如何获取设备的宽度和高度？

在Objective-C中，我们可以使用以下代码获取设备的宽度和高度：

CGRect sizeRect = [UIScreen mainScreen].applicationFrame
float width = sizeRect.size.width
float height = sizeRect.size.height

Swift如何做到这一点？

我没有尝试过，但是应该。

var bounds = UIScreen.main.bounds
var width = bounds.size.width
var height = bounds.size.height

斯威夫特4.2

let screenBounds = UIScreen.main.bounds
let width = screenBounds.width
let height = screenBounds.height

@Houssni的答案是正确的，但是由于我们在谈论Swift，并且这种用例经常出现，因此可以考虑扩展CGRect类似于以下内容：

extension CGRect {
    var wh: (w: CGFloat, h: CGFloat) {
        return (size.width, size.height)
    }
}

然后，您可以像这样使用它：

let (width, height) = UIScreen.mainScreen().applicationFrame.wh

万岁！:)

如果要在代码中使用它。干得好。

func iPhoneScreenSizes() {
    let bounds = UIScreen.main.bounds
    let height = bounds.size.height

    switch height {
    case 480.0:
        print("iPhone 3,4")
    case 568.0:
        print("iPhone 5")
    case 667.0:
        print("iPhone 6")
    case 736.0:
        print("iPhone 6+")
    case 812.0:
        print("iPhone X")
        print("iPhone XS")
        break
    case 896.0:
        print("iPhone XR")
        print("iPhone XS Max")
        break
    default:
        print("not an iPhone")

    }
}

var sizeRect = UIScreen.mainScreen().applicationFrame
var width    = sizeRect.size.width
var height   = sizeRect.size.height

正是这样，也对其进行了测试。

（快速3）请记住，大多数宽度和高度值将基于设备的当前方向。如果您想要一个不基于旋转的一致值，并且可以像纵向旋转那样提供结果，请尝试fixedCoordinateSpace：

let screenSize = UIScreen.main.fixedCoordinateSpace.bounds

由于您要查找设备的屏幕尺寸，最简单的方法是：

let screenSize = UIScreen.mainScreen().bounds.size
let width = screenSize.width
let height = screenSize.height

@Adam Smaka的答案很接近，而在Swift 3中，它是以下内容：

let screenBounds = UIScreen.main.bounds
let width = screenBounds.width
let height = screenBounds.height

UIScreen对象定义与基于硬件的显示关联的属性。iOS设备有一个主屏幕和零个或多个附加屏幕。每个屏幕对象都为关联的显示和其他有趣的属性定义了边界矩形

Apple Doc URL：

https://developer.apple.com/reference/uikit/uiwindow/1621597-screen

快速获取您用户设备的高度/宽度

let screenHeight = UIScreen.main.bounds.height
let screenWidth = UIScreen.main.bounds.width

 static func getDeviceType() -> String
    {
        var strDeviceType = ""
        if UIDevice().userInterfaceIdiom == .phone {
            switch UIScreen.main.nativeBounds.height {
            case 1136:
                strDeviceType = "iPhone 5 or 5S or 5C"
            case 1334:
                strDeviceType = "iPhone 6/6S/7/8"
            case 1920, 2208:
                strDeviceType = "iPhone 6+/6S+/7+/8+"
            case 2436:
                strDeviceType = "iPhone X"
            case 2688:
                strDeviceType = "iPhone Xs Max"
            case 1792:
                strDeviceType = "iPhone Xr"
            default:
                strDeviceType = "unknown"
            }
        }
        return strDeviceType
    }

在Swift 4中，我不得不使用NSScreen.main？.deviceDescription

let deviceDescription = NSScreen.main?.deviceDescription          
let screenSize = deviceDescription![.size]
let screenHeight = (screenSize as! NSSize).height

这非常适合Xcode 12

func iPhoneScreenSizes() {
        let height = UIScreen.main.bounds.size.height
        switch height {
        case 480.0:
            print("iPhone 3,4")
        case 568.0:
            print("iPhone 5 | iPod touch(7th gen)")
        case 667.0:
            print("iPhone 6 | iPhone SE(2nd gen) | iPhone 8")
        case 736.0:
            print("iPhone 6+ | iPhone 8+")
        case 812.0:
            print("iPhone X | iPhone XS | iPhone 11 Pro")
        case 896.0:
            print("iPhone XR | iPhone XS Max | iPhone 11 | iPhone 11 Pro Max")
        default:
            print("not an iPhone")
        }
    }