如何删除字符串中的前导和尾随零？蟒蛇

我有几个像这样的字母数字字符串

listOfNum = ['000231512-n','1209123100000-n00000','alphanumeric0000', '000alphanumeric']

除去尾随零的理想输出为：

listOfNum = ['000231512-n','1209123100000-n','alphanumeric', '000alphanumeric']

前导尾随零的期望输出为：

listOfNum = ['231512-n','1209123100000-n00000','alphanumeric0000', 'alphanumeric']

除去前导零和尾随零的期望输出为：

listOfNum = ['231512-n','1209123100000-n', 'alphanumeric', 'alphanumeric']

目前，我已经按照以下方式进行操作，如果有的话，请提出一种更好的方法：

listOfNum = ['000231512-n','1209123100000-n00000','alphanumeric0000', \
'000alphanumeric']
trailingremoved = []
leadingremoved = []
bothremoved = []

# Remove trailing
for i in listOfNum:
  while i[-1] == "0":
    i = i[:-1]
  trailingremoved.append(i)

# Remove leading
for i in listOfNum:
  while i[0] == "0":
    i = i[1:]
  leadingremoved.append(i)

# Remove both
for i in listOfNum:
  while i[0] == "0":
    i = i[1:]
  while i[-1] == "0":
    i = i[:-1]
  bothremoved.append(i)

那基本的

your_string.strip("0")

删除尾随和前导零？如果您只想删除尾随零，请.rstrip改用（.lstrip仅用于前导零）。

[ 文档中的更多信息。]

您可以使用一些列表推导来获得所需的序列，如下所示：

trailing_removed = [s.rstrip("0") for s in listOfNum]
leading_removed = [s.lstrip("0") for s in listOfNum]
both_removed = [s.strip("0") for s in listOfNum]

删除前导+尾随的“ 0”：

list = [i.strip('0') for i in listOfNum ]

删除前导“ 0”：

list = [ i.lstrip('0') for i in listOfNum ]

删除尾随的“ 0”：

list = [ i.rstrip('0') for i in listOfNum ]

您可以简单地通过bool做到这一点：

if int(number) == float(number):

   number = int(number)

else:

   number = float(number)

您是否尝试了strip（）：

listOfNum = ['231512-n','1209123100000-n00000','alphanumeric0000', 'alphanumeric']
print [item.strip('0') for item in listOfNum]

>>> ['231512-n', '1209123100000-n', 'alphanumeric', 'alphanumeric']

str.strip是解决这种情况的最佳方法，但more_itertools.strip还是一种通用解决方案，可从迭代中剥离前导元素和尾随元素：

码

import more_itertools as mit


iterables = ["231512-n\n","  12091231000-n00000","alphanum0000", "00alphanum"]
pred = lambda x: x in {"0", "\n", " "}
list("".join(mit.strip(i, pred)) for i in iterables)
# ['231512-n', '12091231000-n', 'alphanum', 'alphanum']

细节

注意，这里我们"0"将满足谓词的其他元素中的前导和尾随s 剥离。此工具不仅限于字符串。

另请参阅docs，以获取更多的示例

• more_itertools.strip：剥去两端
• more_itertools.lstrip：去除左端
• more_itertools.rstrip：剥去右端

more_itertools是可通过安装的第三方库> pip install more_itertools。

假设列表中还有其他数据类型（不仅是字符串），请尝试此操作。这将从字符串中删除尾随和前导零，并使其他数据类型保持不变。这也处理特殊情况s ='0'

例如

a = ['001', '200', 'akdl00', 200, 100, '0']

b = [(lambda x: x.strip('0') if isinstance(x,str) and len(x) != 1 else x)(x) for x in a]

b
>>>['1', '2', 'akdl', 200, 100, '0']