F＃List.map是否等效于C＃？

C＃中有与F＃的List.map函数等效的功能吗？即对列表中的每个元素应用一个函数，并返回包含结果的新列表。

就像是：

    public static IEnumerable<TResult> Map<TSource, TResult>(this IEnumerable<TSource> source, Func<TSource, TResult> funky)
    {
        foreach (TSource element in source)
            yield return funky.Invoke(element);
    }

是否已经有内置方式，还是应该只编写自定义扩展名？

那就是LINQ的Select-即

var newSequence = originalSequence.Select(x => {translation});

要么

var newSequence = from x in originalSequence
                  select {translation};

ConvertAll 是内置函数：

public List<TOutput> ConvertAll<TOutput>(
    Converter<T, TOutput> converter
)

自.NET 2.0版以来可用。

MSDN代码示例：

using System;
using System.Drawing;
using System.Collections.Generic;

public class Example
{
    public static void Main()
    {
        List<PointF> lpf = new List<PointF>();

        lpf.Add(new PointF(27.8F, 32.62F));
        lpf.Add(new PointF(99.3F, 147.273F));
        lpf.Add(new PointF(7.5F, 1412.2F));

        Console.WriteLine();
        foreach( PointF p in lpf )
        {
            Console.WriteLine(p);
        }

        List<Point> lp = lpf.ConvertAll( 
            new Converter<PointF, Point>(PointFToPoint));

        Console.WriteLine();
        foreach( Point p in lp )
        {
            Console.WriteLine(p);
        }
    }

    public static Point PointFToPoint(PointF pf)
    {
        return new Point(((int) pf.X), ((int) pf.Y));
    }
}

/* This code example produces the following output:

{X=27.8, Y=32.62}
{X=99.3, Y=147.273}
{X=7.5, Y=1412.2}

{X=27,Y=32}
{X=99,Y=147}
{X=7,Y=1412}
 */