUP BY 
            column
            HAVING 
            COUNT(column) > 1) as t1 ;

我解释这个问题的方式是需要每组答案的小计值。使用以下方法，小计非常容易PARTITION：

SUM(COUNT(0)) OVER (PARTITION BY [Grouping]) AS [MY_TOTAL]

这是我完整的SQL调用的样子：

SELECT MAX(GroupName) [name], MAX(AUX2)[type],  
COUNT(0) [count], SUM(COUNT(0)) OVER(PARTITION BY GroupId) AS [total]
    FROM [MyView]
  WHERE Active=1 AND Type='APP' AND Completed=1
    AND [Date] BETWEEN '01/01/2014' AND GETDATE()
    AND Id = '5b9xxxxx-xxxx-xxxx-xxxx-xxxxxxxxxxxx' AND GroupId IS NOT NULL
  GROUP BY AUX2, GroupId

从中返回的数据如下所示：

name    type    count   total
Training Group 2    Cancelation 1   52
Training Group 2    Completed   41  52
Training Group 2    No Show 6   52
Training Group 2    Rescheduled 4   52
Training Group 3    NULL        4   10535
Training Group 3    Cancelation 857 10535
Training Group 3    Completed   7923    10535
Training Group 3    No Show 292 10535
Training Group 3    Rescheduled 1459    10535
Training Group 4    Cancelation 2   27
Training Group 4    Completed   24  27
Training Group 4    Rescheduled 1   27

  with cttmp
  as
  (
  select Col_Name, count(*) as ctn from tab_name group by Col_Name having count(Col_Name)>1
  )
  select sum(ctn) from c

您可以使用ROLLUP

select nvl(name, 'SUM'), count(*)
from table
group by rollup(name)

您可以按名称尝试分组，并计算该组中的ID。

SELECT name, count(id) as COUNT FROM table group by name

用作

select Name, count(Name) as Count from YourTable
group by Name
union 
Select 'SUM' , COUNT(Name) from YourTable

我正在使用SQL Server，以下应该适用于您：

通过名称联合从表1组中选择cast（名称为varchar（16））作为'名称'，将count（name）作为'Count'通过名称联合全部选择Table1中的'Sum：'，count（name）

我having count(*) > 1也需要。因此，我在参考了上述一些查询后编写了自己的查询

句法：

select sum(count) from (select count(`table_name`.`id`) as `count` from `table_name` where {some condition} group by {some_column} having count(`table_name`.`id`) > 1) as `tmp`;

例：

select sum(count) from (select count(`table_name`.`id`) as `count` from `table_name` where `table_name`.`name` IS NOT NULL and `table_name`.`name` != '' group by `table_name`.`name` having count(`table_name`.`id`) > 1) as `tmp`;

查询后，运行下面的命令以获取总行数

select @@ROWCOUNT

从（Tab_name组中选择count（Col_name）作为具有count（*）> 1的Col_name从Tab_name组中选择s）