Answers:
使用Swift时,您可以使用enum
UIUserInterfaceIdiom
,定义为:
enum UIUserInterfaceIdiom : Int {
case unspecified
case phone // iPhone and iPod touch style UI
case pad // iPad style UI (also includes macOS Catalyst)
}
因此,您可以将其用作:
UIDevice.current.userInterfaceIdiom == .pad
UIDevice.current.userInterfaceIdiom == .phone
UIDevice.current.userInterfaceIdiom == .unspecified
或使用Switch语句:
switch UIDevice.current.userInterfaceIdiom {
case .phone:
// It's an iPhone
case .pad:
// It's an iPad (or macOS Catalyst)
case .unspecified:
// Uh, oh! What could it be?
}
UI_USER_INTERFACE_IDIOM()
是一个Objective-C宏,定义为:
#define UI_USER_INTERFACE_IDIOM() \ ([[UIDevice currentDevice] respondsToSelector:@selector(userInterfaceIdiom)] ? \ [[UIDevice currentDevice] userInterfaceIdiom] : \ UIUserInterfaceIdiomPhone)
另外,请注意,即使在使用Objective-C时,UI_USER_INTERFACE_IDIOM()
也仅在定位iOS 3.2及更低版本时才需要该宏。部署到iOS 3.2及更高版本时,可以[UIDevice userInterfaceIdiom]
直接使用。
UIDevice.currentDevice().userInterfaceIdiom
成为UIDevice.current.userInterfaceIdiom
您应该使用此GBDeviceInfo框架或...
苹果对此进行了定义:
public enum UIUserInterfaceIdiom : Int {
case unspecified
case phone // iPhone and iPod touch style UI
case pad // iPad style UI
@available(iOS 9.0, *)
case tv // Apple TV style UI
@available(iOS 9.0, *)
case carPlay // CarPlay style UI
}
因此对于设备的严格定义可以使用此代码
struct ScreenSize
{
static let SCREEN_WIDTH = UIScreen.main.bounds.size.width
static let SCREEN_HEIGHT = UIScreen.main.bounds.size.height
static let SCREEN_MAX_LENGTH = max(ScreenSize.SCREEN_WIDTH, ScreenSize.SCREEN_HEIGHT)
static let SCREEN_MIN_LENGTH = min(ScreenSize.SCREEN_WIDTH, ScreenSize.SCREEN_HEIGHT)
}
struct DeviceType
{
static let IS_IPHONE_4_OR_LESS = UIDevice.current.userInterfaceIdiom == .phone && ScreenSize.SCREEN_MAX_LENGTH < 568.0
static let IS_IPHONE_5 = UIDevice.current.userInterfaceIdiom == .phone && ScreenSize.SCREEN_MAX_LENGTH == 568.0
static let IS_IPHONE_6_7 = UIDevice.current.userInterfaceIdiom == .phone && ScreenSize.SCREEN_MAX_LENGTH == 667.0
static let IS_IPHONE_6P_7P = UIDevice.current.userInterfaceIdiom == .phone && ScreenSize.SCREEN_MAX_LENGTH == 736.0
static let IS_IPAD = UIDevice.current.userInterfaceIdiom == .pad && ScreenSize.SCREEN_MAX_LENGTH == 1024.0
static let IS_IPAD_PRO = UIDevice.current.userInterfaceIdiom == .pad && ScreenSize.SCREEN_MAX_LENGTH == 1366.0
}
如何使用
if DeviceType.IS_IPHONE_6P_7P {
print("IS_IPHONE_6P_7P")
}
检测iOS版本
struct Version{
static let SYS_VERSION_FLOAT = (UIDevice.current.systemVersion as NSString).floatValue
static let iOS7 = (Version.SYS_VERSION_FLOAT < 8.0 && Version.SYS_VERSION_FLOAT >= 7.0)
static let iOS8 = (Version.SYS_VERSION_FLOAT >= 8.0 && Version.SYS_VERSION_FLOAT < 9.0)
static let iOS9 = (Version.SYS_VERSION_FLOAT >= 9.0 && Version.SYS_VERSION_FLOAT < 10.0)
}
如何使用
if Version.iOS8 {
print("iOS8")
}
struct ScreenSize/DeviceType
这种方法,因为它可以在Simulator中使用
Swift 2.0和iOS 9和Xcode 7.1
// 1. request an UITraitCollection instance
let deviceIdiom = UIScreen.mainScreen().traitCollection.userInterfaceIdiom
// 2. check the idiom
switch (deviceIdiom) {
case .Pad:
print("iPad style UI")
case .Phone:
print("iPhone and iPod touch style UI")
case .TV:
print("tvOS style UI")
default:
print("Unspecified UI idiom")
}
Swift 3.0和Swift 4.0
// 1. request an UITraitCollection instance
let deviceIdiom = UIScreen.main.traitCollection.userInterfaceIdiom
// 2. check the idiom
switch (deviceIdiom) {
case .pad:
print("iPad style UI")
case .phone:
print("iPhone and iPod touch style UI")
case .tv:
print("tvOS style UI")
default:
print("Unspecified UI idiom")
}
使用UITraitCollection。通过UITraitEnvironment协议的traitCollection属性公开了iOS trait环境。以下类别采用了此协议:
如果/其他情况:
if (UIDevice.currentDevice().userInterfaceIdiom == UIUserInterfaceIdiom.Pad)
{
// Ipad
}
else
{
// Iphone
}
我这样做:
UIDevice.current.model
它显示设备的名称。
要检查是iPad还是iPhone:
if ( UIDevice.current.model.range(of: "iPad") != nil){
print("I AM IPAD")
} else {
print("I AM IPHONE")
}
Swift 2.x:
添加到Beslav Turalov答案是新入门的iPad Pro可以很容易地找到这一行
检测iPad Pro
struct DeviceType
{
...
static let IS_IPAD_PRO = UIDevice.currentDevice().userInterfaceIdiom == .Pad && ScreenSize.SCREEN_MAX_LENGTH == 1366.0
}
struct ScreenSize
{
static let SCREEN_WIDTH = UIScreen.main.bounds.size.width
static let SCREEN_HEIGHT = UIScreen.main.bounds.size.height
static let SCREEN_MAX_LENGTH = max(ScreenSize.SCREEN_WIDTH, ScreenSize.SCREEN_HEIGHT)
static let SCREEN_MIN_LENGTH = min(ScreenSize.SCREEN_WIDTH, ScreenSize.SCREEN_HEIGHT)
}
struct DeviceType
{
static let IS_IPHONE = UIDevice.current.userInterfaceIdiom == .phone
static let IS_IPHONE_4_OR_LESS = UIDevice.current.userInterfaceIdiom == .phone && ScreenSize.SCREEN_MAX_LENGTH < 568.0
static let IS_IPHONE_5 = UIDevice.current.userInterfaceIdiom == .phone && ScreenSize.SCREEN_MAX_LENGTH == 568.0
static let IS_IPHONE_6 = UIDevice.current.userInterfaceIdiom == .phone && ScreenSize.SCREEN_MAX_LENGTH == 667.0
static let IS_IPHONE_6P = UIDevice.current.userInterfaceIdiom == .phone && ScreenSize.SCREEN_MAX_LENGTH == 736.0
static let IS_IPHONE_7 = IS_IPHONE_6
static let IS_IPHONE_7P = IS_IPHONE_6P
static let IS_IPAD = UIDevice.current.userInterfaceIdiom == .pad && ScreenSize.SCREEN_MAX_LENGTH == 1024.0
static let IS_IPAD_PRO_9_7 = IS_IPAD
static let IS_IPAD_PRO_12_9 = UIDevice.current.userInterfaceIdiom == .pad && ScreenSize.SCREEN_MAX_LENGTH == 1366.0
static let IS_TV = UIDevice.current.userInterfaceIdiom == .tv
static let IS_CAR_PLAY = UIDevice.current.userInterfaceIdiom == .carPlay
}
struct Version{
static let SYS_VERSION_FLOAT = (UIDevice.current.systemVersion as NSString).floatValue
static let iOS7 = (Version.SYS_VERSION_FLOAT < 8.0 && Version.SYS_VERSION_FLOAT >= 7.0)
static let iOS8 = (Version.SYS_VERSION_FLOAT >= 8.0 && Version.SYS_VERSION_FLOAT < 9.0)
static let iOS9 = (Version.SYS_VERSION_FLOAT >= 9.0 && Version.SYS_VERSION_FLOAT < 10.0)
static let iOS10 = (Version.SYS_VERSION_FLOAT >= 10.0 && Version.SYS_VERSION_FLOAT < 11.0)
}
用法:
if DeviceType.IS_IPHONE_7P { print("iPhone 7 plus") }
if DeviceType.IS_IPAD_PRO_9_7 && Version.iOS10 { print("iPad pro 9.7 with iOS 10 version") }
尝试添加如下扩展名:
public extension UIDevice {
var modelName: String {
var systemInfo = utsname()
uname(&systemInfo)
let machineMirror = Mirror(reflecting: systemInfo.machine)
let identifier = machineMirror.children.reduce("") { identifier, element in
guard let value = element.value as? Int8 where value != 0 else { return identifier }
return identifier + String(UnicodeScalar(UInt8(value)))
}
switch identifier {
case "iPod5,1": return "iPod Touch 5"
case "iPod7,1": return "iPod Touch 6"
case "iPhone3,1", "iPhone3,2", "iPhone3,3": return "iPhone 4"
case "iPhone4,1": return "iPhone 4s"
case "iPhone5,1", "iPhone5,2": return "iPhone 5"
case "iPhone5,3", "iPhone5,4": return "iPhone 5c"
case "iPhone6,1", "iPhone6,2": return "iPhone 5s"
case "iPhone7,2": return "iPhone 6"
case "iPhone7,1": return "iPhone 6 Plus"
case "iPhone8,1": return "iPhone 6s"
case "iPhone8,2": return "iPhone 6s Plus"
case "iPhone9,1", "iPhone9,3": return "iPhone 7"
case "iPhone9,2", "iPhone9,4": return "iPhone 7 Plus"
case "iPhone8,4": return "iPhone SE"
case "iPad2,1", "iPad2,2", "iPad2,3", "iPad2,4":return "iPad 2"
case "iPad3,1", "iPad3,2", "iPad3,3": return "iPad 3"
case "iPad3,4", "iPad3,5", "iPad3,6": return "iPad 4"
case "iPad4,1", "iPad4,2", "iPad4,3": return "iPad Air"
case "iPad5,3", "iPad5,4": return "iPad Air 2"
case "iPad2,5", "iPad2,6", "iPad2,7": return "iPad Mini"
case "iPad4,4", "iPad4,5", "iPad4,6": return "iPad Mini 2"
case "iPad4,7", "iPad4,8", "iPad4,9": return "iPad Mini 3"
case "iPad5,1", "iPad5,2": return "iPad Mini 4"
case "iPad6,3", "iPad6,4", "iPad6,7", "iPad6,8":return "iPad Pro"
case "AppleTV5,3": return "Apple TV"
case "i386", "x86_64": return "Simulator"
default: return identifier
}
}
}
这是您将如何使用它:
let modelName = UIDevice.currentDevice().modelName
编辑 对于模拟器,您可以在此处尝试解决方案
Swift 4.2扩展
public extension UIDevice {
class var isPhone: Bool {
return UIDevice.current.userInterfaceIdiom == .phone
}
class var isPad: Bool {
return UIDevice.current.userInterfaceIdiom == .pad
}
class var isTV: Bool {
return UIDevice.current.userInterfaceIdiom == .tv
}
class var isCarPlay: Bool {
return UIDevice.current.userInterfaceIdiom == .carPlay
}
}
用法
if UIDevice.isPad {
// Do something
}
谢谢大家的支持:))
UIDevice + Extensions.swift
import Foundation
import UIKit
extension UIDevice {
static let modelName: String = {
var systemInfo = utsname()
uname(&systemInfo)
let machineMirror = Mirror(reflecting: systemInfo.machine)
let identifier = machineMirror.children.reduce("") { identifier, element in
guard let value = element.value as? Int8, value != 0 else { return identifier }
return identifier + String(UnicodeScalar(UInt8(value)))
}
func mapToDevice(identifier: String) -> String { // swiftlint:disable:this cyclomatic_complexity
#if os(iOS)
switch identifier {
case "iPod5,1": return "iPod Touch 5"
case "iPod7,1": return "iPod Touch 6"
case "iPhone3,1", "iPhone3,2", "iPhone3,3": return "iPhone 4"
case "iPhone4,1": return "iPhone 4s"
case "iPhone5,1", "iPhone5,2": return "iPhone 5"
case "iPhone5,3", "iPhone5,4": return "iPhone 5c"
case "iPhone6,1", "iPhone6,2": return "iPhone 5s"
case "iPhone7,2": return "iPhone 6"
case "iPhone7,1": return "iPhone 6 Plus"
case "iPhone8,1": return "iPhone 6s"
case "iPhone8,2": return "iPhone 6s Plus"
case "iPhone9,1", "iPhone9,3": return "iPhone 7"
case "iPhone9,2", "iPhone9,4": return "iPhone 7 Plus"
case "iPhone8,4": return "iPhone SE"
case "iPhone10,1", "iPhone10,4": return "iPhone 8"
case "iPhone10,2", "iPhone10,5": return "iPhone 8 Plus"
case "iPhone10,3", "iPhone10,6": return "iPhone X"
case "iPhone11,2": return "iPhone XS"
case "iPhone11,4", "iPhone11,6": return "iPhone XS Max"
case "iPhone11,8": return "iPhone XR"
case "iPad2,1", "iPad2,2", "iPad2,3", "iPad2,4":return "iPad 2"
case "iPad3,1", "iPad3,2", "iPad3,3": return "iPad 3"
case "iPad3,4", "iPad3,5", "iPad3,6": return "iPad 4"
case "iPad4,1", "iPad4,2", "iPad4,3": return "iPad Air"
case "iPad5,3", "iPad5,4": return "iPad Air 2"
case "iPad6,11", "iPad6,12": return "iPad 5"
case "iPad7,5", "iPad7,6": return "iPad 6"
case "iPad2,5", "iPad2,6", "iPad2,7": return "iPad Mini"
case "iPad4,4", "iPad4,5", "iPad4,6": return "iPad Mini 2"
case "iPad4,7", "iPad4,8", "iPad4,9": return "iPad Mini 3"
case "iPad5,1", "iPad5,2": return "iPad Mini 4"
case "iPad6,3", "iPad6,4": return "iPad Pro 9.7 Inch"
case "iPad6,7", "iPad6,8": return "iPad Pro 12.9 Inch"
case "iPad7,1", "iPad7,2": return "iPad Pro 12.9 Inch 2. Generation"
case "iPad7,3", "iPad7,4": return "iPad Pro 10.5 Inch"
case "AppleTV5,3": return "Apple TV"
case "AppleTV6,2": return "Apple TV 4K"
case "AudioAccessory1,1": return "HomePod"
case "i386", "x86_64": return "Simulator \(mapToDevice(identifier: ProcessInfo().environment["SIMULATOR_MODEL_IDENTIFIER"] ?? "iOS"))"
default: return identifier
}
#elseif os(tvOS)
switch identifier {
case "AppleTV5,3": return "Apple TV 4"
case "AppleTV6,2": return "Apple TV 4K"
case "i386", "x86_64": return "Simulator \(mapToDevice(identifier: ProcessInfo().environment["SIMULATOR_MODEL_IDENTIFIER"] ?? "tvOS"))"
default: return identifier
}
#endif
}
return mapToDevice(identifier: identifier)
}()
}
enum DeviceName: String {
case iPod_Touch_5 = "iPod Touch 5"
case pod_Touch_6 = "Pod Touch 6"
case iPhone_4 = "iPhone 4"
case iPhone_4s = "iPhone 4s"
case iPhone_5 = "iPhone 5"
case iPhone_5c = "iPhone 5c"
case iPhone_5s = "iPhone 5s"
case iPhone_6 = "iPhone 6"
case iPhone_6_Plus = "iPhone 6 Plus"
case iPhone_6s = "iPhone 6s"
case iPhone_6s_Plus = "iPhone 6s Plus"
case iPhone_7 = "iPhone 7"
case iPhone_7_Plus = "iPhone 7 Plus"
case iPhone_SE = "iPhone SE"
case iPhone_8 = "iPhone 8"
case iPhone_8_Plus = "iPhone 8 Plus"
case iPhone_X = "iPhone X"
case iPhone_XS = "iPhone XS"
case iPhone_XS_Max = "iPhone XS Max"
case iPhone_XR = "iPhone XR"
case iPad_2 = "iPad 2"
case iPad_3 = "iPad 3"
case iPad_4 = "iPad 4"
case iPad_Air = "iPad Air"
case iPad_Air_2 = "iPad Air 2"
case iPad_5 = "iPad 5"
case iPad_6 = "iPad 6"
case iPad_Mini = "iPad Mini"
case iPad_Mini_2 = "iPad Mini 2"
case iPad_Mini_3 = "iPad Mini 3"
case iPad_Mini_4 = "iPad Mini 4"
case iPad_Pro_9_7_Inch = "iPad Pro 9.7 Inch"
case iPad_Pro_12_9_Inch = "iPad Pro 12.9 Inch"
case iPad_Pro_12_9_Inch_2_Generation = "iPad Pro 12.9 Inch 2. Generation"
case iPad_Pro_10_5_Inch = "iPad Pro 10.5 Inch"
case apple_TV = "Apple TV"
case apple_TV_4K = "Apple TV 4K"
case homePod = "HomePod"
}
SharedFunctions.swift
import Foundation
import UIKit
func isDevice(_ name: DeviceName) -> Bool {
let modelName = UIDevice.modelName.replacingOccurrences(of: "Simulator", with: "").trimmed()
if name.rawValue == modelName {
return true
}
return false
}
String + Whitespace.swift
import Foundation
extension String {
public func trimmed() -> String {
return self.trimmingCharacters(in: .whitespacesAndNewlines)
}
}
尝试以下操作以检查当前设备是iPhone还是iPad:
迅捷5
struct Device {
static let IS_IPAD = UIDevice.current.userInterfaceIdiom == .pad
static let IS_IPHONE = UIDevice.current.userInterfaceIdiom == .phone
}
用:
if(Device.IS_IPHONE){
// device is iPhone
}if(Device.IS_IPAD){
// device is iPad (or a Mac running under macOS Catalyst)
}else{
// other
}
Swift 2.0和iOS 7 + / iOS 8 + / iOS 9+
public class Helper {
public class var isIpad:Bool {
if #available(iOS 8.0, *) {
return UIScreen.mainScreen().traitCollection.userInterfaceIdiom == .Pad
} else {
return UIDevice.currentDevice().userInterfaceIdiom == .Pad
}
}
public class var isIphone:Bool {
if #available(iOS 8.0, *) {
return UIScreen.mainScreen().traitCollection.userInterfaceIdiom == .Phone
} else {
return UIDevice.currentDevice().userInterfaceIdiom == .Phone
}
}
}
用 :
if Helper.isIpad {
}
要么
guard Helper.isIpad else {
return
}
谢谢@ user3378170
仅供参考,我已经使用 UI_USER_INTERFACE_IDIOM()
了我用Swift编写的应用程序。该应用程序可以使用XCode 6.3.1很好地编译,而无需对该命令发出任何警告,并且可以在Simulator(使用任何选定的设备)上以及在我的所有实际设备(iPhone,iPad)(iOS版本为7.1至8.3)上良好运行。
但是,该应用在苹果审阅者的设备上崩溃了(并被拒绝)。我花了几天的时间才发现问题,而又没有再将其重新上传到iTunes Connect。
现在我UIDevice.currentDevice().userInterfaceIdiom
改用了,我的应用程序可以在这种崩溃中幸存下来。
如果要检查当前设备是iPad还是iPhone,则可以使用以下代码行:
if(UIDevice.currentDevice().userInterfaceIdiom == .Pad){
}else if(UIDevice.currentDevice().userInterfaceIdiom == .Phone){
}
对上述答案做了几处补充,以便您返回类型而不是字符串值。
我认为这主要用于UI调整,因此我认为包括所有子模型(例如iPhone 5s)并不重要,但是可以通过在isDevice Array中添加模型测试来轻松扩展它
经过测试,可以在带有物理和模拟器设备的Swift 3.1 Xcode 8.3.2中工作
实现方式:
UIDevice.whichDevice()
public enum SVNDevice {
case isiPhone4, isIphone5, isIphone6or7, isIphone6por7p, isIphone, isIpad, isIpadPro
}
extension UIDevice {
class func whichDevice() -> SVNDevice? {
let isDevice = { (comparision: Array<(Bool, SVNDevice)>) -> SVNDevice? in
var device: SVNDevice?
comparision.forEach({
device = $0.0 ? $0.1 : device
})
return device
}
return isDevice([
(UIDevice.current.userInterfaceIdiom == .phone && ScreenSize.SCREEN_MAX_LENGTH < 568.0, SVNDevice.isiPhone4),
(UIDevice.current.userInterfaceIdiom == .phone && ScreenSize.SCREEN_MAX_LENGTH == 568.0, SVNDevice.isIphone5),
(UIDevice.current.userInterfaceIdiom == .phone && ScreenSize.SCREEN_MAX_LENGTH == 667.0, SVNDevice.isIphone6or7),
(UIDevice.current.userInterfaceIdiom == .phone && ScreenSize.SCREEN_MAX_LENGTH == 736.0, SVNDevice.isIphone6por7p),
(UIDevice.current.userInterfaceIdiom == .pad && ScreenSize.SCREEN_MAX_LENGTH == 1024.0, SVNDevice.isIpad),
(UIDevice.current.userInterfaceIdiom == .pad && ScreenSize.SCREEN_MAX_LENGTH == 1366.0, SVNDevice.isIpadPro)])
}
}
private struct ScreenSize {
static let SCREEN_WIDTH = UIScreen.main.bounds.size.width
static let SCREEN_HEIGHT = UIScreen.main.bounds.size.height
static let SCREEN_MAX_LENGTH = max(ScreenSize.SCREEN_WIDTH, ScreenSize.SCREEN_HEIGHT)
static let SCREEN_MIN_LENGTH = min(ScreenSize.SCREEN_WIDTH, ScreenSize.SCREEN_HEIGHT)
}
我创建了一个名为SVNBootstaper的框架,其中包括此框架和其他一些辅助协议,该协议是公开的,可以通过迦太基获得。
if UIDevice.currentDevice().userInterfaceIdiom == .Pad