我正在尝试在SQLServer中聚合“ STRING”字段。我想找到与Oracle中相同的函数LISTAGG。
您知道如何执行相同的功能或其他方法吗?
例如,
Field A | Field B
1 | A
1 | B
2 | A
我希望这个查询的结果是
1 | AB
2 | A
Answers:
从SQL Server 2017开始,该STRING_AGG
功能可用,从而大大简化了逻辑:
select FieldA, string_agg(FieldB, '') as data
from yourtable
group by FieldA
在SQL Server中,您可以FOR XML PATH
用来获取结果:
select distinct t1.FieldA,
STUFF((SELECT distinct '' + t2.FieldB
from yourtable t2
where t1.FieldA = t2.FieldA
FOR XML PATH(''), TYPE
).value('.', 'NVARCHAR(MAX)')
,1,0,'') data
from yourtable t1;
SELECT FieldA
, GROUP_CONCAT(FieldB ORDER BY FieldB SEPARATOR ',') AS FieldBs
FROM TableName
GROUP BY FieldA
ORDER BY FieldA;
SELECT FieldA
, LISTAGG(FieldB, ',') WITHIN GROUP (ORDER BY FieldB) AS FieldBs
FROM TableName
GROUP BY FieldA
ORDER BY FieldA;
SELECT FieldA
, STRING_AGG(FieldB, ',' ORDER BY FieldB) AS FieldBs
FROM TableName
GROUP BY FieldA
ORDER BY FieldA;
SQL Server≥2017和Azure SQL
SELECT FieldA
, STRING_AGG(FieldB, ',') WITHIN GROUP (ORDER BY FieldB) AS FieldBs
FROM TableName
GROUP BY FieldA
ORDER BY FieldA;
SQL Server≤2016(包含CTE以鼓励DRY原则)
WITH CTE_TableName AS (
SELECT FieldA, FieldB
FROM TableName)
SELECT t0.FieldA
, STUFF((
SELECT ',' + t1.FieldB
FROM CTE_TableName t1
WHERE t1.FieldA = t0.FieldA
ORDER BY t1.FieldB
FOR XML PATH('')), 1, LEN(','), '') AS FieldBs
FROM CTE_TableName t0
GROUP BY t0.FieldA
ORDER BY FieldA;
订购需要CTE或子查询
WITH CTE_TableName AS (
SELECT FieldA, FieldB
FROM TableName
ORDER BY FieldA, FieldB)
SELECT FieldA
, GROUP_CONCAT(FieldB, ',') AS FieldBs
FROM CTE_TableName
GROUP BY FieldA
ORDER BY FieldA;
无需订购
SELECT FieldA
, GROUP_CONCAT(FieldB, ',') AS FieldBs
FROM TableName
GROUP BY FieldA
ORDER BY FieldA;
cte
另一台监视器上成功引用一个成功对象,我会以为您没有正确构建查询?
在SQL Server 2017中添加了STRING_AGG:
SELECT t.name,STRING_AGG (c.name, ',') AS csv
FROM sys.tables t
JOIN sys.columns c on t.object_id = c.object_id
GROUP BY t.name
ORDER BY 1
此外,STRING_SPLIT对于相反的情况也很有用,并且在SQL Server 2016中可用