如何重命名JSON密钥

我有一个具有以下内容的JSON对象：

[
  {
    "_id":"5078c3a803ff4197dc81fbfb",
    "email":"user1@gmail.com",
    "image":"some_image_url",
    "name":"Name 1"
  },
  {
    "_id":"5078c3a803ff4197dc81fbfc",
    "email":"user2@gmail.com",
    "image":"some_image_url",
    "name":"Name 2"
  }
]

我想将“ _id”键更改为“ id”，这样它将变成

[
  {
    "id":"5078c3a803ff4197dc81fbfb",
    "email":"user1@gmail.com",
    "image":"some_image_url",
    "name":"Name 1"
  },
  {
    "id":"5078c3a803ff4197dc81fbfc",
    "email":"user2@gmail.com",
    "image":"some_image_url",
    "name":"Name 2"
  }
]

如何使用Javascript，jQuery或Ruby，Rails做到这一点？

谢谢。

1. 解析JSON

const arr = JSON.parse(json);

2. 对于JSON中的每个对象，重命名键：

obj.id = obj._id;
delete obj._id;

3. 字符串化结果

全部一起：

function renameKey ( obj, oldKey, newKey ) {
  obj[newKey] = obj[oldKey];
  delete obj[oldKey];
}

const json = `
  [
    {
      "_id":"5078c3a803ff4197dc81fbfb",
      "email":"user1@gmail.com",
      "image":"some_image_url",
      "name":"Name 1"
    },
    {
      "_id":"5078c3a803ff4197dc81fbfc",
      "email":"user2@gmail.com",
      "image":"some_image_url",
      "name":"Name 2"
    }
  ]
`;
   
const arr = JSON.parse(json);
arr.forEach( obj => renameKey( obj, '_id', 'id' ) );
const updatedJson = JSON.stringify( arr );

console.log( updatedJson );

在这种情况下，使用字符串替换将是最简单的。序列化JSON不能很好地工作，因为_id将成为对象的属性名称，并且更改属性名称并不是一件容易的事（至少在大多数语言中并非如此，在javascript中还不是很糟糕）。相反，只是做；

jsonString = jsonString.replace("\"_id\":", "\"id\":");

如evanmcdonnal所述，最简单的解决方案是将其作为字符串而不是JSON处理，

var json = [{"_id":"5078c3a803ff4197dc81fbfb","email":"user1@gmail.com","image":"some_image_url","name":"Name 1"},{"_id":"5078c3a803ff4197dc81fbfc","email":"user2@gmail.com","image":"some_image_url","name":"Name 2"}];
    
json = JSON.parse(JSON.stringify(json).split('"_id":').join('"id":'));

document.write(JSON.stringify(json));

这会将给定的JSON数据转换为字符串，并将“ _id”替换为“ id”，然后将其转换回所需的JSON格式。但是我使用split和join代替replace，因为replace它将仅替换字符串的第一次出现。

尝试这个：

let jsonArr = [
    {
        "_id":"5078c3a803ff4197dc81fbfb",
        "email":"user1@gmail.com",
        "image":"some_image_url",
        "name":"Name 1"
    },
    {
        "_id":"5078c3a803ff4197dc81fbfc",
        "email":"user2@gmail.com",
        "image":"some_image_url",
        "name":"Name 2"
    }
]

let idModified = jsonArr.map(
    obj => {
        return {
            "id" : obj._id,
            "email":obj.email,
            "image":obj.image,
            "name":obj.name
        }
    }
);
console.log(idModified);

如果要重命名所有出现的某个键，可以使用带有g选项的正则表达式。例如：

var json = [{"_id":"1","email":"user1@gmail.com","image":"some_image_url","name":"Name 1"},{"_id":"2","email":"user2@gmail.com","image":"some_image_url","name":"Name 2"}];

str = JSON.stringify(json);

现在我们在str中使用字符串格式的json。

使用带有g选项的正则表达式将所有出现的“ _id”替换为“ id” ：

str = str.replace(/\"_id\":/g, "\"id\":");

并返回json格式：

json = JSON.parse(str);

现在我们有了带有所需键名的json。

使用typeScript是可能的

function renameJson(json,oldkey,newkey) {    
 return Object.keys(json).reduce((s,item) => 
      item == oldkey ? ({...s,[newkey]:json[oldkey]}) : ({...s,[item]:json[item]}),{})   
}

示例：https：//codepen.io/lelogualda/pen/BeNwWJ

通过使用地图功能，您可以做到这一点。请参考下面的代码。

var userDetails = [{
  "_id":"5078c3a803ff4197dc81fbfb",
  "email":"user1@gmail.com",
  "image":"some_image_url",
  "name":"Name 1"
},{
  "_id":"5078c3a803ff4197dc81fbfc",
  "email":"user2@gmail.com",
  "image":"some_image_url",
  "name":"Name 2"
}];

var formattedUserDetails = userDetails.map(({ _id:id, email, image, name }) => ({
  id,
  email,
  image,
  name
}));
console.log(formattedUserDetails);

JSON.parse有两个参数。第二个参数reviver是一个转换函数，可以将其格式化为所需的输出格式。请参阅此处的ECMA规范。

在齐磊功能中：

• 如果返回undefined，则原始属性将被删除。
• this 是包含正在作为此函数处理的属性，属性名称为字符串，属性值为该函数的参数的对象。

const json = '[{"_id":"5078c3a803ff4197dc81fbfb","email":"user1@gmail.com","image":"some_image_url","name":"Name 1"},{"_id":"5078c3a803ff4197dc81fbfc","email":"user2@gmail.com","image":"some_image_url","name":"Name 2"}]';

const obj = JSON.parse(json, function(k, v) {
    if (k === "_id") {
        this.id = v;
        return; # if return  undefined, orignal property will be removed
    }
    return v;
});

const res = JSON.stringify(obj);
console.log(res)

输出：

[{"email":"user1@gmail.com","image":"some_image_url","name":"Name 1","id":"5078c3a803ff4197dc81fbfb"},{"email":"user2@gmail.com","image":"some_image_url","name":"Name 2","id":"5078c3a803ff4197dc81fbfc"}]

如果您的对象看起来像这样：

obj = {
    "_id":"5078c3a803ff4197dc81fbfb",
    "email":"user1@gmail.com",
    "image":"some_image_url",
    "name":"Name 1"
   }

JavaScript中最简单的方法可能是：

obj.id = obj._id
del object['_id']

结果，您将获得：

obj = {
    "id":"5078c3a803ff4197dc81fbfb",
    "email":"user1@gmail.com",
    "image":"some_image_url",
    "name":"Name 1"
   }

如果有人需要动态执行此操作：

const keys = Object.keys(jsonObject);

keys.forEach((key) => {

      // CREATE A NEW KEY HERE
      var newKey = key.replace(' ', '_');

      jsonObject[newKey] = jsonObject[key];
      delete jsonObject[key];
   });

jsonObject 现在将具有新密钥。

重要：

如果replace函数未更改您的密钥，它将直接从数组中取出。您可能需要在其中添加一些if语句。

例如，如果要动态执行此操作，则有一个要用作JSON对象键的数组：

你的数组就像：

var keys = ["id", "name","Address","Phone"] // The array size should be same as JSON Object keys size

现在您有了一个JSON Array，如下所示：

var jArray = [
  {
    "_id": 1,
    "_name": "Asna",
    "Address": "NY",
    "Phone": 123
  },
  {
    "_id": 2,
    "_name": "Euphoria",
    "Address": "Monaco",
    "Phone": 124
  },
  {
    "_id": 3,
    "_name": "Ahmed",
    "Address": "Mumbai",
    "Phone": 125
  }
]

$.each(jArray ,function(pos,obj){
    var counter = 0;
    $.each(obj,function(key,value){
        jArray [pos][keys[counter]] = value;
        delete jArray [pos][key];
        counter++;
    })  
})

您生成的JSON数组将类似于：

[
  {
    "id": 1,
    "name": "Asna",
    "Address": "NY",
    "Phone": 123
  },
  {
    "id": 2,
    "name": "Euphoria",
    "Address": "Monaco",
    "Phone": 124
  },
  {
    "id": 3,
    "name": "Ahmed",
    "Address": "Mumbai",
    "Phone": 125
  }
]