如何从Java中的标准输入读取整数值

我可以使用什么类来读取Java中的整数变量？

您可以使用java.util.Scanner（API）：

import java.util.Scanner;

//...

Scanner in = new Scanner(System.in);
int num = in.nextInt();

它还可以使用正则表达式对输入进行标记，等等。该API有示例，并且该站点中还有很多其他示例（例如，输入错误的类型时，如何防止扫描程序抛出异常？）。

如果您使用的是Java 6，则可以使用以下oneliner从控制台读取整数：

int n = Integer.parseInt(System.console().readLine());

在这里，我提供2个示例以从标准输入中读取整数值

例子1

import java.util.Scanner;
public class Maxof2
{ 
  public static void main(String args[])
  {
       //taking value as command line argument.
        Scanner in = new Scanner(System.in); 
       System.out.printf("Enter i Value:  ");
       int i = in.nextInt();
       System.out.printf("Enter j Value:  ");
       int j = in.nextInt();
       if(i > j)
           System.out.println(i+"i is greater than "+j);
       else
           System.out.println(j+" is greater than "+i);
   }
 }

例子2

public class ReadandWritewhateveryoutype
{ 
  public static void main(String args[]) throws java.lang.Exception
  {
System.out.printf("This Program is used to Read and Write what ever you type \nType  quit  to Exit at any Moment\n\n");
    java.io.BufferedReader r = new java.io.BufferedReader (new java.io.InputStreamReader (System.in));
     String hi;
     while (!(hi=r.readLine()).startsWith("quit"))System.out.printf("\nYou have typed: %s \n",hi);
     }
 }

我更喜欢第一个示例，它很容易理解。
您可以在以下网站上在线编译和运行JAVA程序：http : //ideone.com

检查这一：

public static void main(String[] args) {
    String input = null;
    int number = 0;
    try {
        BufferedReader bufferedReader = new BufferedReader(new InputStreamReader(System.in));
        input = bufferedReader.readLine();
        number = Integer.parseInt(input);
    } catch (NumberFormatException ex) {
       System.out.println("Not a number !");
    } catch (IOException e) {
        e.printStackTrace();
    }
}

上面的第二个答案是最简单的答案。

int n = Integer.parseInt(System.console().readLine());

问题是“如何从标准输入中读取”。

控制台是通常与键盘和显示器相关联的设备，可从中启动程序。

您可能希望测试是否没有可用的Java控制台设备，例如，不是从命令行启动的Java VM，还是重定向了标准输入和输出流。

Console cons;
if ((cons = System.console()) == null) {
    System.err.println("Unable to obtain console");
    ...
}

使用控制台是输入数字的简单方法。与parseInt（）/ Double（）等结合使用

s = cons.readLine("Enter a int: ");
int i = Integer.parseInt(s);    

s = cons.readLine("Enter a double: ");
double d = Double.parseDouble(s);

检查这一：

import java.io.*;
public class UserInputInteger
{
        public static void main(String args[])throws IOException
        {
        InputStreamReader read = new InputStreamReader(System.in);
        BufferedReader in = new BufferedReader(read);
        int number;
                System.out.println("Enter the number");
                number = Integer.parseInt(in.readLine());
    }
}

这会引起头痛，因此我在2014年12月更新了将使用用户可用的最常见硬件和软件工具运行的解决方案。请注意，JDK / SDK / JRE / Netbeans及其后续类，模板库编译器，编辑器和debuggerz是自由。

该程序已通过Java v8 u25进行了测试。它是使用
Netbeans IDE 8.0.2，JDK 1.8，OS为win8.1（道歉）和浏览器为Chrome（双重道歉）编写和构建的，旨在帮助UNIX-cmd-line OG处理基于现代GUI-Web的问题。 IDE的费用为零-因为信息（和IDE）应始终免费。由Tapper7。为了每一个。

代码块：

    package modchk; //Netbeans requirement.
    import java.util.Scanner;
    //import java.io.*; is not needed Netbeans automatically includes it.           
    public class Modchk {
        public static void main(String[] args){
            int input1;
            int input2;

            //Explicity define the purpose of the .exe to user:
            System.out.println("Modchk by Tapper7. Tests IOStream and basic bool modulo fxn.\n"
            + "Commented and coded for C/C++ programmers new to Java\n");

            //create an object that reads integers:
            Scanner Cin = new Scanner(System.in); 

            //the following will throw() if you don't do you what it tells you or if 
            //int entered == ArrayIndex-out-of-bounds for your system. +-~2.1e9
            System.out.println("Enter an integer wiseguy: ");
            input1 = Cin.nextInt(); //this command emulates "cin >> input1;"

            //I test like Ernie Banks played hardball: "Let's play two!"
            System.out.println("Enter another integer...anyday now: ");
            input2 = Cin.nextInt(); 

            //debug the scanner and istream:
            System.out.println("the 1st N entered by the user was " + input1);
            System.out.println("the 2nd N entered by the user was " + input2);

            //"do maths" on vars to make sure they are of use to me:
            System.out.println("modchk for " + input1);
            if(2 % input1 == 0){
                System.out.print(input1 + " is even\n"); //<---same output effect as *.println
                }else{
                System.out.println(input1 + " is odd");
            }//endif input1

            //one mo' 'gain (as in istream dbg chk above)
            System.out.println("modchk for " + input2);
            if(2 % input2 == 0){
                System.out.print(input2 + " is even\n");
                }else{
                System.out.println(input2 + " is odd");
            }//endif input2
        }//end main
    }//end Modchk