Answers:
你很亲近 您只需要使用该duration.asHours()
方法(请参阅docs)。
var duration = moment.duration(end.diff(startTime));
var hours = duration.asHours();
.diff()
,是的。除非将end.diff(startTime, 'hours', true)
小时数设为正数。但是,您的第二点是不正确的。duration.hours()
将返回1,如果它是在25小时之前,但duration.asHours()
会回到25
.hours()
没有注意到的情况下错误地使用了该方法。
以下代码块显示了如何使用MomentJS计算两个日期之间的天数差异。
var now = moment(new Date()); //todays date
var end = moment("2015-12-1"); // another date
var duration = moment.duration(now.diff(end));
var days = duration.asDays();
console.log(days)
var now = moment();
。参见momentjs.com/docs/#/parsing/now
或者您可以简单地执行以下操作:
var a = moment('2016-06-06T21:03:55');//now
var b = moment('2016-05-06T20:03:55');
console.log(a.diff(b, 'minutes')) // 44700
console.log(a.diff(b, 'hours')) // 745
console.log(a.diff(b, 'days')) // 31
console.log(a.diff(b, 'weeks')) // 4
docs:这里
您需要做的只是将其hours
作为第二个参数传递给moments diff函数。
var a = moment([21,30,00], "HH:mm:ss")
var b = moment([09,30,00], "HH:mm:ss")
a.diff(b, 'hours') // 12
文件: https ://momentjs.com/docs/#/displaying/difference/
例:
const dateFormat = "YYYY-MM-DD HH:mm:ss";
// Get your start and end date/times
const rightNow = moment().format(dateFormat);
const thisTimeYesterday = moment().subtract(1, 'days').format(dateFormat);
// pass in hours as the second parameter to the diff function
const differenceInHours = moment(rightNow).diff(thisTimeYesterday, 'hours');
console.log(`${differenceInHours} hours have passed since this time yesterday`);
<script
src="https://cdnjs.cloudflare.com/ajax/libs/moment.js/2.20.1/moment.min.js">
</script>
有一个很棒的moment
方法fromNow()
,该方法将以易于阅读的形式从特定时间返回时间,如下所示:
moment('2019-04-30T07:30:53.000Z').fromNow() // an hour ago || a day ago || 10 days ago
或者,如果您希望在两个特定日期之间使用它,则可以使用:
var a = moment([2007, 0, 28]);
var b = moment([2007, 0, 29]);
a.from(b); // "a day ago"
摘自文档:
var __startTime = moment("2016-06-06T09:00").format();
var __endTime = moment("2016-06-06T21:00").format();
var __duration = moment.duration(moment(__endTime).diff(__startTime));
var __hours = __duration.asHours();
console.log(__hours);
就我而言,我想要几个小时和几分钟:
var duration = moment.duration(end.diff(startTime));
var hours = duration.hours(); //hours instead of asHours
var minutes = duration.minutes(); //minutes instead of asMinutes
有关更多信息,请参阅官方文档。
如果您希望按日计算两个日期之间的总分钟数,则下面的代码可能会对您有所帮助:开始日期:2018-05-04 02:08:05,结束日期:2018-05-14 09:04:07 ...
function countDaysAndTimes(startDate,endDate){
return new Promise(function (resolve, reject) {
var dayObj = new Object;
var finalArray = new Array;
var datetime1 = moment(startDate);
var datetime2 = moment(endDate);
if(datetime1.format('D') != datetime2.format('D') || datetime1.format('M') != datetime2.format('M') || datetime1.format('YYYY') != datetime2.format('YYYY')){
var onlyDate1 = startDate.split(" ");
var onlyDate2 = endDate.split(" ");
var totalDays = moment(onlyDate2[0]).diff(moment(onlyDate1[0]), 'days')
// First Day Entry
dayObj.startDate = startDate;
dayObj.endDate = moment(onlyDate1[0]).add(1, 'day').format('YYYY-MM-DD')+" 00:00:00";
dayObj.minutes = moment(dayObj.endDate).diff(moment(dayObj.startDate), 'minutes');
finalArray.push(dayObj);
// Between Days Entry
var i = 1;
if(totalDays > 1){
for(i=1; i<totalDays; i++){
var dayObj1 = new Object;
dayObj1.startDate = moment(onlyDate1[0]).add(i, 'day').format('YYYY-MM-DD')+" 00:00:00";
dayObj1.endDate = moment(onlyDate1[0]).add(i+1, 'day').format('YYYY-MM-DD')+" 00:00:00";
dayObj1.minutes = moment(dayObj1.endDate).diff(moment(dayObj1.startDate), 'minutes');
finalArray.push(dayObj1);
}
}
// Last Day Entry
var dayObj2 = new Object;
dayObj2.startDate = moment(onlyDate1[0]).add(i, 'day').format('YYYY-MM-DD')+" 00:00:00";
dayObj2.endDate = endDate ;
dayObj2.minutes = moment(dayObj2.endDate).diff(moment(dayObj2.startDate), 'minutes');
finalArray.push(dayObj2);
}
else{
dayObj.startDate = startDate;
dayObj.endDate = endDate;
dayObj.minutes = datetime2.diff(datetime1, 'minutes');
finalArray.push(dayObj);
}
console.log(JSON.stringify(finalArray));
// console.table(finalArray);
resolve(finalArray);
});
}
输出量
[
{
"startDate":"2018-05-04 02:08:05",
"endDate":"2018-05-05 00:00:00",
"minutes":1311
},
{
"startDate":"2018-05-05 00:00:00",
"endDate":"2018-05-06 00:00:00",
"minutes":1440
},
{
"startDate":"2018-05-06 00:00:00",
"endDate":"2018-05-07 00:00:00",
"minutes":1440
},
{
"startDate":"2018-05-07 00:00:00",
"endDate":"2018-05-08 00:00:00",
"minutes":1440
},
{
"startDate":"2018-05-08 00:00:00",
"endDate":"2018-05-09 00:00:00",
"minutes":1440
},
{
"startDate":"2018-05-09 00:00:00",
"endDate":"2018-05-10 00:00:00",
"minutes":1440
},
{
"startDate":"2018-05-10 00:00:00",
"endDate":"2018-05-11 00:00:00",
"minutes":1440
},
{
"startDate":"2018-05-11 00:00:00",
"endDate":"2018-05-12 00:00:00",
"minutes":1440
},
{
"startDate":"2018-05-12 00:00:00",
"endDate":"2018-05-13 00:00:00",
"minutes":1440
},
{
"startDate":"2018-05-13 00:00:00",
"endDate":"2018-05-14 00:00:00",
"minutes":1440
},
{
"startDate":"2018-05-14 00:00:00",
"endDate":"2018-05-14 09:04:07",
"minutes":544
}
]
我知道已经回答了这个问题,但是如果您想要递归的东西和更通用的东西,而又不依赖它,fromNow
可以使用我创建的此函数。当然,您可以更改其逻辑以根据需要进行调整,以支持数年和数秒。
var createdAt = moment('2019-05-13T14:23:00.607Z');
var expiresAt = moment('2019-05-14T14:23:00.563Z');
// You can also add years in the beginning of the array or seconds in its end
const UNITS = ["months", "weeks", "days", "hours", "minutes"]
function getValidFor (createdAt, expiresAt, unit = 'months') {
const validForUnit = expiresAt.diff(createdAt, unit);
// you could adjust the if to your needs
if (validForUnit > 1 || unit === "minutes") {
return [validForUnit, unit];
}
return getValidFor(createdAt, expiresAt, UNITS[UNITS.indexOf(unit) + 1]);
}
var timecompare = {
tstr: "",
get: function (current_time, startTime, endTime) {
this.tstr = "";
var s = current_time.split(":"), t1 = tm1.split(":"), t2 = tm2.split(":"), t1s = Number(t1[0]), t1d = Number(t1[1]), t2s = Number(t2[0]), t2d = Number(t2[1]);
if (t1s < t2s) {
this.t(t1s, t2s);
}
if (t1s > t2s) {
this.t(t1s, 23);
this.t(0, t2s);
}
var saat_dk = Number(s[1]);
if (s[0] == tm1.substring(0, 2) && saat_dk >= t1d)
return true;
if (s[0] == tm2.substring(0, 2) && saat_dk <= t2d)
return true;
if (this.tstr.indexOf(s[0]) != 1 && this.tstr.indexOf(s[0]) != -1 && !(this.tstr.indexOf(s[0]) == this.tstr.length - 2))
return true;
return false;
},
t: function (ii, brk) {
for (var i = 0; i <= 23; i++) {
if (i < ii)
continue;
var s = (i < 10) ? "0" + i : i + "";
this.tstr += "," + s;
if (brk == i)
break;
}
}};
startTime.diff(end, 'hours', true);
吗?duration.asHours(); 如果是25个小时前返回1。