在Python中将以分号分隔的字符串拆分为字典

我有一个看起来像这样的字符串：

"Name1=Value1;Name2=Value2;Name3=Value3"

Python中是否有内置类/函数将采用该字符串并构造一个字典，就像我已经做过的那样：

dict = {
    "Name1": "Value1",
    "Name2": "Value2",
    "Name3": "Value3"
}

I have looked through the modules available but can't seem to find anything that matches.

Thanks, I do know how to make the relevant code myself, but since such smallish solutions are usually mine-fields waiting to happen (ie. someone writes: Name1='Value1=2';) etc. then I usually prefer some pre-tested function.

I'll do it myself then.

There's no builtin, but you can accomplish this fairly simply with a generator comprehension:

s= "Name1=Value1;Name2=Value2;Name3=Value3"
dict(item.split("=") for item in s.split(";"))

[Edit] From your update you indicate you may need to handle quoting. This does complicate things, depending on what the exact format you are looking for is (what quote chars are accepted, what escape chars etc). You may want to look at the csv module to see if it can cover your format. Here's an example: (Note that the API is a little clunky for this example, as CSV is designed to iterate through a sequence of records, hence the .next() calls I'm making to just look at the first line. Adjust to suit your needs):

>>> s = "Name1='Value=2';Name2=Value2;Name3=Value3"

>>> dict(csv.reader([item], delimiter='=', quotechar="'").next() 
         for item in csv.reader([s], delimiter=';', quotechar="'").next())

{'Name2': 'Value2', 'Name3': 'Value3', 'Name1': 'Value1=2'}

Depending on the exact structure of your format, you may need to write your own simple parser however.

This comes close to doing what you wanted:

>>> import urlparse
>>> urlparse.parse_qs("Name1=Value1;Name2=Value2;Name3=Value3")
{'Name2': ['Value2'], 'Name3': ['Value3'], 'Name1': ['Value1']}

s1 = "Name1=Value1;Name2=Value2;Name3=Value3"

dict(map(lambda x: x.split('='), s1.split(';')))

It can be simply done by string join and list comprehension

",".join(["%s=%s" % x for x in d.items()])

>>d = {'a':1, 'b':2}
>>','.join(['%s=%s'%x for x in d.items()])
>>'a=1,b=2'

easytiger $ cat test.out test.py | sed 's/^/    /'
p_easytiger_quoting:1.84563302994
{'Name2': 'Value2', 'Name3': 'Value3', 'Name1': 'Value1'}
p_brian:2.30507516861
{'Name2': 'Value2', 'Name3': "'Value3'", 'Name1': 'Value1'}
p_kyle:7.22536420822
{'Name2': ['Value2'], 'Name3': ["'Value3'"], 'Name1': ['Value1']}
import timeit
import urlparse

s = "Name1=Value1;Name2=Value2;Name3='Value3'"

def p_easytiger_quoting(s):
    d = {}
    s = s.replace("'", "")
    for x in s.split(';'):
        k, v = x.split('=')
        d[k] = v
    return d


def p_brian(s):
    return dict(item.split("=") for item in s.split(";"))

def p_kyle(s):
    return urlparse.parse_qs(s)



print "p_easytiger_quoting:" + str(timeit.timeit(lambda: p_easytiger_quoting(s)))
print p_easytiger_quoting(s)


print "p_brian:" + str(timeit.timeit(lambda: p_brian(s)))
print p_brian(s)

print "p_kyle:" + str(timeit.timeit(lambda: p_kyle(s)))
print p_kyle(s)

IF your Value1, Value2 are just placeholders for actual values, you can also use the dict() function in combination with eval().

>>> s= "Name1=1;Name2=2;Name3='string'"
>>> print eval('dict('+s.replace(';',',')+')')
{'Name2: 2, 'Name3': 'string', 'Name1': 1}

This is beacuse the dict() function understand the syntax dict(Name1=1, Name2=2,Name3='string'). Spaces in the string (e.g. after each semicolon) are ignored. But note the string values do require quoting.