我喜欢从将您的视图嵌入到NET中继承的滑动包UINavigationController。不幸的是，我似乎找不到隐藏它的方法，NavigationBar但仍然可以向后滑动触摸板gesture。我可以编写自定义手势，但我不希望这样做，而是依靠UINavigationController向后滑动gesture。

如果我在情节提要图中取消选中，则后向滑动不起作用

或者，如果我以编程方式将其隐藏，则采用相同的方案。

- (void)viewDidLoad
{
    [super viewDidLoad];
    [self.navigationController setNavigationBarHidden:YES animated:NO]; // and animated:YES
}

有没有办法隐藏顶部NavigationBar并仍然可以滑动？

正在工作的黑客攻击是在设定interactivePopGestureRecognizer的的委托UINavigationController，以nil这样的：

[self.navigationController.interactivePopGestureRecognizer setDelegate:nil];

但是在某些情况下，它可能会产生奇怪的效果。

其他方法的问题

设置interactivePopGestureRecognizer.delegate = nil具有意外的副作用。

设置navigationController?.navigationBar.hidden = true确实有效，但不允许您隐藏导航栏中的更改。

最后，通常最好的做法是UIGestureRecognizerDelegate为导航控制器创建模型对象。将其设置为UINavigationController堆栈中的控制器是导致EXC_BAD_ACCESS错误的原因。

完整解决方案

首先，将此类添加到您的项目中：

class InteractivePopRecognizer: NSObject, UIGestureRecognizerDelegate {

    var navigationController: UINavigationController

    init(controller: UINavigationController) {
        self.navigationController = controller
    }

    func gestureRecognizerShouldBegin(_ gestureRecognizer: UIGestureRecognizer) -> Bool {
        return navigationController.viewControllers.count > 1
    }

    // This is necessary because without it, subviews of your top controller can
    // cancel out your gesture recognizer on the edge.
    func gestureRecognizer(_ gestureRecognizer: UIGestureRecognizer, shouldRecognizeSimultaneouslyWith otherGestureRecognizer: UIGestureRecognizer) -> Bool {
        return true
    }
}

然后，将导航控制器设置interactivePopGestureRecognizer.delegate为新InteractivePopRecognizer类的实例。

var popRecognizer: InteractivePopRecognizer?

override func viewDidLoad() {
    super.viewDidLoad()
    setInteractiveRecognizer()
}

private func setInteractiveRecognizer() {
    guard let controller = navigationController else { return }
    popRecognizer = InteractivePopRecognizer(controller: controller)
    controller.interactivePopGestureRecognizer?.delegate = popRecognizer
}

享受一个无副作用的隐藏导航栏，即使您的顶级控制器具有表，集合或滚动视图子视图，该导航栏也可以使用。

就我而言，以防止产生奇怪的影响

根视图控制器

override func viewDidLoad() {
    super.viewDidLoad()

    // Enable swipe back when no navigation bar
    navigationController?.interactivePopGestureRecognizer?.delegate = self 

}


func gestureRecognizerShouldBegin(_ gestureRecognizer: UIGestureRecognizer) -> Bool {
    if(navigationController!.viewControllers.count > 1){
        return true
    }
    return false
}

http://www.gampood.com/pop-viewcontroller-with-out-navigation-bar/

更新于iOS 13.4

iOS 13.4打破了以前的解决方案，因此事情变得很丑陋。看起来在iOS 13.4中，此行为现在由私有方法控制_gestureRecognizer:shouldReceiveEvent:（不要与shouldReceiveiOS 13.4中添加的新public方法混淆）。

我发现其他发布的解决方案会覆盖该委托，或者将其设置为nil会导致某些意外行为。

就我而言，当我位于导航堆栈的顶部并尝试使用该手势再弹出一个时，它将失败（如预期的那样），但是随后尝试推入堆栈将开始在导航栏中引起奇怪的图形故障导航栏。这是有道理的，因为在隐藏导航栏并抛出所有其他行为时，委托不仅用于处理是否阻止手势识别，还用于处理委托。

根据我的测试，似乎gestureRecognizer(_:, shouldReceiveTouch:)是原始委托人正在实施的用于隐藏手势的方法，该方法在隐藏导航栏时阻止其被识别，而不是gestureRecognizerShouldBegin(_:)。gestureRecognizerShouldBegin(_:)由于缺少的实现而在其委托工作中实现的其他解决方案gestureRecognizer(_:, shouldReceiveTouch:)将导致接收所有触摸的默认行为。

@Nathan Perry的解决方案已接近尾声，但是如果没有实现respondsToSelector(_:)，则将消息发送到委托的UIKit代码将认为没有任何其他委托方法的实现，并且forwardingTargetForSelector(_:)将永远不会被调用。

因此，在我们要修改行为的一种特定情况下，我们控制“ gestureRecognizer（_ :, shouldReceiveTouch :)”，否则将其他所有内容转发给委托。

class AlwaysPoppableNavigationController : UINavigationController {

    private var alwaysPoppableDelegate: AlwaysPoppableDelegate!

    override func viewDidLoad() {
        super.viewDidLoad()

        self.alwaysPoppableDelegate = AlwaysPoppableDelegate(navigationController: self, originalDelegate: self.interactivePopGestureRecognizer!.delegate!)
        self.interactivePopGestureRecognizer!.delegate = self.alwaysPoppableDelegate
    }
}

private class AlwaysPoppableDelegate : NSObject, UIGestureRecognizerDelegate {

    weak var navigationController: AlwaysPoppableNavigationController?
    weak var originalDelegate: UIGestureRecognizerDelegate?

    init(navigationController: AlwaysPoppableNavigationController, originalDelegate: UIGestureRecognizerDelegate) {
        self.navigationController = navigationController
        self.originalDelegate = originalDelegate
    }

    // For handling iOS before 13.4
    @objc func gestureRecognizer(_ gestureRecognizer: UIGestureRecognizer, shouldReceive touch: UITouch) -> Bool {
        if let navigationController = navigationController, navigationController.isNavigationBarHidden && navigationController.viewControllers.count > 1 {
            return true
        }
        else if let originalDelegate = originalDelegate {
            return originalDelegate.gestureRecognizer!(gestureRecognizer, shouldReceive: touch)
        }
        else {
            return false
        }
    }

    // For handling iOS 13.4+
    @objc func _gestureRecognizer(_ gestureRecognizer: UIGestureRecognizer, shouldReceiveEvent event: UIEvent) -> Bool {
        if let navigationController = navigationController, navigationController.isNavigationBarHidden && navigationController.viewControllers.count > 1 {
            return true
        }
        else if let originalDelegate = originalDelegate {
            let selector = #selector(_gestureRecognizer(_:shouldReceiveEvent:))
            if originalDelegate.responds(to: selector) {
                let result = originalDelegate.perform(selector, with: gestureRecognizer, with: event)
                return result != nil
            }
        }

        return false
    }

    override func responds(to aSelector: Selector) -> Bool {
        if #available(iOS 13.4, *) {
            // iOS 13.4+ does not need to override responds(to:) behavior, it only uses forwardingTarget
            return originalDelegate?.responds(to: aSelector) ?? false
        }
        else {
            if aSelector == #selector(gestureRecognizer(_:shouldReceive:)) {
                return true
            }
            else {
                return originalDelegate?.responds(to: aSelector) ?? false
            }
        }
    }

    override func forwardingTarget(for aSelector: Selector) -> Any? {
        if #available(iOS 13.4, *), aSelector == #selector(_gestureRecognizer(_:shouldReceiveEvent:)) {
            return nil
        }
        else {
            return self.originalDelegate
        }
    }
}

您可以如下子类化UINavigationController：

@interface CustomNavigationController : UINavigationController<UIGestureRecognizerDelegate>

@end

实现方式：

@implementation CustomNavigationController

- (void)setNavigationBarHidden:(BOOL)hidden animated:(BOOL)animated {
    [super setNavigationBarHidden:hidden animated:animated];
    self.interactivePopGestureRecognizer.delegate = self;
}

- (BOOL)gestureRecognizerShouldBegin:(UIGestureRecognizer *)gestureRecognizer {
    if (self.viewControllers.count > 1) {
        return YES;
    }
    return NO;
}

@end

简单，无副作用答案

尽管此处的大多数答案都不错，但它们似乎具有意想不到的副作用（应用程序中断）或过于冗长。

我能想到的最简单但功能齐全的解决方案是：

在要隐藏NavigationBar的ViewController中，

class MyNoNavBarViewController: UIViewController {
    
    // needed for reference when leaving this view controller
    var initialInteractivePopGestureRecognizerDelegate: UIGestureRecognizerDelegate?
    
    override func viewDidLoad() {
        super.viewDidLoad()
        
        // we will need a reference to the initial delegate so that when we push or pop.. 
        // ..this view controller we can appropriately assign back the original delegate
        initialInteractivePopGestureRecognizerDelegate = self.navigationController?.interactivePopGestureRecognizer?.delegate
    }

    override func viewWillAppear(_ animated: Bool) {
        super.viewWillAppear(true)

        // we must set the delegate to nil whether we are popping or pushing to..
        // ..this view controller, thus we set it in viewWillAppear()
        self.navigationController?.interactivePopGestureRecognizer?.delegate = nil
    }

    override func viewWillDisappear(_ animated: Bool) {
        super.viewWillDisappear(true)

        // and every time we leave this view controller we must set the delegate back..
        // ..to what it was originally
        self.navigationController?.interactivePopGestureRecognizer?.delegate = initialInteractivePopGestureRecognizerDelegate
    }
}

其他答案建议仅将委托设置为nil。向后滑动到导航堆栈上的初始视图控制器会导致所有手势被禁用。可能是对UIKit / UIGesture开发人员的某种监督。

同样，我在此处实现的一些答案也导致了非标准的Apple导航行为（具体而言，允许向上或向下滚动同时向后滑动）。这些答案似乎也很冗长，在某些情况下还不完整。

基于Hunter Maximillion Monk的回答，我为UINavigationController创建了一个子类，然后在情节提要中为UINavigationController设置了自定义类。这两个类的最终代码如下：

InteractivePopRecognizer：

class InteractivePopRecognizer: NSObject {

    // MARK: - Properties

    fileprivate weak var navigationController: UINavigationController?

    // MARK: - Init

    init(controller: UINavigationController) {
        self.navigationController = controller

        super.init()

        self.navigationController?.interactivePopGestureRecognizer?.delegate = self
    }
}

extension InteractivePopRecognizer: UIGestureRecognizerDelegate {
    func gestureRecognizerShouldBegin(_ gestureRecognizer: UIGestureRecognizer) -> Bool {
        return (navigationController?.viewControllers.count ?? 0) > 1
    }

    // This is necessary because without it, subviews of your top controller can cancel out your gesture recognizer on the edge.
    func gestureRecognizer(_ gestureRecognizer: UIGestureRecognizer, shouldRecognizeSimultaneouslyWith otherGestureRecognizer: UIGestureRecognizer) -> Bool {
        return true
    }
}

HiddenNavBarNavigationController：

class HiddenNavBarNavigationController: UINavigationController {

    // MARK: - Properties

    private var popRecognizer: InteractivePopRecognizer?

    // MARK: - Lifecycle

    override func viewDidLoad() {
        super.viewDidLoad()
        setupPopRecognizer()
    }

    // MARK: - Setup

    private func setupPopRecognizer() {
        popRecognizer = InteractivePopRecognizer(controller: self)
    }
}

故事板：

看起来@ChrisVasseli提供的解决方案是最好的。我想在Objective-C中提供相同的解决方案，因为问题与Objective-C有关（请参阅标签）

@interface InteractivePopGestureDelegate : NSObject <UIGestureRecognizerDelegate>

@property (nonatomic, weak) UINavigationController *navigationController;
@property (nonatomic, weak) id<UIGestureRecognizerDelegate> originalDelegate;

@end

@implementation InteractivePopGestureDelegate

- (BOOL)gestureRecognizer:(UIGestureRecognizer *)gestureRecognizer shouldReceiveTouch:(UITouch *)touch
{
    if (self.navigationController.navigationBarHidden && self.navigationController.viewControllers.count > 1) {
        return YES;
    } else {
        return [self.originalDelegate gestureRecognizer:gestureRecognizer shouldReceiveTouch:touch];
    }
}

- (BOOL)respondsToSelector:(SEL)aSelector
{
    if (aSelector == @selector(gestureRecognizer:shouldReceiveTouch:)) {
        return YES;
    } else {
        return [self.originalDelegate respondsToSelector:aSelector];
    }
}

- (id)forwardingTargetForSelector:(SEL)aSelector
{
    return self.originalDelegate;
}

@end

@interface NavigationController ()

@property (nonatomic) InteractivePopGestureDelegate *interactivePopGestureDelegate;

@end

@implementation NavigationController

- (void)viewDidLoad
{
    [super viewDidLoad];

    self.interactivePopGestureDelegate = [InteractivePopGestureDelegate new];
    self.interactivePopGestureDelegate.navigationController = self;
    self.interactivePopGestureDelegate.originalDelegate = self.interactivePopGestureRecognizer.delegate;
    self.interactivePopGestureRecognizer.delegate = self.interactivePopGestureDelegate;
}

@end

我的解决方案是直接扩展UINavigationController类：

import UIKit

extension UINavigationController: UIGestureRecognizerDelegate {

    override open func viewDidAppear(_ animated: Bool) {
        super.viewDidAppear(animated)

        self.interactivePopGestureRecognizer?.delegate = self
    }

    public func gestureRecognizerShouldBegin(_ gestureRecognizer: UIGestureRecognizer) -> Bool {
        return self.viewControllers.count > 1
    }

}

这样，所有的导航控制器都可以通过滑动关闭。

您可以使用代理委托来完成。在构建导航控制器时，请抓住现有的委托。并将其传递给代理。然后将所有委托方法传递给现有委托，除了gestureRecognizer:shouldReceiveTouch:使用forwardingTargetForSelector:

建立：

let vc = UIViewController(nibName: nil, bundle: nil)
let navVC = UINavigationController(rootViewController: vc)
let bridgingDelegate = ProxyDelegate()
bridgingDelegate.existingDelegate = navVC.interactivePopGestureRecognizer?.delegate
navVC.interactivePopGestureRecognizer?.delegate = bridgingDelegate

代理代表：

class ProxyDelegate: NSObject, UIGestureRecognizerDelegate {
    var existingDelegate: UIGestureRecognizerDelegate? = nil

    override func forwardingTargetForSelector(aSelector: Selector) -> AnyObject? {
        return existingDelegate
    }

    func gestureRecognizer(gestureRecognizer: UIGestureRecognizer, shouldReceiveTouch touch: UITouch) -> Bool {
        return true
    }  
}

Hunter Monk的答案确实很棒，但不幸的是，在iOS 13.3.1中，它不起作用。

我将解释隐藏UINavigationBar而不失落的另一种方式swipe to back gesture。我已经在iOS 13.3.1和12.4.3上进行了测试，并且可以正常工作。

你需要创建一个自定义类UINavigationController，并设置类UINavigationController中Storyboard

不要隐藏NavigationBar在Storyboard

范例Storyboard：

最后，把这个：navigationBar.isHidden = true在viewDidLoad的CustomNavigationController类。

请确保不要使用此方法setNavigationBarHidden(true, animated: true)隐藏NavigationBar。

import UIKit

class CustomNavigationController: UINavigationController {

    override func viewDidLoad() {
        super.viewDidLoad()

        navigationBar.isHidden = true
    }
}

Xamarin答案：

IUIGestureRecognizerDelegate在ViewController的Class定义中实现Interface：

public partial class myViewController : UIViewController, IUIGestureRecognizerDelegate

在您的ViewController中，添加以下方法：

[Export("gestureRecognizerShouldBegin:")]
public bool ShouldBegin(UIGestureRecognizer recognizer) {
  if (recognizer is UIScreenEdgePanGestureRecognizer && 
      NavigationController.ViewControllers.Length == 1) {
    return false;
  }
  return true;
}

在您的ViewController中，ViewDidLoad()添加以下行：

NavigationController.InteractivePopGestureRecognizer.Delegate = this;

我已经尝试过了，并且效果很好： 如何隐藏导航栏而不会丢失滑动功能

这个想法是在您的.h中实现“ UIGestureRecognizerDelegate”，并将其添加到您的.m文件中。

- (void)viewWillAppear:(BOOL)animated {
// hide nav bar
[[self navigationController] setNavigationBarHidden:YES animated:YES];

// enable slide-back
if ([self.navigationController respondsToSelector:@selector(interactivePopGestureRecognizer)]) {
    self.navigationController.interactivePopGestureRecognizer.enabled = YES;
    self.navigationController.interactivePopGestureRecognizer.delegate = self;
  }
}

- (BOOL)gestureRecognizerShouldBegin:(UIGestureRecognizer *)gestureRecognizer {
   return YES;  
}

这是我的解决方案：我正在更改导航栏上的Alpha，但导航栏未隐藏。我所有的视图控制器都是BaseViewController的子类，我在那里：

    override func viewDidAppear(_ animated: Bool) {
    super.viewDidAppear(animated)
    navigationController?.navigationBar.alpha = 0.0
}

您也可以将UINavigationController子类化，并将该方法放在那里。

有些人通过setNavigationBarHidden用animated调用该方法YES而获得成功。

在没有导航栏的视图控制器中，我使用

open override func viewWillAppear(_ animated: Bool) {
  super.viewWillAppear(animated)

  CATransaction.begin()
  UIView.animate(withDuration: 0.25, animations: { [weak self] in
    self?.navigationController?.navigationBar.alpha = 0.01
  })
  CATransaction.commit()
}

open override func viewWillDisappear(_ animated: Bool) {
  super.viewWillDisappear(animated)
  CATransaction.begin()
  UIView.animate(withDuration: 0.25, animations: { [weak self] in
    self?.navigationController?.navigationBar.alpha = 1.0
  })
  CATransaction.commit()
}

在交互式解雇过程中，后退按钮会一直闪着，这就是我隐藏它的原因。

有一个非常简单的解决方案，我尝试过并且可以完美地运行，它在Xamarin.iOS中，但是也可以应用于本机：

    public override void ViewWillAppear(bool animated)
    {
        base.ViewWillAppear(animated);
        this.NavigationController.SetNavigationBarHidden(true, true);
    }

    public override void ViewDidAppear(bool animated)
    {
        base.ViewDidAppear(animated);
        this.NavigationController.SetNavigationBarHidden(false, false);
        this.NavigationController.NavigationBar.Hidden = true;
    }

    public override void ViewWillDisappear(bool animated)
    {
        base.ViewWillDisappear(animated);
        this.NavigationController.SetNavigationBarHidden(true, false);
    }

这是当用户滑出ViewController时禁用手势识别器的方法。您可以将其粘贴到viewWillAppear（）或ViewDidLoad（）方法上。

if ([self.navigationController respondsToSelector:@selector(interactivePopGestureRecognizer)]) {
    self.navigationController.interactivePopGestureRecognizer.enabled = NO;
}