UIActivityViewController在iOS 8 iPad上崩溃

我目前正在使用Xcode 6（测试版6）测试我的应用。UIActivityViewController可以在iPhone设备和模拟器上正常运行，但在iPad模拟器和设备（iOS 8）上崩溃并显示以下日志

Terminating app due to uncaught exception 'NSGenericException', 
reason: 'UIPopoverPresentationController 
(<_UIAlertControllerActionSheetRegularPresentationController: 0x7fc7a874bd90>) 
should have a non-nil sourceView or barButtonItem set before the presentation occurs.

我正在将以下代码用于iOS 7和iOS 8的iPhone和iPad

NSData *myData = [NSData dataWithContentsOfFile:_filename];
NSArray *activityItems = [NSArray arrayWithObjects:myData, nil];
UIActivityViewController *activityViewController = [[UIActivityViewController alloc] initWithActivityItems:nil applicationActivities:nil];
activityViewController.excludedActivityTypes = @[UIActivityTypeCopyToPasteboard];
[self presentViewController:activityViewController animated:YES completion:nil];

我的另一个应用程序也发生了类似的崩溃。你能指导我吗？iOS 8中的UIActivityViewController有什么变化吗？我检查了一下，但没有找到任何东西

在iPad上，活动视图控制器将使用新的UIPopoverPresentationController显示为弹出窗口，它要求您使用以下三个属性之一为弹出窗口的显示指定锚点：

• barButtonItem
• sourceView
• sourceRect

为了指定锚点，您将需要获取对UIActivityController的UIPopoverPresentationController的引用，并按如下所示设置属性之一：

if ( [activityViewController respondsToSelector:@selector(popoverPresentationController)] ) { 
// iOS8
 activityViewController.popoverPresentationController.sourceView =
parentView;
 }

同样的问题出现在我的项目中，然后我找到了UIActivityViewController在iPad中打开我们必须使用的解决方案UIPopoverController

这是在iPhone和iPad上同时使用它的代码：

//to attach the image and text with sharing 
UIImage *image=[UIImage imageNamed:@"giraffe.png"];
NSString *str=@"Image form My app";
NSArray *postItems=@[str,image];

UIActivityViewController *controller = [[UIActivityViewController alloc] initWithActivityItems:postItems applicationActivities:nil];

//if iPhone
if (UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiomPhone) {
    [self presentViewController:controller animated:YES completion:nil];
}
//if iPad
else {
    // Change Rect to position Popover
    UIPopoverController *popup = [[UIPopoverController alloc] initWithContentViewController:controller];
    [popup presentPopoverFromRect:CGRectMake(self.view.frame.size.width/2, self.view.frame.size.height/4, 0, 0)inView:self.view permittedArrowDirections:UIPopoverArrowDirectionAny animated:YES];
}

快速4.2 /快速5

func openShareDilog() {
    let text = "share text will goes here"

    // set up activity view controller
    let textToShare = [text]
    let activityViewController = UIActivityViewController(activityItems: textToShare, applicationActivities: nil)
    activityViewController.excludedActivityTypes = [.airDrop]

    if let popoverController = activityViewController.popoverPresentationController {
        popoverController.sourceRect = CGRect(x: UIScreen.main.bounds.width / 2, y: UIScreen.main.bounds.height / 2, width: 0, height: 0)
        popoverController.sourceView = self.view
        popoverController.permittedArrowDirections = UIPopoverArrowDirection(rawValue: 0)
    }

    self.present(activityViewController, animated: true, completion: nil)
}

我最近在Swift 2.0中遇到了这个确切的问题（原始问题），在UIActivityViewControlleriPhone上可以正常工作，但是在模拟iPad时导致崩溃。

我只是想在这里添加答案，至少在Swift 2.0中，您不需要if语句。您可以将其popoverPresentationController设为可选。

顺便说一句，可接受的答案似乎是说您可以只有一个sourceView，一个sourceRect或一个barButtonItem，但是根据Apple的UIPopoverPresentationController文档，您需要以下之一：

• barButtonItem
• sourceView 和 sourceRect

我正在处理的特定示例如下所示，其中我正在创建一个函数，该函数接受UIView（用于sourceView和sourceRect）和String（UIActivityViewController的唯一activityItem）。

func presentActivityViewController(sourceView: UIView, activityItem: String ) {

    let activityViewController = UIActivityViewController(activityItems: [activityItem], applicationActivities: [])

    activityViewController.popoverPresentationController?.sourceView = sourceView
    activityViewController.popoverPresentationController?.sourceRect = sourceView.bounds

    self.presentViewController(activityViewController, animated: true, completion: nil)
}

此代码可在iPhone和iPad（甚至我认为是tvOS）上运行-如果设备不支持 popoverPresentationController，则提及该代码的两行代码实际上将被忽略。

有点不错，要使其在iPad上运行，您需要做的只是添加两行代码，如果使用barButtonItem，则只需添加一行代码！

我看到许多人在使用Swift代码时对iPhone / iPad等进行硬编码。

这不是必需的，您必须使用语言功能。以下代码假定您将使用UIBarButtonItem并将在iPhone和iPad 上均可使用。

@IBAction func share(sender: AnyObject) {
    let vc = UIActivityViewController(activityItems: ["hello"], applicationActivities: nil)
    vc.popoverPresentationController?.barButtonItem = sender as? UIBarButtonItem
    self.presentViewController(vc, animated: true, completion: nil)
 }

请注意，没有if语句或任何其他疯狂的东西。可选的拆包在iPhone上为零，因此该行在vc.popoverPresentationController?iPhone上不起作用。

使用Xamarin.iOS的解决方案。

在我的示例中，我正在截屏，生成图像并允许用户共享图像。iPad上的弹出窗口位于屏幕中间。

var activityItems = new NSObject[] { image };
var excludedActivityTypes = new NSString[] {
    UIActivityType.PostToWeibo,
    UIActivityType.CopyToPasteboard,
    UIActivityType.AddToReadingList,
    UIActivityType.AssignToContact,
    UIActivityType.Print,
};
var activityViewController = new UIActivityViewController(activityItems, null);

//set subject line if email is used
var subject = new NSString("subject");
activityViewController.SetValueForKey(NSObject.FromObject("Goal Length"), subject);

activityViewController.ExcludedActivityTypes = excludedActivityTypes;
//configure for iPad, note if you do not your app will not pass app store review
if(null != activityViewController.PopoverPresentationController)
{
    activityViewController.PopoverPresentationController.SourceView = this.View;
    var frame = UIScreen.MainScreen.Bounds;
    frame.Height /= 2;
    activityViewController.PopoverPresentationController.SourceRect = frame;
}
this.PresentViewController(activityViewController, true, null);

Swift，iOS 9/10（不建议使用UIPopoverController之后）

let activityViewController = UIActivityViewController(activityItems: sharingItems, applicationActivities: nil)

    if UIDevice.currentDevice().userInterfaceIdiom == .Pad {

       if activityViewController.respondsToSelector(Selector("popoverPresentationController")) {
          activityViewController.popoverPresentationController?.sourceView = self.view
        }
    }

    self.presentViewController(activityViewController, animated: true, completion: nil)

在Swift中为iPad修复此问题，最好的方法就是这样做。

    let things = ["Things to share"]
    let avc = UIActivityViewController(activityItems:things, applicationActivities:nil)
    avc.setValue("Subject title", forKey: "subject")
    avc.completionWithItemsHandler = {
        (s: String!, ok: Bool, items: [AnyObject]!, err:NSError!) -> Void in
    }

    self.presentViewController(avc, animated:true, completion:nil)
    if let pop = avc.popoverPresentationController {
        let v = sender as! UIView // sender would be the button view tapped, but could be any view
        pop.sourceView = v
        pop.sourceRect = v.bounds
    }

修复Swift 2.0

    if UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiom.Phone {
        self.presentViewController(activityVC, animated: true, completion: nil)
    }
    else {
        let popup: UIPopoverController = UIPopoverController(contentViewController: activityVC)
        popup.presentPopoverFromRect(CGRectMake(self.view.frame.size.width / 2, self.view.frame.size.height / 4, 0, 0), inView: self.view, permittedArrowDirections: UIPopoverArrowDirection.Any, animated: true)
    }

斯威夫特3：

class func openShareActions(image: UIImage, vc: UIViewController) {
    let activityVC = UIActivityViewController(activityItems: [image], applicationActivities: nil)
    if UIDevice.current.userInterfaceIdiom == .pad {
        if activityVC.responds(to: #selector(getter: UIViewController.popoverPresentationController)) {
            activityVC.popoverPresentationController?.sourceView = vc.view
        }
    }
    vc.present(activityVC, animated: true, completion: nil)
}

如果UIActivityViewController单击时显示，请UIBarButtonItem使用以下代码：

activityViewController.popoverPresentationController?.barButtonItem = sender

否则，如果您使用其他控件（例如a）UIButton，请使用以下代码：

activityViewController.popoverPresentationController?.sourceView = sender
activityViewController.popoverPresentationController?.sourceRect = sender.bounds

从文档到UIPopoverPresentationController：

var barButtonItem: UIBarButtonItem? { get set }

为该属性分配一个值，以将弹出框锚定到指定的条形按钮项。出现时，弹出框的箭头指向指定的项目。或者，您可以使用sourceView和sourceRect属性指定弹出框的锚点位置。

迅速：

    let activityViewController = UIActivityViewController(activityItems: sharingItems, applicationActivities: nil)

    //if iPhone
    if (UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiom.Phone) {
        self.presentViewController(activityViewController, animated: true, completion: nil)
    } else { //if iPad
        // Change Rect to position Popover
        var popoverCntlr = UIPopoverController(contentViewController: activityViewController)
        popoverCntlr.presentPopoverFromRect(CGRectMake(self.view.frame.size.width/2, self.view.frame.size.height/4, 0, 0), inView: self.view, permittedArrowDirections: UIPopoverArrowDirection.Any, animated: true)

    }

适用于Objective-C并使用UIPopoverPresentationController的解决方案

    UIActivityViewController *controller = /*Init your Controller*/;
    //if iPhone
    if (UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiomPhone) {
        [self presentViewController:controller animated:YES completion:nil];
    }
    //if iPad
    else {
        UIPopoverPresentationController* popOver = controller.popoverPresentationController
        if(popOver){
            popOver.sourceView = controller.view;
            popOver.sourceRect = CGRectMake(self.view.frame.size.width/2, self.view.frame.size.height/4, 0, 0);
            [self presentViewController:controller animated:YES completion:nil];
        }
    }

我尝试了下一个代码，它的工作原理是：

首先在您的View Controller中放置一个条形按钮项，然后创建一个IBOutlet：

@property(weak,nonatomic)IBOutlet UIBarButtonItem *barButtonItem;

.m文件中的下一个： yourUIActivityViewController.popoverPresentationController.barButtonItem = self.barButtonItem;

迅速= iOS7 / iOS8

let activityViewController = UIActivityViewController(activityItems: sharingItems, applicationActivities: nil)

//if iPhone
if (UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiom.Phone) {
    // go on..
} else {
    //if iPad
    if activityViewController.respondsToSelector(Selector("popoverPresentationController")) {
        // on iOS8
        activityViewController.popoverPresentationController!.barButtonItem = self.shareButtonItem;
    }
}
self.presentViewController(activityViewController, animated: true, completion: nil)

我找到了这个解决方案首先，您的呈现弹出框的视图控制器应实现 <UIPopoverPresentationControllerDelegate>协议。

接下来，您需要设置 popoverPresentationController的代表。

添加以下功能：

- (void)prepareForSegue:(UIStoryboardSegue *)segue sender:(id)sender {
// Assuming you've hooked this all up in a Storyboard with a popover presentation style
    if ([segue.identifier isEqualToString:@"showPopover"]) {
        UINavigationController *destNav = segue.destinationViewController;
        PopoverContentsViewController *vc = destNav.viewControllers.firstObject;

        // This is the important part
        UIPopoverPresentationController *popPC = destNav.popoverPresentationController;
        popPC.delegate = self;
    }
}

- (UIModalPresentationStyle)adaptivePresentationStyleForPresentationController: (UIPresentationController *)controller {
    return UIModalPresentationNone;
}

在iphone和ipad中运行的以下4个代码中。根据文件

您有责任使用给定设备惯用法的适当方法来展示和关闭视图控制器。在iPad上，必须在弹出窗口中显示视图控制器。在其他设备上，您必须以模态显示。

 let activityViewController = UIActivityViewController(activityItems: activityitems, applicationActivities: nil)

    if UIDevice.current.userInterfaceIdiom == .pad {

        if activityViewController.responds(to: #selector(getter: UIViewController.popoverPresentationController)) {
            activityViewController.popoverPresentationController?.sourceView = self.view
        }
    }

    self.present(activityViewController, animated: true, completion: nil)

我使用的是Swift5。当我在iPad上的应用程序中单击“共享按钮”时，出现了同样的崩溃问题。找到了这个解决方案。步骤1：将“视图”对象（在对象库中搜索“ UIView”）添加到Main.storyboard。步骤2：在ViewController.swift中创建一个@IBOutlet并分配任何名称（例如：view1）

步骤3：将上述名称（例如：view1）添加为sourceView。这是我的“共享按钮”操作。

@IBAction func Share(_ sender: Any) {
    let activityVC = UIActivityViewController(activityItems: ["www.google.com"], applicationActivities: nil)
    activityVC.popoverPresentationController?.sourceView = view1

    self.present(activityVC, animated: true, completion: nil)


}

我是新手，很快就坚持了一周。希望这会帮助某人。所以分享这个解决方案。

对于Swift 2.0。我发现，如果您尝试将弹出框锚定到iPad上的“共享”按钮，则此方法有效。假设您已经在工具栏中为共享按钮创建了一个出口。

func share(sender: AnyObject) {
    let firstActivityItem = "test"

    let activityViewController = UIActivityViewController(activityItems: [firstActivityItem], applicationActivities: nil)

    if UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiom.Phone {
        self.presentViewController(activityViewController, animated: true, completion: nil)
    }
    else {            
        if activityViewController.respondsToSelector("popoverPresentationController") {
            activityViewController.popoverPresentationController!.barButtonItem = sender as? UIBarButtonItem
            self.presentViewController(activityViewController, animated: true, completion: nil)
        }

    }
}

如果您使用swift为iPad开发，请小心，它在调试中可以正常工作，但在发行时会崩溃。为了使其能够与testFlight和AppStore一起使用，请禁用针对swift use -nonefor release的优化。