如何从Google地图中的纬度和经度坐标中获取城市名称?


Answers:


243

Geocoder您可以从对象中调用getFromLocation(double, double, int)方法。它将返回Address具有方法的对象的列表getLocality()

Geocoder gcd = new Geocoder(context, Locale.getDefault());
List<Address> addresses = gcd.getFromLocation(lat, lng, 1);
if (addresses.size() > 0) {
    System.out.println(addresses.get(0).getLocality());
}
else {
   // do your stuff
}

2
我收到错误消息,提示“服务器等待响应超时”。我添加了Internet权限。还需要其他东西吗?
Bhaumik Belani '16

我不记得我还需要其他东西。尝试其他经纬度。
ccheneson

5
有时getLocality()返回null,城市名称停留在mAdminArea
Leo Droidcoder

2
对于美国(和其他一些国家/地区)的地址,请使用getAdminArea()返回状态
Dustfinger-恢复莫妮卡

请不要使用地理编码器。它在许多设备上引发异常,需要重新启动才能再次正常工作。
Prasad Pawar

27

我正在使用此代码。您还可以通过以下方法获取城市以及有关经度和纬度的其他详细信息:

public class getReverseGeoCoding {
    private String Address1 = "", Address2 = "", City = "", State = "", Country = "", County = "", PIN = "";
    
    public void getAddress() {
        Address1 = "";
        Address2 = "";
        City = "";
        State = "";
        Country = "";
        County = "";
        PIN = "";
        
        try {
            
            JSONObject jsonObj = parser_Json.getJSONfromURL("http://maps.googleapis.com/maps/api/geocode/json?latlng=" + Global.curLatitude + ","
                    + Global.curLongitude + "&sensor=true&key=YOUR_API_KEY");
            String Status = jsonObj.getString("status");
            if (Status.equalsIgnoreCase("OK")) {
                JSONArray Results = jsonObj.getJSONArray("results");
                JSONObject zero = Results.getJSONObject(0);
                JSONArray address_components = zero.getJSONArray("address_components");
                
                for (int i = 0; i < address_components.length(); i++) {
                    JSONObject zero2 = address_components.getJSONObject(i);
                    String long_name = zero2.getString("long_name");
                    JSONArray mtypes = zero2.getJSONArray("types");
                    String Type = mtypes.getString(0);
                    
                    if (TextUtils.isEmpty(long_name) == false || !long_name.equals(null) || long_name.length() > 0 || long_name != "") {
                        if (Type.equalsIgnoreCase("street_number")) {
                            Address1 = long_name + " ";
                        } else if (Type.equalsIgnoreCase("route")) {
                            Address1 = Address1 + long_name;
                        } else if (Type.equalsIgnoreCase("sublocality")) {
                            Address2 = long_name;
                        } else if (Type.equalsIgnoreCase("locality")) {
                            // Address2 = Address2 + long_name + ", ";
                            City = long_name;
                        } else if (Type.equalsIgnoreCase("administrative_area_level_2")) {
                            County = long_name;
                        } else if (Type.equalsIgnoreCase("administrative_area_level_1")) {
                            State = long_name;
                        } else if (Type.equalsIgnoreCase("country")) {
                            Country = long_name;
                        } else if (Type.equalsIgnoreCase("postal_code")) {
                            PIN = long_name;
                        }
                    }
                    
                    // JSONArray mtypes = zero2.getJSONArray("types");
                    // String Type = mtypes.getString(0);
                    // Log.e(Type,long_name);
                }
            }
            
        } catch (Exception e) {
            e.printStackTrace();
        }
        
    }
    
    public String getAddress1() {
        return Address1;
        
    }
    
    public String getAddress2() {
        return Address2;
        
    }
    
    public String getCity() {
        return City;
        
    }
    
    public String getState() {
        return State;
        
    }
    
    public String getCountry() {
        return Country;
        
    }
    
    public String getCounty() {
        return County;
        
    }
    
    public String getPIN() {
        return PIN;
        
    }
    
}

有关如何获取Google Map Api密钥的更多详细信息

JSON解析器类

public class parser_Json {
    public static JSONObject getJSONfromURL(String url) {

        // initialize
        InputStream is = null;
        String result = "";
        JSONObject jObject = null;

        // http post
        try {
            HttpClient httpclient = new DefaultHttpClient();
            HttpPost httppost = new HttpPost(url);
            HttpResponse response = httpclient.execute(httppost);
            HttpEntity entity = response.getEntity();
            is = entity.getContent();

        } catch (Exception e) {
            Log.e("log_tag", "Error in http connection " + e.toString());
        }

        // convert response to string
        try {
            BufferedReader reader = new BufferedReader(new InputStreamReader(is, "iso-8859-1"), 8);
            StringBuilder sb = new StringBuilder();
            String line = null;
            while ((line = reader.readLine()) != null) {
                sb.append(line + "\n");
            }
            is.close();
            result = sb.toString();
        } catch (Exception e) {
            Log.e("log_tag", "Error converting result " + e.toString());
        }

        // try parse the string to a JSON object
        try {
            jObject = new JSONObject(result);
        } catch (JSONException e) {
            Log.e("log_tag", "Error parsing data " + e.toString());
        }

        return jObject;
    }

}

您可以从此问题获取更多信息:使用纬度和经度获取特定地址


@ErumHannan您可以在服务中这样做** new getReverseGeoCoding()。getCity(); **这将返回您当前来自全球类的当前城市或经纬度。
Vipul Purohit

我使用了您的代码,但返回的错误为{“ error_message”:“”您必须使用API​​密钥来验证对Google Maps Platform API的每个请求。有关其他信息,请访问http:\ / \ / g.co \ / dev \ / maps-no-account“,”结果“:[],”状态“:” REQUEST_DENIED“}我应该如何解决?
Mohsen Hatami

12

试试这个

  List<Address> list = geoCoder.getFromLocation(location
            .getLatitude(), location.getLongitude(), 1);
    if (list != null & list.size() > 0) {
        Address address = list.get(0);
        result = address.getLocality();
        return result;

8

尝试下面的代码,希望对您有用:-

CityAsyncTask cst = new CityAsyncTask(HomeScreenUserLocation.this,
                latitude, longitude);
        cst.execute();

        String lo = null;
        try {
            lo = cst.get().toString();
        } catch (InterruptedException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        } catch (ExecutionException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }

AsyncTask

public class CityAsyncTask extends AsyncTask<String, String, String> {
    Activity act;
    double latitude;
    double longitude;

    public CityAsyncTask(Activity act, double latitude, double longitude) {
        // TODO Auto-generated constructor stub
        this.act = act;
        this.latitude = latitude;
        this.longitude = longitude;
    }

    @Override
    protected String doInBackground(String... params) {
        String result = "";
        Geocoder geocoder = new Geocoder(act, Locale.getDefault());
        try {
            List<Address> addresses = geocoder.getFromLocation(latitude,
                    longitude, 1);
            Log.e("Addresses", "-->" + addresses);
            result = addresses.get(0).toString();
        } catch (IOException e) {
            e.printStackTrace();
        }
        return result;
    }

    @Override
    protected void onPostExecute(String result) {
        // TODO Auto-generated method stub
        super.onPostExecute(result);

    }
}

7

只要使用这种方法,并通过您的纬度,很长。

public static void getAddress(Context context, double LATITUDE, double LONGITUDE) {

//Set Address
try {
    Geocoder geocoder = new Geocoder(context, Locale.getDefault());
    List<Address> addresses = geocoder.getFromLocation(LATITUDE, LONGITUDE, 1);
    if (addresses != null && addresses.size() > 0) {



        String address = addresses.get(0).getAddressLine(0); // If any additional address line present than only, check with max available address lines by getMaxAddressLineIndex()
        String city = addresses.get(0).getLocality();
        String state = addresses.get(0).getAdminArea();
        String country = addresses.get(0).getCountryName();
        String postalCode = addresses.get(0).getPostalCode();
        String knownName = addresses.get(0).getFeatureName(); // Only if available else return NULL

        Log.d(TAG, "getAddress:  address" + address);
        Log.d(TAG, "getAddress:  city" + city);
        Log.d(TAG, "getAddress:  state" + state);
        Log.d(TAG, "getAddress:  postalCode" + postalCode);
        Log.d(TAG, "getAddress:  knownName" + knownName);

    }
} catch (IOException e) {
    e.printStackTrace();
}
    return;
}

现有答案中尚未添加的内容是什么?
OrangeDog

@OrangeDog带有Try Catch异常的简化方法。这样其他人可以轻松理解它。
Hamza Khan

3
 private class MatchingNearByLocationTask extends
        AsyncTask<Void, Void, Void> 
 {

    @Override
    protected void onPreExecute() {
        super.onPreExecute();
        // Showing progress dialog

        progressDialog = new ProgressDialog(mContext);
        progressDialog.setMessage("Loading...");
        progressDialog.setCancelable(true);
        progressDialog.show();

    }

    @Override
    protected Void doInBackground(Void... arg0) {

        jsonStr = getLocationInfo(Latitude, Longitude).toString();
        if (jsonStr != null) {
            Log.i("location--??", jsonStr);

            JSONObject jsonObj;
            try {
                jsonObj = new JSONObject(jsonStr);

                String Status = jsonObj.getString("status");
                if (Status.equalsIgnoreCase("OK")) {
                    JSONArray Results = jsonObj.getJSONArray("results");
                    JSONObject zero = Results.getJSONObject(0);
                    JSONArray address_components = zero
                            .getJSONArray("address_components");

                    for (int i = 0; i < address_components.length(); i++) {
                        JSONObject zero2 = address_components
                                .getJSONObject(i);
                        String long_name = zero2.getString("long_name");
                        JSONArray mtypes = zero2.getJSONArray("types");
                        String Type = mtypes.getString(0);
                        if (Type.equalsIgnoreCase("administrative_area_level_2")) {
                            // Address2 = Address2 + long_name + ", ";
                            String City = long_name;
                            Log.d(" CityName --->", City + "");
                        }
                    }
                }

            }

            catch (JSONException e) {

                e.printStackTrace();
            }

        }

        return null;
    }

    @Override
    protected void onPostExecute(Void result) {
        super.onPostExecute(result);
        // Dismiss the progress dialog
        if (progressDialog.isShowing()) {
            progressDialog.dismiss();
        }

    }

    @Override
    protected void onCancelled() {

        super.onCancelled();
        progressDialog.dismiss();

    }

}




private JSONObject getLocationInfo(double lat, double lng) {

    HttpGet httpGet = new HttpGet(
            "http://maps.googleapis.com/maps/api/geocode/json?latlng="
                    + lat + "," + lng + "&sensor=false");
    HttpClient client = new DefaultHttpClient();
    HttpResponse response;
    StringBuilder stringBuilder = new StringBuilder();

    try {
        response = client.execute(httpGet);
        HttpEntity entity = response.getEntity();
        InputStream stream = entity.getContent();
        int b;
        while ((b = stream.read()) != -1) {
            stringBuilder.append((char) b);
        }
    } catch (ClientProtocolException e) {
    } catch (IOException e) {
    }

    JSONObject jsonObject = new JSONObject();
    try {
        jsonObject = new JSONObject(stringBuilder.toString());
    } catch (JSONException e) {
        e.printStackTrace();
    }

    return jsonObject;
}

3

试试这个

var geocoder;
geocoder = new google.maps.Geocoder();
var latlng = new google.maps.LatLng(latitude, longitude);

geocoder.geocode(
{'latLng': latlng}, 
function(results, status) {
    if (status == google.maps.GeocoderStatus.OK) {
            if (results[0]) {
                var add= results[0].formatted_address ;
                var  value=add.split(",");

                count=value.length;
                country=value[count-1];
                state=value[count-2];
                city=value[count-3];
                alert("city name is: " + city);
            }
            else  {
                alert("address not found");
            }
    }
     else {
        alert("Geocoder failed due to: " + status);
    }
}

);


1

我找到了解决此问题的新方法。在这里,我已经使用google http服务来获取基于经度和纬度的位置信息。您只需要在url和api密钥中传递纬度和经度(例如:latlng = 21.1497409、79.08747970000002和key =您的API密钥)。这是我在ExampleService课堂上得到的服务

 getService(url) {

    return this.http.get(url).map((data: any) => data.json())

}

您可以将其放置在所需的任何位置,只需在需要位置数据的组件中调用以下服务

this._exampleService.getService("https://maps.googleapis.com/maps/api/geocode/json?latlng=21.1497409, 79.08747970000002&key=YOUR API KEY").subscribe(getplaceData => {
            var placeDataDest: any;
            placeDataDest = getplaceData;
            console.log("i got place id yeee " + placeDataDest['results'][0]['place_id']);
            console.log("i got place details yeee " + placeDataDest['results']);
        });

同样找到城市名称...。希望您会发现这很有用


1

请参考下面的代码

 Geocoder geocoder = new Geocoder(this, Locale.getDefault());
     List<Address> addresses = geocoder.getFromLocation(latitude, longitude, 1);
     String cityName = addresses.get(0).getAddressLine(0);
     String stateName = addresses.get(0).getAddressLine(1);
     String countryName = addresses.get(0).getAddressLine(2);


0
 com.alibaba.fastjson.JSONObject jsonObject = com.alibaba.fastjson.JSONObject.parseObject(data);
        if("OK".equals(jsonObject.getString("status"))){
            String formatted_address;
            JSONArray results = jsonObject.getJSONArray("results");
            if(results != null && results.size() > 0){
                com.alibaba.fastjson.JSONObject object = results.getJSONObject(0);
                String addressComponents = object.getString("address_components");
                formatted_address = object.getString("formatted_address");
                Log.e("amaya","formatted_address="+formatted_address+"--url="+url);
                if(findCity){
                    boolean finded = false;
                    JSONArray ac = JSONArray.parseArray(addressComponents);
                    if(ac != null && ac.size() > 0){
                        for(int i=0;i<ac.size();i++){
                            com.alibaba.fastjson.JSONObject jo = ac.getJSONObject(i);
                            JSONArray types = jo.getJSONArray("types");
                            if(types != null && types.size() > 0){
                                for(int j=0;j<ac.size();j++){
                                    String string = types.getString(i);
                                    if("administrative_area_level_1".equals(string)){
                                        finded = true;
                                        break;
                                    }
                                }
                            }
                            if(finded) break;
                        }
                    }
                    Log.e("amaya","city="+formatted_address);
                }else{
                    Log.e("amaya","poiName="+hotspotPoi.getPoi_name()+"--"+hotspotPoi);
                }
                if(hotspotPoi != null) hotspotPoi.setPoi_name(formatted_address);
                EventBus.getDefault().post(new AmayaEvent.GeoEvent(hotspotPoi));
            }
        }

这是解析Google反馈数据的方法。


0

尝试使用此api:

网址“:http : //maps.googleapis.com/maps/api/geocode/json?latlng=” + String.valueOf(yout_lattitude)+“,” + String.valueOf(your_longitude)


0

工作代码:

addresses = geocoder.getFromLocation(mMap.getCameraPosition().target.latitude, mMap.getCameraPosition().target.longitude, 1); // Here 1 represent max location result to returned, by documents it recommended 1 to 5

                String locality = addresses.get(0).getLocality(); // If any additional address line present than only, check with max available address lines by getMaxAddressLineIndex()
                String subLocality = addresses.get(0).getSubLocality(); // If any additional address line present than only, check with max available address lines by getMaxAddressLineIndex()
                //String address = addresses.get(0).getAddressLine(0); // If any additional address line present than only, check with max available address lines by getMaxAddressLineIndex()
                String address1 = addresses.get(0).getAddressLine(1); // If any additional address line present than only, check with max available address lines by getMaxAddressLineIndex()
                String address2 = addresses.get(0).getAddressLine(2); // If any additional address line present than only, check with max available address lines by getMaxAddressLineIndex()
                String city = addresses.get(0).getLocality();
                String state = addresses.get(0).getAdminArea();
                String country = addresses.get(0).getCountryName();
               // String postalCode = addresses.get(0).getPostalCode();
                String knownName = addresses.get(0).getFeatureName();

0
import org.json.JSONObject

fun parseLocation(response: String): GeoLocation? {

val geoCodes by lazy { doubleArrayOf(0.0, 0.0) }

val jObj = JSONObject(response)
if (jObj.has(KEY_RESULTS)) {

    val jArrResults = jObj.getJSONArray(KEY_RESULTS)
    for (i in 0 until jArrResults.length()) {
        val jObjResult = jArrResults.getJSONObject(i)
        //getting latitude and longitude
        if (jObjResult.has(KEY_GEOMETRY)) {
            val jObjGeometry = jObjResult.getJSONObject(KEY_GEOMETRY)

            if (jObjGeometry.has(KEY_LOCATION)) {
                val jObjLocation = jObjGeometry.getJSONObject(KEY_LOCATION)
                if (jObjLocation.has(KEY_LAT)) {
                    geoCodes[0] = jObjLocation.getDouble(KEY_LAT)
                }

                if (jObjLocation.has(KEY_LNG)) {
                    geoCodes[1] = jObjLocation.getDouble(KEY_LNG)
                }
            }
        }

        var administrativeAreaLevel1: String? = null

        //getting city
        if (jObjResult.has(KEY_ADDRESS_COMPONENTS)) {

            val jArrAddressComponents = jObjResult.getJSONArray(KEY_ADDRESS_COMPONENTS)
            for (i in 0 until jArrAddressComponents.length()) {

                val jObjAddressComponents = jArrAddressComponents.getJSONObject(i)
                if (jObjAddressComponents.has(KEY_TYPES)) {

                    val jArrTypes = jObjAddressComponents.getJSONArray(KEY_TYPES)
                    for (j in 0 until jArrTypes.length()) {

                        when (jArrTypes.getString(j)) {

                            VALUE_LOCALITY, VALUE_POSTAL_TOWN -> {
                                return GeoLocation(jObjAddressComponents.getString(KEY_LONG_NAME), *geoCodes)
                            }

                            ADMINISTRATIVE_AREA_LEVEL_1 -> {
                                administrativeAreaLevel1 = jObjAddressComponents.getString(KEY_LONG_NAME)
                            }

                            else -> {
                            }
                        }
                    }
                }
            }

            for (i in 0 until jArrAddressComponents.length()) {

                val jObjAddressComponents = jArrAddressComponents.getJSONObject(i)
                if (jObjAddressComponents.has(KEY_TYPES)) {

                    val jArrTypes = jObjAddressComponents.getJSONArray(KEY_TYPES)

                    val typeList = ArrayList<String>()
                    for (j in 0 until jArrTypes.length()) {
                        typeList.add(jArrTypes.getString(j))
                    }

                    if (typeList.contains(VALUE_SUBLOCALITY)) {
                        var hasSubLocalityLevel = false
                        typeList.forEach { type ->
                            if (type.contains(VALUE_SUBLOCALITY_LEVEL)) {
                                hasSubLocalityLevel = true

                                if (type == VALUE_SUBLOCALITY_LEVEL_1) {
                                    return GeoLocation(jObjAddressComponents.getString(KEY_LONG_NAME), *geoCodes)
                                }
                            }
                        }
                        if (!hasSubLocalityLevel) {
                            return GeoLocation(jObjAddressComponents.getString(KEY_LONG_NAME), *geoCodes)
                        }
                    }
                }
            }
        }

        if (geoCodes.isNotEmpty()) return GeoLocation(administrativeAreaLevel1, geoCodes = *geoCodes)
     }
   }
return null
}

data class GeoLocation(val latitude: Double = 0.0, val longitude: Double = 0.0, val city: String? = null) : Parcelable {

constructor(city: String? = null, vararg geoCodes: Double) : this(geoCodes[0], geoCodes[1], city)

constructor(source: Parcel) : this(source.readDouble(), source.readDouble(), source.readString())

companion object {
    @JvmField
    val CREATOR = object : Parcelable.Creator<GeoLocation> {

        override fun createFromParcel(source: Parcel) = GeoLocation(source)

        override fun newArray(size: Int): Array<GeoLocation?> = arrayOfNulls(size)
    }
}

override fun writeToParcel(dest: Parcel, flags: Int) {
    dest.writeDouble(latitude)
    dest.writeDouble(longitude)
    dest.writeString(city)
}

override fun describeContents() = 0
}

0

我在巴西。由于地区的细节,这座城市有时以不同的方式出现。我认为在印度和其他国家也是如此。因此,为防止错误,我进行了以下验证:

private fun getAddress(latLng: LatLng): String {
    // 1
    val geocoder = Geocoder(this)
    val addresses: List<Address>?
    var city = "no"

    try {

        addresses = geocoder.getFromLocation(latLng.latitude, latLng.longitude, 1)

        if (null != addresses && !addresses.isEmpty()) { //prevent from error
             //sometimes the city comes in locality, sometimes in subAdminArea.
            if (addresses[0].locality == null) {

                city = addresses[0].subAdminArea
            } else {
                city = addresses[0].locality
            }

            }
    } catch (e: IOException) {
        Log.e("MapsActivity", e.localizedMessage)
    }

    return city
    }

您还可以检查城市是否返回“否”。如果是这样,就不可能获得用户位置。希望能帮助到你。

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