我试图用Java脚本编写视频扑克游戏,以降低其基础知识,但我遇到了一个问题,其中jQuery click事件处理程序多次触发。
它们被附加到用于下注的按钮上,并且在游戏过程中第一手下注时效果很好(仅触发一次);但是在秒针下注中,每次按下一个下注或下注按钮都会触发两次点击事件(因此,每次按下正确的赌注量是两次)。总体而言,在按一次下注按钮时触发单击事件的次数遵循此模式- 序列的第i个词用于从游戏开始时对第i只手进行下注:1、2、4 ,7、11、16、22、29、37、46,无论值多少,它看起来都是n(n + 1)/ 2 +1-而且我不够聪明,无法弄清楚,我使用OEIS。:)
这是正在起作用的click事件处理程序的函数;希望它很容易理解(让我知道是否可以,我也想做得更好):
/** The following function keeps track of bet buttons that are pressed, until place button is pressed to place bet. **/
function pushingBetButtons() {
$("#money").text("Money left: $" + player.money); // displays money player has left
$(".bet").click(function() {
var amount = 0; // holds the amount of money the player bet on this click
if($(this).attr("id") == "bet1") { // the player just bet $1
amount = 1;
} else if($(this).attr("id") == "bet5") { // etc.
amount = 5;
} else if($(this).attr("id") == "bet25") {
amount = 25;
} else if($(this).attr("id") == "bet100") {
amount = 100;
} else if($(this).attr("id") == "bet500") {
amount = 500;
} else if($(this).attr("id") == "bet1000") {
amount = 1000;
}
if(player.money >= amount) { // check whether the player has this much to bet
player.bet += amount; // add what was just bet by clicking that button to the total bet on this hand
player.money -= amount; // and, of course, subtract it from player's current pot
$("#money").text("Money left: $" + player.money); // then redisplay what the player has left
} else {
alert("You don't have $" + amount + " to bet.");
}
});
$("#place").click(function() {
if(player.bet == 0) { // player didn't bet anything on this hand
alert("Please place a bet first.");
} else {
$("#card_para").css("display", "block"); // now show the cards
$(".card").bind("click", cardClicked); // and set up the event handler for the cards
$("#bet_buttons_para").css("display", "none"); // hide the bet buttons and place bet button
$("#redraw").css("display", "block"); // and reshow the button for redrawing the hand
player.bet = 0; // reset the bet for betting on the next hand
drawNewHand(); // draw the cards
}
});
}
如果您有任何想法或建议,或者我的问题的解决方案是否类似于此处的另一个问题的解决方案,请让我知道(我看过很多标题相似的主题,也没有运气找到可行的解决方案为了我)。
var amount = parseInt(this.id.replace(/[^\d]/g,''),10);
而且,如果要多次使用元素的同一属性,请对该属性进行一次高速缓存,请不要一直查找它。查找很昂贵。