通过导航控制器快速传递数据

我的选择之一是从视图控制器过渡到表视图控制器。我想在两者之间传递一个数组，但是在tableview控制器之前使用导航控制器，所以我不知道如何传递该数组。如何通过导航控制器将数据传递到表视图控制器？

重写prepareForSegue并在所需的表视图上设置任何值。您可以从UINavigation viewControllers属性中获取tableview 。

override func prepareForSegue(segue: UIStoryboardSegue!, sender: AnyObject!){

   let navVC = segue.destinationViewController as UINavigationController

   let tableVC = navVC.viewControllers.first as YourTableViewControllerClass

   tableVC.yourTableViewArray = localArrayValue   
}

对于Swift 3：

override func prepare(for segue: UIStoryboardSegue, sender: Any?) {

   let navVC = segue.destination as? UINavigationController

   let tableVC = navVC?.viewControllers.first as! YourTableViewControllerClass

   tableVC.yourTableViewArray = localArrayValue   
}

@汤米·德沃伊（Tommy Devoy）的答案是正确的，但这是Swift 3中的同一件事

更新了Swift 3

  // MARK: - Navigation

//In a storyboard-based application, you will often want to do a little preparation before navigation
override func prepare(for segue: UIStoryboardSegue, sender: Any?) {
    // Get the new view controller using segue.destinationViewController.
    // Pass the selected object to the new view controller.


    if segue.identifier == "yourSegueIdentifier"  {

        if let navController = segue.destination as? UINavigationController {

            if let chidVC = navController.topViewController as? YourViewController {
                 //TODO: access here chid VC  like childVC.yourTableViewArray = localArrayValue 


            }

        }

    }

}

SWIFT 3（经测试的解决方案）-在VC之间传递数据-使用NavigationController进行Segue

override func prepare(for segue: UIStoryboardSegue, sender: Any?) {

        let navigationContoller = segue.destination as! UINavigationController

        let receiverViewController = navigationContoller?.topViewController as ReceiverViewController

        receiverViewController.reveivedObject = sentObject 
    }

我在Horatio的解决方案中遇到此错误。

ERROR: Value of type 'UINavigationController' has no member 'yourTableViewArray'

因此，这可能会帮助像我这样的其他人寻找code唯一的解决方案。我想重定向到导航控制器，但将数据传递到该导航控制器中的根视图控制器。

if let controller = UIStoryboard(name: "Main", bundle: nil).instantiateViewController(withIdentifier: "yourNavigationControllerID") as? UINavigationController,
   let yourViewController = controller.viewControllers.first as? YourViewController {
        yourViewController.yourVariableName = "value"
        self.window?.rootViewController = controller  // if presented from AppDelegate
        // present(controller, animated: true, completion: nil) // if presented from ViewController
}

Tommy的解决方案要求您在情节提要中设置Segue。

这是仅代码解决方案：

func functionToPassAsAction() {
    var controller: UINavigationController
    controller = self.storyboard?.instantiateViewControllerWithIdentifier("NavigationVCIdentifierFromStoryboard") as! UINavigationController 
    controller.yourTableViewArray = localArrayValue
    self.presentViewController(controller, animated: true, completion: nil)
}

SWIFT 3的固定语法

  override func prepare(for segue: UIStoryboardSegue, sender: Any?) {
        let navVC = segue.destination as! UINavigationController
        let tableVC = navVC.viewControllers.first as! YourTableViewControllerClass

        tableVC.yourTableViewArray = localArrayValue
    }

迅捷5

class MyNavigationController: UINavigationController {
    
    var myData: String!
    
    override func viewDidLoad() {
        if let vc = self.topViewController as? MyViewcontoller{
            vc.data = self.myData
        }
    }
    
}

   let navigation = UIStoryboard(name: "Main", bundle: nil).instantiateViewController(withIdentifier: "MyNavigationController") as! MyNavigationController
   navigation.myData = "Data that you want to pass"
   present(navigation, animated: true, completion: nil)

在表格视图中快速传递文本4 **或仅传递数据但更改功能**

第一视图控制器

类

 let name_array = ["BILL GATES", "MARK ZUKERBERG", "DULKAR SALMAN", "TOVINO" , "SMITH"]

func tableView（_ tableView：UITableView，didSelectRowAt indexPath：IndexPath）{

    let story: UIStoryboard = UIStoryboard(name: "Main", bundle: nil)

    let new = story.instantiateViewController(withIdentifier: "SecondViewController")as! SecondViewController

        new.str1 = name_array[indexPath.row]

    self.navigationController?.pushViewController(new, animated: true)

第二视图控制器

class SecondViewController：UIViewController {

@IBOutlet weak var lbl2: UILabel!

var str1 = String()

override func viewDidLoad() {
    super.viewDidLoad()

     lbl2.text =  str1

}