我添加了两个jQuery UI Dropdown自动完成脚本。现在,我想同时获取第二个下拉菜单的值onchange和要分别存储在变量中。怎么可能?
有什么想法或建议吗?谢谢。
我的小提琴: 样本
我的JS代码:
(function($) {
$.widget("ui.combobox", {
_create: function() {
var self = this,
select = this.element.hide(),
selected = select.children(":selected"),
value = selected.val() ? selected.text() : "";
var input = this.input = $("<input>").insertAfter(select).val(value).autocomplete({
delay: 0,
minLength: 0,
source: function(request, response) {
var matcher = new RegExp($.ui.autocomplete.escapeRegex(request.term), "i");
response(select.children("option").map(function() {
var text = $(this).text();
if (this.value && (!request.term || matcher.test(text)))
return {
label: text.replace(new RegExp("(?![^&;]+;)(?!<[^<>]*)(" + $.ui.autocomplete.escapeRegex(request.term) + ")(?![^<>]*>)(?![^&;]+;)", "gi"), "<strong>$1</strong>"),
value: text,
option: this
};
}));
},
select: function(event, ui) {
ui.item.option.selected = true;
self._trigger("selected", event, {
item: ui.item.option
});
select.trigger("change");
},
change: function(event, ui) {
if (!ui.item) {
var matcher = new RegExp("^" + $.ui.autocomplete.escapeRegex($(this).val()) + "$", "i"),
valid = false;
select.children("option").each(function() {
if ($(this).text().match(matcher)) {
this.selected = valid = true;
return false;
}
});
if (!valid) {
// remove invalid value, as it didn't match anything
$(this).val("");
select.val("");
input.data("autocomplete").term = "";
return false;
}
}
}
}).addClass("ui-widget ui-widget-content ui-corner-left");
input.data("autocomplete")._renderItem = function(ul, item) {
return $("<li></li>").data("item.autocomplete", item).append("<a>" + item.label + "</a>").appendTo(ul);
};
this.button = $("<button type='button'> </button>").attr("tabIndex", -1).attr("title", "Show All Items").insertAfter(input).button({
icons: {
primary: "ui-icon-triangle-1-s"
},
text: false
}).removeClass("ui-corner-all").addClass("ui-corner-right ui-button-icon").click(function() {
// close if already visible
if (input.autocomplete("widget").is(":visible")) {
input.autocomplete("close");
return;
}
// pass empty string as value to search for, displaying all results
input.autocomplete("search", "");
input.focus();
});
},
destroy: function() {
this.input.remove();
this.button.remove();
this.element.show();
$.Widget.prototype.destroy.call(this);
}
});
})(jQuery);
$(function() {
/*start point value*/
$("#pick").combobox({
change: function() {
alert("changed");
}
});
$("#toggle").click(function() {
$("#pick").toggle();
});
$("#pick").change(function() {
var start = this.value;
});
/*end point value*/
$("#drop").combobox({
change: function() {
alert("changed");
}
});
$("#toggle").click(function() {
$("#drop").toggle();
});
$("#drop").change(function() {
var end = this.value;
});
});
我的HTML代码:
<div class="ui-widget">
<select id="pick">
<option value="">Select one...</option>
<option value="1">1</option>
<option value="2">2</option>
<option value="3">3</option>
<option value="4">4</option>
</select>
<select id="drop">
<option value="">Select one...</option>
<option value="11">11</option>
<option value="12">12</option>
<option value="13">13</option>
<option value="14">14</option>
</select>
</div>
$("#drop").change(function () { var first = $('#pick').val(); var second = $(this).val(); console.log(first, second); });
JSFiddle的 注意事项。