使用函数获取两个日期之间的日期列表

我的问题类似于此MySQL问题，但适用于SQL Server：

是否存在将返回两个日期之间的天数列表的函数或查询？例如，假设有一个名为ExplodeDates的函数：

SELECT ExplodeDates('2010-01-01', '2010-01-13');

这将返回具有以下值的单列表：

2010-01-01
2010-01-02
2010-01-03
2010-01-04
2010-01-05
2010-01-06
2010-01-07
2010-01-08
2010-01-09
2010-01-10
2010-01-11
2010-01-12
2010-01-13

我在想日历/数字表可以在这里为我提供帮助。

更新资料

我决定看看提供的三个代码答案，执行结果（占总批处理的百分比）是：

• 罗伯·法利（Rob Farley）的答案：18％
• StingyJack的答案：41％
• KM的答案：41％

越低越好

我接受了Rob Farley的答案，因为它是最快的，即使数字表解决方案（KM和StingyJack都在他们的答案中使用）是我的最爱。Rob Farley的速度快了三分之二。

更新2

Alivia的回答更为简洁。我已更改了接受的答案。

这几行是sql server中此问题的简单答案。

WITH mycte AS
(
  SELECT CAST('2011-01-01' AS DATETIME) DateValue
  UNION ALL
  SELECT  DateValue + 1
  FROM    mycte   
  WHERE   DateValue + 1 < '2021-12-31'
)

SELECT  DateValue
FROM    mycte
OPTION (MAXRECURSION 0)

尝试这样的事情：

CREATE FUNCTION dbo.ExplodeDates(@startdate datetime, @enddate datetime)
returns table as
return (
with 
 N0 as (SELECT 1 as n UNION ALL SELECT 1)
,N1 as (SELECT 1 as n FROM N0 t1, N0 t2)
,N2 as (SELECT 1 as n FROM N1 t1, N1 t2)
,N3 as (SELECT 1 as n FROM N2 t1, N2 t2)
,N4 as (SELECT 1 as n FROM N3 t1, N3 t2)
,N5 as (SELECT 1 as n FROM N4 t1, N4 t2)
,N6 as (SELECT 1 as n FROM N5 t1, N5 t2)
,nums as (SELECT ROW_NUMBER() OVER (ORDER BY (SELECT 1)) as num FROM N6)
SELECT DATEADD(day,num-1,@startdate) as thedate
FROM nums
WHERE num <= DATEDIFF(day,@startdate,@enddate) + 1
);

然后，您使用：

SELECT *
FROM dbo.ExplodeDates('20090401','20090531') as d;

编辑（接受后）：

请注意...如果您已经有足够大的nums表，则应使用：

CREATE FUNCTION dbo.ExplodeDates(@startdate datetime, @enddate datetime)
returns table as
return (
SELECT DATEADD(day,num-1,@startdate) as thedate
FROM nums
WHERE num <= DATEDIFF(day,@startdate,@enddate) + 1
);

您可以使用以下方式创建此类表：

CREATE TABLE dbo.nums (num int PRIMARY KEY);
INSERT dbo.nums values (1);
GO
INSERT dbo.nums SELECT num + (SELECT COUNT(*) FROM nums) FROM nums
GO 20

这些行将创建一个包含1M行的数字表，并且比一张一张地插入它们要快得多。

您不应该使用涉及BEGIN和END的函数来创建ExplodeDates函数，因为Query Optimizer根本无法简化查询。

这正是您想要的，从Will的早期文章中进行了修改。不需要辅助表或循环。

WITH date_range (calc_date) AS (
    SELECT DATEADD(DAY, DATEDIFF(DAY, 0, '2010-01-13') - DATEDIFF(DAY, '2010-01-01', '2010-01-13'), 0)
        UNION ALL SELECT DATEADD(DAY, 1, calc_date)
            FROM date_range
            WHERE DATEADD(DAY, 1, calc_date) <= '2010-01-13')
SELECT calc_date
FROM date_range;

DECLARE @MinDate DATETIME = '2012-09-23 00:02:00.000',
    @MaxDate DATETIME = '2012-09-25 00:00:00.000';

SELECT  TOP (DATEDIFF(DAY, @MinDate, @MaxDate) + 1) Dates = DATEADD(DAY, ROW_NUMBER() OVER(ORDER BY a.object_id) - 1, @MinDate)
FROM sys.all_objects a CROSS JOIN sys.all_objects b;

我是一个Oracle专家，但我相信MS SQL Server支持connect by子句：

select  sysdate + level
from    dual
connect by level <= 10 ;

输出为：

SYSDATE+LEVEL
05-SEP-09
06-SEP-09
07-SEP-09
08-SEP-09
09-SEP-09
10-SEP-09
11-SEP-09
12-SEP-09
13-SEP-09
14-SEP-09

Dual只是oracle附带的“虚拟”表（它包含1行，单词“ dummy”作为单列的值）。

一些想法：

如果您需要列表日期来循环浏览它们，则可以使用“开始日期”和“天数”参数，并在创建日期和使用日期时进行一次while循环？

使用C＃CLR存储过程并用C＃编写代码

用代码在数据库外执行此操作

所有这些日期都已经在数据库中了吗？还是只想知道两个日期之间的日期？如果是第一个，则可以使用BETWEEN或<=> =查找之间的日期

例：

SELECT column_name(s)
FROM table_name
WHERE column_name
BETWEEN value1 AND value2

要么

SELECT column_name(s)
FROM table_name
WHERE column_name
value1 >= column_name
AND column_name =< value2

您所要做的就是更改下面提供的代码中的硬编码值

DECLARE @firstDate datetime
    DECLARE @secondDate datetime
    DECLARE @totalDays  INT
    SELECT @firstDate = getDate() - 30
    SELECT @secondDate = getDate()

    DECLARE @index INT
    SELECT @index = 0
    SELECT @totalDays = datediff(day, @firstDate, @secondDate)

    CREATE TABLE #temp
    (
         ID INT NOT NULL IDENTITY(1,1)
        ,CommonDate DATETIME NULL
    )

    WHILE @index < @totalDays
        BEGIN

            INSERT INTO #temp (CommonDate) VALUES  (DATEADD(Day, @index, @firstDate))   
            SELECT @index = @index + 1
        END

    SELECT CONVERT(VARCHAR(10), CommonDate, 102) as [Date Between] FROM #temp

    DROP TABLE #temp

派对晚了一点，但是我相当喜欢这个解决方案。

CREATE FUNCTION ExplodeDates(@startDate DateTime, @endDate DateTime)
RETURNS table as
return (
    SELECT  TOP (DATEDIFF(DAY, @startDate, @endDate) + 1)
            DATEADD(DAY, ROW_NUMBER() OVER(ORDER BY a.object_id) - 1, @startDate) AS DATE
    FROM    sys.all_objects a
            CROSS JOIN sys.all_objects b
            )

在使用我的函数之前，您需要设置一个“帮助器”表，每个数据库只需要执行一次此操作：

CREATE TABLE Numbers
(Number int  NOT NULL,
    CONSTRAINT PK_Numbers PRIMARY KEY CLUSTERED (Number ASC)WITH (PAD_INDEX  = OFF, STATISTICS_NORECOMPUTE  = OFF, IGNORE_DUP_KEY = OFF, ALLOW_ROW_LOCKS  = ON, ALLOW_PAGE_LOCKS  = ON) ON [PRIMARY]
) ON [PRIMARY]
DECLARE @x int
SET @x=0
WHILE @x<8000
BEGIN
    SET @x=@x+1
    INSERT INTO Numbers VALUES (@x)
END

这是函数：

CREATE FUNCTION dbo.ListDates
(
     @StartDate    char(10)  
    ,@EndDate      char(10)
)
RETURNS
@DateList table
(
    Date datetime
)
AS
BEGIN


IF ISDATE(@StartDate)!=1 OR ISDATE(@EndDate)!=1
BEGIN
    RETURN
END

INSERT INTO @DateList
        (Date)
    SELECT
        CONVERT(datetime,@StartDate)+n.Number-1
        FROM Numbers  n
        WHERE Number<=DATEDIFF(day,@StartDate,CONVERT(datetime,@EndDate)+1)


RETURN

END --Function

用这个：

select * from dbo.ListDates('2010-01-01', '2010-01-13')

输出：

Date
-----------------------
2010-01-01 00:00:00.000
2010-01-02 00:00:00.000
2010-01-03 00:00:00.000
2010-01-04 00:00:00.000
2010-01-05 00:00:00.000
2010-01-06 00:00:00.000
2010-01-07 00:00:00.000
2010-01-08 00:00:00.000
2010-01-09 00:00:00.000
2010-01-10 00:00:00.000
2010-01-11 00:00:00.000
2010-01-12 00:00:00.000
2010-01-13 00:00:00.000

(13 row(s) affected)

也许，如果您希望采用一种更简单的方法，则应该这样做。

WITH date_range (calc_date) AS (
    SELECT DATEADD(DAY, DATEDIFF(DAY, 0, CURRENT_TIMESTAMP) - 6, 0)
        UNION ALL SELECT DATEADD(DAY, 1, calc_date)
            FROM date_range
            WHERE DATEADD(DAY, 1, calc_date) < CURRENT_TIMESTAMP)
SELECT calc_date
FROM date_range;

但是临时表也是一种非常好的方法。也许您还应该考虑填充的日历表。

绝对是一个数字表，但是如果您确实需要性能，则可能要使用Mark Redman的CLR proc / assembly的想法。

如何创建日期表（以及创建数字表的超快速方法）

/*Gets a list of integers into a temp table (Jeff Moden's idea from SqlServerCentral.com)*/
 SELECT TOP 10950 /*30 years of days*/
        IDENTITY(INT,1,1) as N
   INTO #Numbers
   FROM Master.dbo.SysColumns sc1,
        Master.dbo.SysColumns sc2


/*Create the dates table*/
CREATE TABLE [TableOfDates](
    [fld_date] [datetime] NOT NULL,
 CONSTRAINT [PK_TableOfDates] PRIMARY KEY CLUSTERED 
(
    [fld_date] ASC
)WITH FILLFACTOR = 99 ON [PRIMARY]
) ON [PRIMARY]

/*fill the table with dates*/
DECLARE @daysFromFirstDateInTheTable int
DECLARE @firstDateInTheTable DATETIME

SET @firstDateInTheTable = '01/01/1998'
SET @daysFromFirstDateInTheTable = (SELECT (DATEDIFF(dd, @firstDateInTheTable ,GETDATE()) + 1))

INSERT INTO
      TableOfDates
SELECT 
      DATEADD(dd,nums.n - @daysFromFirstDateInTheTable, CAST(FLOOR(CAST(GETDATE() as FLOAT)) as DateTime)) as FLD_Date
FROM #Numbers nums

现在您已经有了一个日期表，可以使用诸如KM之类的函数（不是PROC）来获取日期表。

CREATE FUNCTION dbo.ListDates
(
     @StartDate    DATETIME  
    ,@EndDate      DATETIME
)
RETURNS
@DateList table
(
    Date datetime
)
AS
BEGIN

/*add some validation logic of your own to make sure that the inputs are sound.Adjust the rest as needed*/

  INSERT INTO
    @DateList
  SELECT FLD_Date FROM TableOfDates (NOLOCK) WHERE FLD_Date >= @StartDate AND FLD_Date <= @EndDate
  RETURN
END

Declare @date1 date = '2016-01-01'
              ,@date2 date = '2016-03-31'
              ,@date_index date
Declare @calender table (D date)
SET @date_index = @date1
WHILE @date_index<=@date2
BEGIN
INSERT INTO @calender
SELECT @date_index

SET @date_index = dateadd(day,1,@date_index)

IF @date_index>@date2
Break
ELSE
Continue
END

-###一打中的六个。假设MsSql的另一种方法

Declare @MonthStart    datetime   = convert(DateTime,'07/01/2016')
Declare @MonthEnd      datetime   = convert(DateTime,'07/31/2016')
Declare @DayCount_int       Int   = 0 
Declare @WhileCount_int     Int   = 0

set @DayCount_int = DATEDIFF(DAY, @MonthStart, @MonthEnd)
select @WhileCount_int
WHILE @WhileCount_int < @DayCount_int + 1
BEGIN
   print convert(Varchar(24),DateAdd(day,@WhileCount_int,@MonthStart),101)
   SET @WhileCount_int = @WhileCount_int + 1;
END;

如果您要打印从特定年份到当前日期的年份。刚刚更改了接受的答案。

WITH mycte AS
    (
      SELECT YEAR(CONVERT(DATE, '2006-01-01',102)) DateValue
      UNION ALL
      SELECT  DateValue + 1
      FROM    mycte   
      WHERE   DateValue + 1 < = YEAR(GETDATE())
    )
    SELECT  DateValue
    FROM    mycte

OPTION (MAXRECURSION 0)

该查询适用于Microsoft SQL Server。

select distinct format( cast('2010-01-01' as datetime) + ( a.v / 10 ), 'yyyy-MM-dd' ) as aDate
       from (
             SELECT ones.n + 10 * tens.n + 100 * hundreds.n + 1000 * thousands.n as v
             FROM (VALUES(0),(1),(2),(3),(4),(5),(6),(7),(8),(9)) ones(n),
                    (VALUES(0),(1),(2),(3),(4),(5),(6),(7),(8),(9)) tens(n),
                    (VALUES(0),(1),(2),(3),(4),(5),(6),(7),(8),(9)) hundreds(n),
                  (VALUES(0),(1),(2),(3),(4),(5),(6),(7),(8),(9)) thousands(n)
       ) a
       where format( cast('2010-01-01' as datetime) + ( a.v / 10 ), 'yyyy-MM-dd' ) < cast('2010-01-13' as datetime)
       order by aDate asc;

现在让我们看看它是如何工作的。

内部查询仅返回一个从0到9999的整数列表。它将为我们提供10,000个值的范围来计算日期。您可以通过添加1万和100万的行等等来获得更多日期。

SELECT ones.n + 10 * tens.n + 100 * hundreds.n + 1000 * thousands.n as v
         FROM (VALUES(0),(1),(2),(3),(4),(5),(6),(7),(8),(9)) ones(n),
                (VALUES(0),(1),(2),(3),(4),(5),(6),(7),(8),(9)) tens(n),
                (VALUES(0),(1),(2),(3),(4),(5),(6),(7),(8),(9)) hundreds(n),
              (VALUES(0),(1),(2),(3),(4),(5),(6),(7),(8),(9)) thousands(n)
   ) a;

这部分将字符串转换为日期，并从内部查询中为其添加数字。

cast('2010-01-01' as datetime) + ( a.v / 10 )

然后，我们将结果转换为所需的格式。这也是列名！

format( cast('2010-01-01' as datetime) + ( a.v / 10 ), 'yyyy-MM-dd' )

接下来，我们仅提取不同的值，并为列名指定aDate的别名。

distinct format( cast('2010-01-01' as datetime) + ( a.v / 10 ), 'yyyy-MM-dd' ) as aDate

我们使用where子句仅过滤所需范围内的日期。请注意，由于SQL Server在where子句中不接受列别名aDate，因此我们在此处使用列名。

where format( cast('2010-01-01' as datetime) + ( a.v / 10 ), 'yyyy-MM-dd' ) < cast('2010-01-13' as datetime)

最后，我们对结果进行排序。

   order by aDate asc;

如果您处于像我这样的情况，其中禁止使用过程和函数，并且您的sql用户没有插入权限，因此不允许插入，也“不允许设置/声明类似@c的临时变量”，但是您想要要生成特定时期的日期列表（例如，本年度进行一些汇总），请使用此

select * from 
(select adddate('1970-01-01',t4*10000 + t3*1000 + t2*100 + t1*10 + t0) gen_date from
 (select 0 t0 union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t0,
 (select 0 t1 union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t1,
 (select 0 t2 union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t2,
 (select 0 t3 union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t3,
 (select 0 t4 union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t4) v
where gen_date between '2017-01-01' and '2017-12-31'

WITH TEMP (DIA, SIGUIENTE_DIA ) AS
           (SELECT 
               1, 
               CAST(@FECHAINI AS DATE)
            FROM 
               DUAL
           UNION ALL
            SELECT 
               DIA, 
               DATEADD(DAY, DIA, SIGUIENTE_DIA)
            FROM 
               TEMP
            WHERE
               DIA < DATEDIFF(DAY,  @FECHAINI, @FECHAFIN)   
               AND DATEADD(DAY, 1, SIGUIENTE_DIA) <=  CAST(@FECHAFIN AS DATE)
           )
           SELECT 
              SIGUIENTE_DIA AS CALENDARIO 
           FROM
              TEMP
           ORDER BY   
              SIGUIENTE_DIA

详细信息在表DUAL上，但是如果您将此表交换为虚拟表，则可以使用。

SELECT  dateadd(dd,DAYS,'2013-09-07 00:00:00') DATES
INTO        #TEMP1
FROM
(SELECT TOP 365 colorder - 1 AS DAYS from master..syscolumns 
    WHERE id = -519536829 order by colorder) a

WHERE datediff(dd,dateadd(dd,DAYS,'2013-09-07 00:00:00'),'2013-09-13 00:00:00' ) >= 0 
    AND  dateadd(dd,DAYS,'2013-09-07 00:00:00') <=  '2013-09-13 00:00:00'  
    SELECT * FROM #TEMP1

答案是avialbe在这里 如何列出两个日期之间的所有日期

Create Procedure SelectDates(@fromDate Date, @toDate Date)
AS
BEGIN
    SELECT DATEADD(DAY,number,@fromDate) [Date]
    FROM master..spt_values
    WHERE type = 'P'
    AND DATEADD(DAY,number,@fromDate) < @toDate

END

DECLARE @StartDate DATE = '2017-09-13',         @EndDate DATE = '2017-09-16'

SELECT date  FROM (   SELECT DATE = DATEADD(DAY, rn - 1, @StartDate)   FROM    (
    SELECT TOP (DATEDIFF(DAY, @StartDate, DATEADD(DAY,1,@EndDate)))
      rn = ROW_NUMBER() OVER (ORDER BY s1.[object_id])
    FROM sys.all_objects AS s1
    CROSS JOIN sys.all_objects AS s2
    ORDER BY s1.[object_id]   ) AS x ) AS y

结果：

2017-09-13

2017-09-14

2017-09-15

2017-09-16