用php上传多个文件


122

我想上传多个文件并将其存储在一个文件夹中,并获取路径并将其存储在数据库中。

注意:文件可以是任何类型...



2
这是一个很好的示例供您遵循:示例
jini 2010年

@sarfraz我度过了一个周末...刚才我尝试了一个非常简单的示例
udaya

@sarfraz我尝试通过添加点击生成<td> <input name =“ ufile []” type =“ file” id =“ ufile []” size =“ 50” /> </ td> td>处于添加点击状态,但未实现结果?您能看到我发布的新问题
吗?udaya

Answers:


260

我知道这是一篇过时的文章,但是对于试图上传多个文件的人来说,一些进一步的解释可能会很有用...这是您需要做的:

  • 输入名称必须定义为数组,即 name="inputName[]"
  • 输入元素必须具有multiple="multiple"或仅multiple
  • 在您的PHP文件中使用语法 "$_FILES['inputName']['param'][index]"
  • 确保查找空文件名和路径,该数组可能包含空字符串array_filter()计数前使用。

这是一个肮脏的例子(仅显示相关代码)

HTML:

<input name="upload[]" type="file" multiple="multiple" />

PHP:

//$files = array_filter($_FILES['upload']['name']); //something like that to be used before processing files.

// Count # of uploaded files in array
$total = count($_FILES['upload']['name']);

// Loop through each file
for( $i=0 ; $i < $total ; $i++ ) {

  //Get the temp file path
  $tmpFilePath = $_FILES['upload']['tmp_name'][$i];

  //Make sure we have a file path
  if ($tmpFilePath != ""){
    //Setup our new file path
    $newFilePath = "./uploadFiles/" . $_FILES['upload']['name'][$i];

    //Upload the file into the temp dir
    if(move_uploaded_file($tmpFilePath, $newFilePath)) {

      //Handle other code here

    }
  }
}

希望这会有所帮助!


1
我不确定是否<input type="file">允许该属性multiple-预期的结果是什么?浏览器允许选择多个文件?
2012年

9
@Sven是的,HTML5支持它,请检查此链接,我的糟糕情况似乎是IE不支持此链接...如果所有人都按标准执行,Geeze我们的生活将变得更加轻松...大声笑
Andy Braham

7
@AndyBraham的multipleinput元素的属性是布尔型,这意味着你没有提供一个值: <input name="upload[]" type="file" multiple /> 请参阅HTML5规范:w3.org/TR/2011/WD-html5-20110525/...
罗布·约翰森

11
值得一提的是,用户必须一次选择所有文件。任何进一步的选择尝试将取消先前的选择。
Skippy le Grand Gourou 2015年

2
@AlienBishop在这里不太正确,multiple =“ multiple”很好,可以作为替代选择包含在规范中。
kojow7年7

38

可以选择多个文件,然后使用执行上传
<input type='file' name='file[]' multiple>
的示例php脚本上传:

<html>
<title>Upload</title>
<?php
    session_start();
    $target=$_POST['directory'];
        if($target[strlen($target)-1]!='/')
                $target=$target.'/';
            $count=0;
            foreach ($_FILES['file']['name'] as $filename) 
            {
                $temp=$target;
                $tmp=$_FILES['file']['tmp_name'][$count];
                $count=$count + 1;
                $temp=$temp.basename($filename);
                move_uploaded_file($tmp,$temp);
                $temp='';
                $tmp='';
            }
    header("location:../../views/upload.php");
?>
</html>

所选文件作为数组接收

$_FILES['file']['name'][0]存储第一个文件的名称。
$_FILES['file']['name'][1]存储第二个文件的名称。
等等。


上传多个文件时,有什么方法可以用JS访问每个文件的文件路径?例如,对于单个文件,你可以简单地查询fileInput.value,但我注意到,当选择了多个文件fileInput.value仍然只输出一个路径...
oldboy

6

的HTML

  1. 创建div id='dvFile';

  2. 创建一个button;

  3. onclick 该按钮调用功能的 add_more()

的JavaScript

function  add_more() {
  var txt = "<br><input type=\"file\" name=\"item_file[]\">";
  document.getElementById("dvFile").innerHTML += txt;
}

的PHP

if(count($_FILES["item_file"]['name'])>0)
 { 
//check if any file uploaded
 $GLOBALS['msg'] = ""; //initiate the global message
  for($j=0; $j < count($_FILES["item_file"]['name']); $j++)
 { //loop the uploaded file array
   $filen = $_FILES["item_file"]['name']["$j"]; //file name
   $path = 'uploads/'.$filen; //generate the destination path
   if(move_uploaded_file($_FILES["item_file"]['tmp_name']["$j"],$path)) 
{
   //upload the file
    $GLOBALS['msg'] .= "File# ".($j+1)." ($filen) uploaded successfully<br>";
    //Success message
   }
  }
 }
 else {
  $GLOBALS['msg'] = "No files found to upload"; //No file upload message 
}

这样,您可以根据需要添加文件/图像,并通过php脚本处理它们。


1
替换此 document.getElementById(“ dvFile”)。innerHTML + = txt; $(“ #dvFile”).append(txt); 它会保存您的附件
Rahul rajoria

这个答案是过时的(我认为太简单了,太复杂了)。对于正确的答案,请看@ rjv's
Vladimir

@VladimirNul在上传多个文件时,是否可以使用JS访问每个文件的文件路径?例如,对于单个文件,您可以简单地查询fileInput.value,但是我注意到,当选择多个文件时,fileInput.value仍然仅输出一个路径...
oldboy

@Anthony听起来您正在用javascript执行此操作,但我不明白这一点。请检查rjv的答案。
弗拉基米尔·努尔

5

与上传一个文件没有什么不同- $_FILES包含所有上传文件的数组。

PHP手册中有一章:上传多个文件

如果要在用户端轻松选择以启用多个文件上传(一次选择多个文件而不是填写上传字段),请查看SWFUpload。但是,它的工作方式不同于正常的文件上传形式,并且需要Flash才能工作。SWFUpload与Flash一起已被废弃。查看其他较新的答案,以获取现在正确的方法。


1
这个答案是过时的。对于正确的答案,请查看@ rjv's
Vladimir

真正。编辑以反映这一点。
Pekka

4
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Untitled Document</title>
</head>

<body>
<?php
$max_no_img=4; // Maximum number of images value to be set here

echo "<form method=post action='' enctype='multipart/form-data'>";
echo "<table border='0' width='400' cellspacing='0' cellpadding='0' align=center>";
for($i=1; $i<=$max_no_img; $i++){
echo "<tr><td>Images $i</td><td>
<input type=file name='images[]' class='bginput'></td></tr>";
}

echo "<tr><td colspan=2 align=center><input type=submit value='Add Image'></td></tr>";
echo "</form> </table>";
while(list($key,$value) = each($_FILES['images']['name']))
{
    //echo $key;
    //echo "<br>";
    //echo $value;
    //echo "<br>";
if(!empty($value)){   // this will check if any blank field is entered
$filename =rand(1,100000).$value;    // filename stores the value

$filename=str_replace(" ","_",$filename);// Add _ inplace of blank space in file name, you can remove this line

$add = "upload/$filename";   // upload directory path is set
//echo $_FILES['images']['type'][$key];     // uncomment this line if you want to display the file type
//echo "<br>";                             // Display a line break
copy($_FILES['images']['tmp_name'][$key], $add); 
echo $add;
    //  upload the file to the server
chmod("$add",0777);                 // set permission to the file.
}
}
?>
</body>
</html>

这个答案是过时的。对于正确的答案,请看@ rjv's
Vladimir

4

简单的是,只需先计算文件数组,然后在while循环中就可以轻松地执行此操作

$count = count($_FILES{'item_file']['name']);

现在,您获得了正确的文件总数。

在while循环中这样做:

$i = 0;
while($i<$count)
{
    Upload one by one like we do normally
    $i++;
}

1
这里缺少一些内容,请查看@rjv的答案。
弗拉基米尔·努尔


3

这是我写的一个函数,它返回一个更易于理解的$_FILES数组。

function getMultiple_FILES() {
    $_FILE = array();
    foreach($_FILES as $name => $file) {
        foreach($file as $property => $keys) {
            foreach($keys as $key => $value) {
                $_FILE[$name][$key][$property] = $value;
            }
        }
    }
    return $_FILE;
}

2

我运行带有错误元素的foreach循环,看起来像

 foreach($_FILES['userfile']['error'] as $k=>$v)
 {
    $uploadfile = 'uploads/'. basename($_FILES['userfile']['name'][$k]);
    if (move_uploaded_file($_FILES['userfile']['tmp_name'][$k], $uploadfile)) 
    {
        echo "File : ", $_FILES['userfile']['name'][$k] ," is valid, and was                      successfully uploaded.\n";
    }

    else 
    {
        echo "Possible file : ", $_FILES['userfile']['name'][$k], " upload attack!\n";
    }   

 }


0

通过使用以下脚本,我们可以使用php轻松上传多个文件。

下载完整源代码并预览

<?php
if (isset($_POST['submit'])) {
    $j = 0; //Variable for indexing uploaded image 

 $target_path = "uploads/"; //Declaring Path for uploaded images
    for ($i = 0; $i < count($_FILES['file']['name']); $i++) {//loop to get individual element from the array

        $validextensions = array("jpeg", "jpg", "png");  //Extensions which are allowed
        $ext = explode('.', basename($_FILES['file']['name'][$i]));//explode file name from dot(.) 
        $file_extension = end($ext); //store extensions in the variable

  $target_path = $target_path . md5(uniqid()) . "." . $ext[count($ext) - 1];//set the target path with a new name of image
        $j = $j + 1;//increment the number of uploaded images according to the files in array       

   if (($_FILES["file"]["size"][$i] < 100000) //Approx. 100kb files can be uploaded.
                && in_array($file_extension, $validextensions)) {
            if (move_uploaded_file($_FILES['file']['tmp_name'][$i], $target_path)) {//if file moved to uploads folder
                echo $j. ').<span id="noerror">Image uploaded successfully!.</span><br/><br/>';
            } else {//if file was not moved.
                echo $j. ').<span id="error">please try again!.</span><br/><br/>';
            }
        } else {//if file size and file type was incorrect.
            echo $j. ').<span id="error">***Invalid file Size or Type***</span><br/><br/>';
        }
    }
}
?>

0
$property_images = $_FILES['property_images']['name'];
    if(!empty($property_images))
    {
        for($up=0;$up<count($property_images);$up++)
        {
            move_uploaded_file($_FILES['property_images']['tmp_name'][$up],'../images/property_images/'.$_FILES['property_images']['name'][$up]);
        }
    }

1
请检查此URL,这将有助于提高您的内容质量
Willie Cheng

0

这对我有用。我必须上传文件,存储文件名,并且还要从输入字段中存储其他信息,并且每个文件名应包含一个记录。我使用了serialize(),然后将其添加到主要的SQL查询中。

  class addReminder extends dbconn {
    public function addNewReminder(){

           $this->exdate = $_POST['exdate'];
           $this->name = $_POST['name'];
           $this->category = $_POST['category'];
           $this->location = $_POST['location'];
           $this->notes = $_POST['notes'];



           try {

                     if(isset($_POST['submit'])){
                       $total = count($_FILES['fileUpload']['tmp_name']);
                       for($i=0;$i<$total;$i++){
                         $fileName = $_FILES['fileUpload']['name'][$i];
                         $ext = pathinfo($fileName, PATHINFO_EXTENSION);
                         $newFileName = md5(uniqid());
                         $fileDest = 'filesUploaded/'.$newFileName.'.'.$ext;
                         $justFileName = $newFileName.'.'.$ext;
                         if($ext === 'pdf' || 'jpeg' || 'JPG'){
                             move_uploaded_file($_FILES['fileUpload']['tmp_name'][$i], $fileDest);
                             $this->fileName = array($justFileName);
                             $this->encodedFileNames = serialize($this->fileName);
                             var_dump($this->encodedFileNames);
                         }else{
                           echo $fileName . ' Could not be uploaded. Pdfs and jpegs only please';
                         }
                       }

                    $sql = "INSERT INTO reminders (exdate, name, category, location, fileUpload, notes) VALUES (:exdate,:name,:category,:location,:fileName,:notes)";
                    $stmt = $this->connect()->prepare($sql);
                    $stmt->bindParam(':exdate', $this->exdate);
                    $stmt->bindParam(':name', $this->name);
                    $stmt->bindParam(':category', $this->category);
                    $stmt->bindParam(':location', $this->location);
                    $stmt->bindParam(':fileName', $this->encodedFileNames);
                    $stmt->bindParam(':notes', $this->notes);
                    $stmt->execute();
                  }

           }catch(PDOException $e){
             echo $e->getMessage();
           }
      }
    }

-1

尼斯链接:

PHP单一文件上载具有各种基本解释

通过验证上传PHP文件

PHP带有验证的多个文件上传单击此处下载源代码

使用ProgressBar和验证上传PHP / jQuery多个文件(单击此处下载源代码)

如何在PHP中上传文件并在MySql数据库中存储(单击此处以下载源代码)

extract($_POST);
    $error=array();
    $extension=array("jpeg","jpg","png","gif");
    foreach($_FILES["files"]["tmp_name"] as $key=>$tmp_name)
            {
                $file_name=$_FILES["files"]["name"][$key];
                $file_tmp=$_FILES["files"]["tmp_name"][$key];
                $ext=pathinfo($file_name,PATHINFO_EXTENSION);
                if(in_array($ext,$extension))
                {
                    if(!file_exists("photo_gallery/".$txtGalleryName."/".$file_name))
                    {
                        move_uploaded_file($file_tmp=$_FILES["files"]["tmp_name"][$key],"photo_gallery/".$txtGalleryName."/".$file_name);
                    }
                    else
                    {
                        $filename=basename($file_name,$ext);
                        $newFileName=$filename.time().".".$ext;
                        move_uploaded_file($file_tmp=$_FILES["files"]["tmp_name"][$key],"photo_gallery/".$txtGalleryName."/".$newFileName);
                    }
                }
                else
                {
                    array_push($error,"$file_name, ");
                }
            }

并且您必须检查您的HTML代码

<form action="create_photo_gallery.php" method="post" enctype="multipart/form-data">
    <table width="100%">
        <tr>
            <td>Select Photo (one or multiple):</td>
            <td><input type="file" name="files[]" multiple/></td>
        </tr>
        <tr>
            <td colspan="2" align="center">Note: Supported image format: .jpeg, .jpg, .png, .gif</td>
        </tr>
        <tr>
            <td colspan="2" align="center"><input type="submit" value="Create Gallery" id="selectedButton"/></td>
        </tr>
    </table>
</form>

尼斯链接:

PHP单一文件上载具有各种基本解释

通过验证上传PHP文件

PHP带有验证的多个文件上传单击此处下载源代码

使用ProgressBar和验证上传PHP / jQuery多个文件(单击此处下载源代码)

如何在PHP中上传文件并在MySql数据库中存储(单击此处以下载源代码)

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