我正在使用一个表单小部件，供用户在文本输入中输入一天的时间（对于日历应用程序）。我想使用JavaScript（我们使用的是jQuery FWIW）来解析用户输入到JavaScriptDate()对象中的文本的最佳方法，以便我可以轻松地执行比较和其他操作。
我尝试了该parse()方法，但对于我的需求来说有点挑剔。我希望它能够成功地将以下示例输入时间（除了其他逻辑上相似的时间格式）解析为同一Date()对象：
我认为我可能会使用正则表达式来拆分输入并提取要用于创建Date()对象的信息。做这个的最好方式是什么？
Answers:
一种适用于您指定的输入的快速解决方案：
function parseTime( t ) {
var d = new Date();
var time = t.match( /(\d+)(?::(\d\d))?\s*(p?)/ );
d.setHours( parseInt( time[1]) + (time[3] ? 12 : 0) );
d.setMinutes( parseInt( time[2]) || 0 );
return d;
}
var tests = [
'1:00 pm','1:00 p.m.','1:00 p','1:00pm','1:00p.m.','1:00p','1 pm',
'1 p.m.','1 p','1pm','1p.m.', '1p', '13:00','13', '1a', '12', '12a', '12p', '12am', '12pm', '2400am', '2400pm', '2400',
'1000', '100', '123', '2459', '2359', '2359am', '1100', '123p',
'1234', '1', '9', '99', '999', '9999', '99999', '0000', '0011', '-1', 'mioaw' ];
for ( var i = 0; i < tests.length; i++ ) {
console.log( tests[i].padStart( 9, ' ' ) + " = " + parseTime(tests[i]) );
}它也应该适用于其他一些品种（例如，即使使用了am，它仍然可以使用-例如）。显然，这很粗糙，但是也很轻巧（例如，使用它比完整的库便宜得多）。
警告：该代码不适用于12:00 AM等。
提供的所有示例在从12:00 am到12:59 am的时间内都无法正常工作。如果正则表达式与时间不匹配，它们也会引发错误。以下处理此问题：
function parseTime(timeString) {
if (timeString == '') return null;
var time = timeString.match(/(\d+)(:(\d\d))?\s*(p?)/i);
if (time == null) return null;
var hours = parseInt(time[1],10);
if (hours == 12 && !time[4]) {
hours = 0;
}
else {
hours += (hours < 12 && time[4])? 12 : 0;
}
var d = new Date();
d.setHours(hours);
d.setMinutes(parseInt(time[3],10) || 0);
d.setSeconds(0, 0);
return d;
}
var tests = [
'1:00 pm','1:00 p.m.','1:00 p','1:00pm','1:00p.m.','1:00p','1 pm',
'1 p.m.','1 p','1pm','1p.m.', '1p', '13:00','13', '1a', '12', '12a', '12p', '12am', '12pm', '2400am', '2400pm', '2400',
'1000', '100', '123', '2459', '2359', '2359am', '1100', '123p',
'1234', '1', '9', '99', '999', '9999', '99999', '0000', '0011', '-1', 'mioaw' ];
for ( var i = 0; i < tests.length; i++ ) {
console.log( tests[i].padStart( 9, ' ' ) + " = " + parseTime(tests[i]) );
}这将适用于其中包含时间的字符串。因此，将解析“ abcde12：00pmdef”并返回12 pm。如果期望的结果是仅在字符串中包含时间时返回一个时间，则可以使用以下正则表达式，前提是您将“ time [4]”替换为“ time [6]”。
/^(\d+)(:(\d\d))?\s*((a|(p))m?)?$/i
不用自己动手，只需使用datejs即可。
当无法解析字符串时，此处的大多数正则表达式解决方案都会引发错误，并且其中很少有类似1330或的字符串130pm。尽管OP并未指定这些格式，但我发现它们对于解析人类输入的日期至关重要。
所有这些使我想到使用正则表达式可能不是最好的方法。
我的解决方案是一个函数，它不仅解析时间，而且还允许您指定输出格式和四舍五入到的步长（间隔）。它大约有70行，仍然很轻巧，可以解析所有上述格式以及没有冒号的格式。
function parseTime(time, format, step) {
var hour, minute, stepMinute,
defaultFormat = 'g:ia',
pm = time.match(/p/i) !== null,
num = time.replace(/[^0-9]/g, '');
// Parse for hour and minute
switch(num.length) {
case 4:
hour = parseInt(num[0] + num[1], 10);
minute = parseInt(num[2] + num[3], 10);
break;
case 3:
hour = parseInt(num[0], 10);
minute = parseInt(num[1] + num[2], 10);
break;
case 2:
case 1:
hour = parseInt(num[0] + (num[1] || ''), 10);
minute = 0;
break;
default:
return '';
}
// Make sure hour is in 24 hour format
if( pm === true && hour > 0 && hour < 12 ) hour += 12;
// Force pm for hours between 13:00 and 23:00
if( hour >= 13 && hour <= 23 ) pm = true;
// Handle step
if( step ) {
// Step to the nearest hour requires 60, not 0
if( step === 0 ) step = 60;
// Round to nearest step
stepMinute = (Math.round(minute / step) * step) % 60;
// Do we need to round the hour up?
if( stepMinute === 0 && minute >= 30 ) {
hour++;
// Do we need to switch am/pm?
if( hour === 12 || hour === 24 ) pm = !pm;
}
minute = stepMinute;
}
// Keep within range
if( hour <= 0 || hour >= 24 ) hour = 0;
if( minute < 0 || minute > 59 ) minute = 0;
// Format output
return (format || defaultFormat)
// 12 hour without leading 0
.replace(/g/g, hour === 0 ? '12' : 'g')
.replace(/g/g, hour > 12 ? hour - 12 : hour)
// 24 hour without leading 0
.replace(/G/g, hour)
// 12 hour with leading 0
.replace(/h/g, hour.toString().length > 1 ? (hour > 12 ? hour - 12 : hour) : '0' + (hour > 12 ? hour - 12 : hour))
// 24 hour with leading 0
.replace(/H/g, hour.toString().length > 1 ? hour : '0' + hour)
// minutes with leading zero
.replace(/i/g, minute.toString().length > 1 ? minute : '0' + minute)
// simulate seconds
.replace(/s/g, '00')
// lowercase am/pm
.replace(/a/g, pm ? 'pm' : 'am')
// lowercase am/pm
.replace(/A/g, pm ? 'PM' : 'AM');
}
var tests = [
'1:00 pm','1:00 p.m.','1:00 p','1:00pm','1:00p.m.','1:00p','1 pm',
'1 p.m.','1 p','1pm','1p.m.', '1p', '13:00','13', '1a', '12', '12a', '12p', '12am', '12pm', '2400am', '2400pm', '2400',
'1000', '100', '123', '2459', '2359', '2359am', '1100', '123p',
'1234', '1', '9', '99', '999', '9999', '99999', '0000', '0011', '-1', 'mioaw' ];
for ( var i = 0; i < tests.length; i++ ) {
console.log( tests[i].padStart( 9, ' ' ) + " = " + parseTime(tests[i]) );
}这是对乔的版本的改进。随时对其进行进一步编辑。
function parseTime(timeString)
{
if (timeString == '') return null;
var d = new Date();
var time = timeString.match(/(\d+)(:(\d\d))?\s*(p?)/i);
d.setHours( parseInt(time[1],10) + ( ( parseInt(time[1],10) < 12 && time[4] ) ? 12 : 0) );
d.setMinutes( parseInt(time[3],10) || 0 );
d.setSeconds(0, 0);
return d;
}
var tests = [
'1:00 pm','1:00 p.m.','1:00 p','1:00pm','1:00p.m.','1:00p','1 pm',
'1 p.m.','1 p','1pm','1p.m.', '1p', '13:00','13', '1a', '12', '12a', '12p', '12am', '12pm', '2400am', '2400pm', '2400',
'1000', '100', '123', '2459', '2359', '2359am', '1100', '123p',
'1234', '1', '9', '99', '999', '9999', '99999', '0000', '0011', '-1', 'mioaw' ];
for ( var i = 0; i < tests.length; i++ ) {
console.log( tests[i].padStart( 9, ' ' ) + " = " + parseTime(tests[i]) );
}变化：
在实施John Resig的解决方案时，我遇到了一些麻烦。这是根据他的回答我一直在使用的修改后的函数：
function parseTime(timeString)
{
if (timeString == '') return null;
var d = new Date();
var time = timeString.match(/(\d+)(:(\d\d))?\s*(p?)/);
d.setHours( parseInt(time[1]) + ( ( parseInt(time[1]) < 12 && time[4] ) ? 12 : 0) );
d.setMinutes( parseInt(time[3]) || 0 );
d.setSeconds(0, 0);
return d;
} // parseTime()
var tests = [
'1:00 pm','1:00 p.m.','1:00 p','1:00pm','1:00p.m.','1:00p','1 pm',
'1 p.m.','1 p','1pm','1p.m.', '1p', '13:00','13', '1a', '12', '12a', '12p', '12am', '12pm', '2400am', '2400pm', '2400',
'1000', '100', '123', '2459', '2359', '2359am', '1100', '123p',
'1234', '1', '9', '99', '999', '9999', '99999', '0000', '0011', '-1', 'mioaw' ];
for ( var i = 0; i < tests.length; i++ ) {
console.log( tests[i].padStart( 9, ' ' ) + " = " + parseTime(tests[i]) );
}对于所有使用以下24小时时钟的人，这里提供的解决方案更多：
function parseTime(text) {
var time = text.match(/(\d?\d):?(\d?\d?)/);
var h = parseInt(time[1], 10);
var m = parseInt(time[2], 10) || 0;
if (h > 24) {
// try a different format
time = text.match(/(\d)(\d?\d?)/);
h = parseInt(time[1], 10);
m = parseInt(time[2], 10) || 0;
}
var d = new Date();
d.setHours(h);
d.setMinutes(m);
return d;
}
var tests = [
'1:00 pm','1:00 p.m.','1:00 p','1:00pm','1:00p.m.','1:00p','1 pm',
'1 p.m.','1 p','1pm','1p.m.', '1p', '13:00','13', '1a', '12', '12a', '12p', '12am', '12pm', '2400am', '2400pm', '2400',
'1000', '100', '123', '2459', '2359', '2359am', '1100', '123p',
'1234', '1', '9', '99', '999', '9999', '99999', '0000', '0011', '-1', 'mioaw' ];
for ( var i = 0; i < tests.length; i++ ) {
console.log( tests[i].padStart( 9, ' ' ) + " = " + parseTime(tests[i]) );
}该时间包的大小0.9kbs。NPM和Bower软件包管理器可用。
这是直接来自的示例README.md：
var t = Time('2p');
t.hours(); // 2
t.minutes(); // 0
t.period(); // 'pm'
t.toString(); // '2:00 pm'
t.nextDate(); // Sep 10 2:00 (assuming it is 1 o'clock Sep 10)
t.format('hh:mm AM') // '02:00 PM'
t.isValid(); // true
Time.isValid('99:12'); // false
这是一种更坚固的方法，它考虑了用户打算如何使用这种类型的输入。例如，如果用户输入“ 12”，则他们希望它是下午12点（中午）而不是上午12点。下面的函数处理所有这些。也可以在这里找到：http : //blog.de-zwart.net/2010-02/javascript-parse-time/
/**
* Parse a string that looks like time and return a date object.
* @return Date object on success, false on error.
*/
String.prototype.parseTime = function() {
// trim it and reverse it so that the minutes will always be greedy first:
var value = this.trim().reverse();
// We need to reverse the string to match the minutes in greedy first, then hours
var timeParts = value.match(/(a|p)?\s*((\d{2})?:?)(\d{1,2})/i);
// This didnt match something we know
if (!timeParts) {
return false;
}
// reverse it:
timeParts = timeParts.reverse();
// Reverse the internal parts:
for( var i = 0; i < timeParts.length; i++ ) {
timeParts[i] = timeParts[i] === undefined ? '' : timeParts[i].reverse();
}
// Parse out the sections:
var minutes = parseInt(timeParts[1], 10) || 0;
var hours = parseInt(timeParts[0], 10);
var afternoon = timeParts[3].toLowerCase() == 'p' ? true : false;
// If meridian not set, and hours is 12, then assume afternoon.
afternoon = !timeParts[3] && hours == 12 ? true : afternoon;
// Anytime the hours are greater than 12, they mean afternoon
afternoon = hours > 12 ? true : afternoon;
// Make hours be between 0 and 12:
hours -= hours > 12 ? 12 : 0;
// Add 12 if its PM but not noon
hours += afternoon && hours != 12 ? 12 : 0;
// Remove 12 for midnight:
hours -= !afternoon && hours == 12 ? 12 : 0;
// Check number sanity:
if( minutes >= 60 || hours >= 24 ) {
return false;
}
// Return a date object with these values set.
var d = new Date();
d.setHours(hours);
d.setMinutes(minutes);
return d;
}
var tests = [
'1:00 pm','1:00 p.m.','1:00 p','1:00pm','1:00p.m.','1:00p','1 pm',
'1 p.m.','1 p','1pm','1p.m.', '1p', '13:00','13', '1a', '12', '12a', '12p', '12am', '12pm', '2400am', '2400pm', '2400',
'1000', '100', '123', '2459', '2359', '2359am', '1100', '123p',
'1234', '1', '9', '99', '999', '9999', '99999', '0000', '0011', '-1', 'mioaw' ];
for ( var i = 0; i < tests.length; i++ ) {
console.log( tests[i].padStart( 9, ' ' ) + " = " + tests[i].parseTime() );
}这是一个字符串原型，因此您可以像这样使用它：
var str = '12am';
var date = str.parseTime();
AnyTime.Converter可以解析许多不同格式的日期/时间：
很多答案，所以再也不会受到伤害。
/**
* Parse a time in nearly any format
* @param {string} time - Anything like 1 p, 13, 1:05 p.m., etc.
* @returns {Date} - Date object for the current date and time set to parsed time
*/
function parseTime(time) {
var b = time.match(/\d+/g);
// return undefined if no matches
if (!b) return;
var d = new Date();
d.setHours(b[0]>12? b[0] : b[0]%12 + (/p/i.test(time)? 12 : 0), // hours
/\d/.test(b[1])? b[1] : 0, // minutes
/\d/.test(b[2])? b[2] : 0); // seconds
return d;
}
var tests = [
'1:00 pm','1:00 p.m.','1:00 p','1:00pm','1:00p.m.','1:00p','1 pm',
'1 p.m.','1 p','1pm','1p.m.', '1p', '13:00','13', '1a', '12', '2400',
'1000', '100', '123', '2459', '2359', '2359am', '1100', '123p',
'1234', '1', '9', '99', '999', '9999', '99999', '0000', '0011', '-1', 'mioaw' ];
for ( var i = 0; i < tests.length; i++ ) {
console.log( tests[i].padStart( 9, ' ' ) + " = " + parseTime(tests[i]) );
}为了使其具有适当的鲁棒性，它应检查每个值是否在允许值的范围内，例如，am / pm小时是否必须为1到12（含），否则为0到24（含）等。
我对上面的功能做了一些修改，以支持更多格式。
还没有清除它，但可以满足我的所有想法。
function parseTime(timeString) {
if (timeString == '') return null;
var time = timeString.match(/^(\d+)([:\.](\d\d))?\s*((a|(p))m?)?$/i);
if (time == null) return null;
var m = parseInt(time[3], 10) || 0;
var hours = parseInt(time[1], 10);
if (time[4]) time[4] = time[4].toLowerCase();
// 12 hour time
if (hours == 12 && !time[4]) {
hours = 12;
}
else if (hours == 12 && (time[4] == "am" || time[4] == "a")) {
hours += 12;
}
else if (hours < 12 && (time[4] != "am" && time[4] != "a")) {
hours += 12;
}
// 24 hour time
else if(hours > 24 && hours.toString().length >= 3) {
if(hours.toString().length == 3) {
m = parseInt(hours.toString().substring(1,3), 10);
hours = parseInt(hours.toString().charAt(0), 10);
}
else if(hours.toString().length == 4) {
m = parseInt(hours.toString().substring(2,4), 10);
hours = parseInt(hours.toString().substring(0,2), 10);
}
}
var d = new Date();
d.setHours(hours);
d.setMinutes(m);
d.setSeconds(0, 0);
return d;
}
var tests = [
'1:00 pm','1:00 p.m.','1:00 p','1:00pm','1:00p.m.','1:00p','1 pm',
'1 p.m.','1 p','1pm','1p.m.', '1p', '13:00','13', '1a', '12', '12a', '12p', '12am', '12pm', '2400am', '2400pm', '2400',
'1000', '100', '123', '2459', '2359', '2359am', '1100', '123p',
'1234', '1', '9', '99', '999', '9999', '99999', '0000', '0011', '-1', 'mioaw' ];
for ( var i = 0; i < tests.length; i++ ) {
console.log( tests[i].padStart( 9, ' ' ) + " = " + parseTime(tests[i]) );
}这是覆盖原始答案，任意合理位数，猫输入数据和逻辑谬论的另一种方法。该算法如下：
将小时，分钟和后继子句转换为Date对象是读者的一项工作（许多其他答案显示了如何执行此操作）。
"use strict";
String.prototype.toTime = function () {
var time = this;
var post_meridiem = false;
var ante_meridiem = false;
var hours = 0;
var minutes = 0;
if( time != null ) {
post_meridiem = time.match( /p/i ) !== null;
ante_meridiem = time.match( /a/i ) !== null;
// Preserve 2400h time by changing leading zeros to 24.
time = time.replace( /^00/, '24' );
// Strip the string down to digits and convert to a number.
time = parseInt( time.replace( /\D/g, '' ) );
}
else {
time = 0;
}
if( time > 0 && time < 24 ) {
// 1 through 23 become hours, no minutes.
hours = time;
}
else if( time >= 100 && time <= 2359 ) {
// 100 through 2359 become hours and two-digit minutes.
hours = ~~(time / 100);
minutes = time % 100;
}
else if( time >= 2400 ) {
// After 2400, it's midnight again.
minutes = (time % 100);
post_meridiem = false;
}
if( hours == 12 && ante_meridiem === false ) {
post_meridiem = true;
}
if( hours > 12 ) {
post_meridiem = true;
hours -= 12;
}
if( minutes > 59 ) {
minutes = 59;
}
var result =
(""+hours).padStart( 2, "0" ) + ":" + (""+minutes).padStart( 2, "0" ) +
(post_meridiem ? "PM" : "AM");
return result;
};
var tests = [
'1:00 pm','1:00 p.m.','1:00 p','1:00pm','1:00p.m.','1:00p','1 pm',
'1 p.m.','1 p','1pm','1p.m.', '1p', '13:00','13', '1a', '12', '12a', '12p', '12am', '12pm', '2400am', '2400pm', '2400',
'1000', '100', '123', '2459', '2359', '2359am', '1100', '123p',
'1234', '1', '9', '99', '999', '9999', '99999', '0000', '0011', '-1', 'mioaw' ];
for ( var i = 0; i < tests.length; i++ ) {
console.log( tests[i].padStart( 9, ' ' ) + " = " + tests[i].toTime() );
}在jQuery中，新定义的String原型的用法如下：
<input type="text" class="time" />
$(".time").change( function() {
var $this = $(this);
$(this).val( time.toTime() );
});
我对其他答案不满意，所以又做了一个。这个版本：
undefined无效输入，例如“ 13:00 pm”或“ 11:65”localDate参数，则返回，否则返回Unix时代（1970年1月1日）的UTC时间。1330（要禁用，请在正则表达式中输入第一个“：”）^\s*在正则表达式中）编辑：现在它是一个包含格式化程序的软件包timeToString：npm i simplertime
/**
* Parses a string into a Date. Supports several formats: "12", "1234",
* "12:34", "12:34pm", "12:34 PM", "12:34:56 pm", and "12:34:56.789".
* The time must be at the beginning of the string but can have leading spaces.
* Anything is allowed after the time as long as the time itself appears to
* be valid, e.g. "12:34*Z" is OK but "12345" is not.
* @param {string} t Time string, e.g. "1435" or "2:35 PM" or "14:35:00.0"
* @param {Date|undefined} localDate If this parameter is provided, setHours
* is called on it. Otherwise, setUTCHours is called on 1970/1/1.
* @returns {Date|undefined} The parsed date, if parsing succeeded.
*/
function parseTime(t, localDate) {
// ?: means non-capturing group and ?! is zero-width negative lookahead
var time = t.match(/^\s*(\d\d?)(?::?(\d\d))?(?::(\d\d))?(?!\d)(\.\d+)?\s*(pm?|am?)?/i);
if (time) {
var hour = parseInt(time[1]), pm = (time[5] || ' ')[0].toUpperCase();
var min = time[2] ? parseInt(time[2]) : 0;
var sec = time[3] ? parseInt(time[3]) : 0;
var ms = (time[4] ? parseFloat(time[4]) * 1000 : 0);
if (pm !== ' ' && (hour == 0 || hour > 12) || hour > 24 || min >= 60 || sec >= 60)
return undefined;
if (pm === 'A' && hour === 12) hour = 0;
if (pm === 'P' && hour !== 12) hour += 12;
if (hour === 24) hour = 0;
var date = new Date(localDate!==undefined ? localDate.valueOf() : 0);
var set = (localDate!==undefined ? date.setHours : date.setUTCHours);
set.call(date, hour, min, sec, ms);
return date;
}
return undefined;
}
var testSuite = {
'1300': ['1:00 pm','1:00 P.M.','1:00 p','1:00pm','1:00p.m.','1:00p','1 pm',
'1 p.m.','1 p','1pm','1p.m.', '1p', '13:00','13', '1:00:00PM', '1300', '13'],
'1100': ['11:00am', '11:00 AM', '11:00', '11:00:00', '1100'],
'1359': ['1:59 PM', '13:59', '13:59:00', '1359', '1359:00', '0159pm'],
'100': ['1:00am', '1:00 am', '0100', '1', '1a', '1 am'],
'0': ['00:00', '24:00', '12:00am', '12am', '12:00:00 AM', '0000', '1200 AM'],
'30': ['0:30', '00:30', '24:30', '00:30:00', '12:30:00 am', '0030', '1230am'],
'1435': ["2:35 PM", "14:35:00.0", "1435"],
'715.5': ["7:15:30", "7:15:30am"],
'109': ['109'], // Three-digit numbers work (I wasn't sure if they would)
'': ['12:60', '11:59:99', '-12:00', 'foo', '0660', '12345', '25:00'],
};
var passed = 0;
for (var key in testSuite) {
let num = parseFloat(key), h = num / 100 | 0;
let m = num % 100 | 0, s = (num % 1) * 60;
let expected = Date.UTC(1970, 0, 1, h, m, s); // Month is zero-based
let strings = testSuite[key];
for (let i = 0; i < strings.length; i++) {
var result = parseTime(strings[i]);
if (result === undefined ? key !== '' : key === '' || expected !== result.valueOf()) {
console.log(`Test failed at ${key}:"${strings[i]}" with result ${result ? result.toUTCString() : 'undefined'}`);
} else {
passed++;
}
}
}
console.log(passed + ' tests passed.');
其他答案汇编表
首先，我无法相信没有内置的功能甚至没有强大的第三方库可以处理此问题。实际上，这是Web开发，因此我可以相信。
试图用所有这些不同的算法测试所有极端情况让我很头疼，所以我自由地将这个线程中的所有答案和测试编译到一个方便的表中。
代码（和结果表）太大了，无法包含内联，所以我做了一个JSFiddle：
http://jsfiddle.net/jLv16ydb/4/show
// heres some filler code of the functions I included in the test,
// because StackOverfleaux wont let me have a jsfiddle link without code
Functions = [
JohnResig,
Qwertie,
PatrickMcElhaney,
Brad,
NathanVillaescusa,
DaveJarvis,
AndrewCetinic,
StefanHaberl,
PieterDeZwart,
JoeLencioni,
Claviska,
RobG,
DateJS,
MomentJS
];
// I didn't include `date-fns`, because it seems to have even more
// limited parsing than MomentJS or DateJS
请随意拨弄我的小提琴并添加更多算法和测试用例
我没有在结果和“预期”输出之间添加任何比较，因为在某些情况下可以对“预期”输出进行辩论（例如，应12解释为12:00am或12:00pm？）。您将必须仔细检查表格，看看哪种算法最适合您。
注意：颜色不一定表示输出的质量或“预期”，它们仅表示输出的类型：
red =抛出js错误
yellow= “falsy”值（undefined，null，NaN，""，"invalid date"）
green= jsDate()对象
light green =其他一切
在Date()输出对象的情况下，我将其转换为24小时HH:mm格式以便于比较。
为什么不使用验证来缩小用户可以放入的内容，并简化列表，使其仅包含可以解析（或在某些调整后解析）的格式。
我认为要求用户以受支持的格式放置时间并不要求太多。
dd：dd A（m）/ P（m）
dd A（m）/ P（m）
dd
对Patrick McElhaney解决方案的改进（他无法正确处理凌晨12点）
function parseTime( timeString ) {
var d = new Date();
var time = timeString.match(/(\d+)(:(\d\d))?\s*([pP]?)/i);
var h = parseInt(time[1], 10);
if (time[4])
{
if (h < 12)
h += 12;
}
else if (h == 12)
h = 0;
d.setHours(h);
d.setMinutes(parseInt(time[3], 10) || 0);
d.setSeconds(0, 0);
return d;
}
var tests = [
'1:00 pm','1:00 p.m.','1:00 p','1:00pm','1:00p.m.','1:00p','1 pm',
'1 p.m.','1 p','1pm','1p.m.', '1p', '13:00','13', '1a', '12', '2400',
'1000', '100', '123', '2459', '2359', '2359am', '1100', '123p',
'1234', '1', '9', '99', '999', '9999', '99999', '0000', '0011', '-1', 'mioaw' ];
for ( var i = 0; i < tests.length; i++ ) {
console.log( tests[i].padStart( 9, ' ' ) + " = " + parseTime(tests[i]) );
}如果你只想几秒钟，这里是一支班轮
const toSeconds = s => s.split(':').map(v => parseInt(v)).reverse().reduce((acc,e,i) => acc + e * Math.pow(60,i))
在对我的其他编译答案进行了彻底的测试和调查之后，我得出结论，@ Dave Jarvis的解决方案与我认为合理的输出和边缘案例处理最为接近。作为参考，我查看了Google日历的时间输入在退出文本框后将时间重新格式化为什么时间。
即便如此，我仍然看到它无法像Google日历那样处理一些（尽管很奇怪）边缘案例。因此，我从头开始进行了重新设计，这就是我想到的。我也将其添加到我的编译答案中。
// attempt to parse string as time. return js date object
function parseTime(string) {
string = String(string);
var am = null;
// check if "apm" or "pm" explicitly specified, otherwise null
if (string.toLowerCase().includes("p")) am = false;
else if (string.toLowerCase().includes("a")) am = true;
string = string.replace(/\D/g, ""); // remove non-digit characters
string = string.substring(0, 4); // take only first 4 digits
if (string.length === 3) string = "0" + string; // consider eg "030" as "0030"
string = string.replace(/^00/, "24"); // add 24 hours to preserve eg "0012" as "00:12" instead of "12:00", since will be converted to integer
var time = parseInt(string); // convert to integer
// default time if all else fails
var hours = 12,
minutes = 0;
// if able to parse as int
if (Number.isInteger(time)) {
// treat eg "4" as "4:00pm" (or "4:00am" if "am" explicitly specified)
if (time >= 0 && time <= 12) {
hours = time;
minutes = 0;
// if "am" or "pm" not specified, establish from number
if (am === null) {
if (hours >= 1 && hours <= 12) am = false;
else am = true;
}
}
// treat eg "20" as "8:00pm"
else if (time >= 13 && time <= 99) {
hours = time % 24;
minutes = 0;
// if "am" or "pm" not specified, force "am"
if (am === null) am = true;
}
// treat eg "52:95" as 52 hours 95 minutes
else if (time >= 100) {
hours = Math.floor(time / 100); // take first two digits as hour
minutes = time % 100; // take last two digits as minute
// if "am" or "pm" not specified, establish from number
if (am === null) {
if (hours >= 1 && hours <= 12) am = false;
else am = true;
}
}
// add 12 hours if "pm"
if (am === false && hours !== 12) hours += 12;
// sub 12 hours if "12:00am" (midnight), making "00:00"
if (am === true && hours === 12) hours = 0;
// keep hours within 24 and minutes within 60
// eg 52 hours 95 minutes becomes 4 hours 35 minutes
hours = hours % 24;
minutes = minutes % 60;
}
// convert to js date object
var date = new Date();
date.setHours(hours);
date.setMinutes(minutes);
date.setSeconds(0);
return date;
}
var tests = [
'1:00 pm','1:00 p.m.','1:00 p','1:00pm','1:00p.m.','1:00p','1 pm',
'1 p.m.','1 p','1pm','1p.m.', '1p', '13:00','13', '1a', '12', '12a', '12p', '12am', '12pm', '2400am', '2400pm', '2400',
'1000', '100', '123', '2459', '2359', '2359am', '1100', '123p',
'1234', '1', '9', '99', '999', '9999', '99999', '0000', '0011', '-1', 'mioaw' ];
for ( var i = 0; i < tests.length; i++ ) {
console.log( tests[i].padStart( 9, ' ' ) + " = " + parseTime(tests[i]) );
}我觉得这是我所需要的最接近的产品，但是欢迎提出建议。注意：这是以美国为中心的，对于某些模式它默认为am / pm：
1=> 13:00（1:00pm）1100=> 23:00（11:00pm）456=> 16:56（4:56pm）1100请将其解析为11:00am。（我敢打赌我们作为数据输入的大多数人类活动都是在白天进行的。）如果您可以回忆起缺乏我的解决方案的极端情况，那么对我的回答进行评论将不胜感激。不错的总结！
string = String(string);可string = String(string.toLowerCase())避免冗余呼叫。周围有布尔逻辑一些其他简化可以做出..
99*测试给不一致的结果，1000可能意味着10:00am，且-1为1:00pm好。但是，返回Date对象似乎超出了用例。（它假定还需要当前日期，对于输入的任何特定时间不一定是正确的。）
1100在GCal中映射到晚上11点。回复：99*，我不知道。可能会辩论，等应解释为什么999，9999但我的评论说了我的假设。在这种情况下，GCal甚至不接受52:95。最后，重新：Date。它提供了其它的一些get和format功能。还有一些库需要Date格式的东西，这就是我的案例iirc。