带有Alamofire正文的简单字符串的POST请求


84

在iOS应用中,如何使用Alamofire在HTTP正文中使用简单字符串发送POST请求?

默认情况下,Alamofire需要用于请求的参数:

Alamofire.request(.POST, "http://mywebsite.com/post-request", parameters: ["foo": "bar"])

这些参数包含键值对。但是我不想在HTTP正文中发送带有键值字符串的请求。

我的意思是这样的:

Alamofire.request(.POST, "http://mywebsite.com/post-request", body: "myBodyString")

Answers:


88

您的示例Alamofire.request(.POST, "http://mywebsite.com/post-request", parameters: ["foo": "bar"])已经包含“ foo = bar”字符串作为其主体。但是,如果您真的要使用自定义格式的字符串。你可以这样做:

Alamofire.request(.POST, "http://mywebsite.com/post-request", parameters: [:], encoding: .Custom({
            (convertible, params) in
            var mutableRequest = convertible.URLRequest.copy() as NSMutableURLRequest
            mutableRequest.HTTPBody = "myBodyString".dataUsingEncoding(NSUTF8StringEncoding, allowLossyConversion: false)
            return (mutableRequest, nil)
        }))

注意:parameters不应该nil

更新(Alamofire 4.0,Swift 3.0):

在Alamofire 4.0中,API已更改。因此,对于自定义编码,我们需要符合ParameterEncoding协议的值/对象。

extension String: ParameterEncoding {

    public func encode(_ urlRequest: URLRequestConvertible, with parameters: Parameters?) throws -> URLRequest {
        var request = try urlRequest.asURLRequest()
        request.httpBody = data(using: .utf8, allowLossyConversion: false)
        return request
    }

}

Alamofire.request("http://mywebsite.com/post-request", method: .post, parameters: [:], encoding: "myBody", headers: [:])

这不仅适用于简单的JSON类型映射字符串,而且适用于所有类型的JSON字符串。
萨希尔·卡普尔

拯救了我的一天:)谢谢(y)
ishhhh 2015年

1
@silmaril在我的情况下,只有使用PUT方法时,我才能从后端获取原始请求,请您帮我,为什么POST请求看不到任何东西
AJ

1
.Alamofire 4 Swift 3中不再提供自定义功能,我无法找到替代方法,有任何提示吗?
Raheel Sadiq

@Silmaril我贴出的问题太多,请回答这个问题,所以我可以关闭它:stackoverflow.com/questions/39573514/...
Raheel萨迪克

64

你可以这样做:

  1. 我创建了一个单独的请求Alamofire对象。
  2. 将字符串转换为数据
  3. 将数据放入httpBody

    var request = URLRequest(url: URL(string: url)!)
    request.httpMethod = HTTPMethod.post.rawValue
    request.setValue("application/json", forHTTPHeaderField: "Content-Type")
    
    let pjson = attendences.toJSONString(prettyPrint: false)
    let data = (pjson?.data(using: .utf8))! as Data
    
    request.httpBody = data
    
    Alamofire.request(request).responseJSON { (response) in
    
    
        print(response)
    
    }
    

5
这应该是公认的答案。它很简单,可以完全满足需要,并且没有不必要的扩展或转换。谢啦。
西藏沿海地区

2
附注:我已经“借用”了您的另一个问题的答案-stackoverflow.com/a/42411188/362305
西藏沿海地区

2
出席
人数

@SyraKozZ出席人数无关紧要,唯一重要的是pjson是json字符串。您可以在其中放置任何json字符串。
afrodev

13

如果您使用Alamofire,将类型编码为“ URLEncoding.httpBody”就足够了

这样,尽管您在代码中将其定义为json,也可以将数据作为字符串在httpbody中发送。

它对我有用。

更新于

  var url = "http://..."
    let _headers : HTTPHeaders = ["Content-Type":"application/x-www-form-urlencoded"]
    let params : Parameters = ["grant_type":"password","username":"mail","password":"pass"]

    let url =  NSURL(string:"url" as String)

    request(url, method: .post, parameters: params, encoding: URLEncoding.httpBody , headers: _headers).responseJSON(completionHandler: {
        response in response

        let jsonResponse = response.result.value as! NSDictionary

        if jsonResponse["access_token"] != nil
        {
            access_token = String(describing: jsonResponse["accesstoken"]!)

        }

    })

1
我会更新我的回答,写一个使用的代码,因为我无法找到如何编写代码从这里评论..对不起,我迟到@巴德尔菲拉利。
杰马尔BAYRI

非常感谢
Badr Filali

1
为我工作,但我的身体需要为JSON,因此,我将编码:URLEncoding.httpBody更改为编码:JSONEncoding.default,一切正常。
恩戈洛·波洛托

是的@AngeloPolotto感谢您的构造:)这是关于服务类型的编码。可以根据您的其他api用作URLEncoding或JSONEncoding。
Cemal BAYRI '18

谢谢你的回答。但是我面临的问题是当我发送变量而不是double quotes strings并获得错误代码时400。我该如何解决?
毒蛇

8

我修改了@Silmaril的答案以扩展Alamofire的Manager。此解决方案使用EVReflection直接序列化对象:

//Extend Alamofire so it can do POSTs with a JSON body from passed object
extension Alamofire.Manager {
    public class func request(
        method: Alamofire.Method,
        _ URLString: URLStringConvertible,
          bodyObject: EVObject)
        -> Request
    {
        return Manager.sharedInstance.request(
            method,
            URLString,
            parameters: [:],
            encoding: .Custom({ (convertible, params) in
                let mutableRequest = convertible.URLRequest.copy() as! NSMutableURLRequest
                mutableRequest.HTTPBody = bodyObject.toJsonString().dataUsingEncoding(NSUTF8StringEncoding, allowLossyConversion: false)
                return (mutableRequest, nil)
            })
        )
    }
}

然后,您可以像这样使用它:

Alamofire.Manager.request(.POST, endpointUrlString, bodyObject: myObjectToPost)

5

如果要在请求中将字符串作为原始正文发布

return Alamofire.request(.POST, "http://mywebsite.com/post-request" , parameters: [:], encoding: .Custom({
            (convertible, params) in
            let mutableRequest = convertible.URLRequest.copy() as! NSMutableURLRequest

            let data = ("myBodyString" as NSString).dataUsingEncoding(NSUTF8StringEncoding)
            mutableRequest.HTTPBody = data
            return (mutableRequest, nil)
        }))

嗨,JITHINRAJ,我在这里stackoverflow.com/questions/40385992/…发表了一个问题。我想发送一个xml正文
mike vorisis,2016年

5

我已经完成了从字符串数组。调整此解决方案以适应琴弦。

来自Alamofire 4的“本地”方式:

struct JSONStringArrayEncoding: ParameterEncoding {
    private let myString: String

    init(string: String) {
        self.myString = string
    }

    func encode(_ urlRequest: URLRequestConvertible, with parameters: Parameters?) throws -> URLRequest {
        var urlRequest = urlRequest.urlRequest

        let data = myString.data(using: .utf8)!

        if urlRequest?.value(forHTTPHeaderField: "Content-Type") == nil {
            urlRequest?.setValue("application/json", forHTTPHeaderField: "Content-Type")
        }

        urlRequest?.httpBody = data

        return urlRequest!
    }
}

然后通过以下方式提出您的请求:

Alamofire.request("your url string", method: .post, parameters: [:], encoding: JSONStringArrayEncoding.init(string: "My string for body"), headers: [:])

4

我已经使用@afrodev的答案作为参考。就我而言,我将函数参数作为必须在请求中发布的字符串。所以,这是代码:

func defineOriginalLanguage(ofText: String) {
    let text =  ofText
    let stringURL = basicURL + "identify?version=2018-05-01"
    let url = URL(string: stringURL)

    var request = URLRequest(url: url!)
    request.httpMethod = HTTPMethod.post.rawValue
    request.setValue("text/plain", forHTTPHeaderField: "Content-Type")
    request.httpBody = text.data(using: .utf8)

    Alamofire.request(request)
        .responseJSON { response in
            print(response)
    }
}

你到底得到了什么?
GeoSD '18

3

基于Illya Krit的答案

细节

  • Xcode版本10.2.1(10E1001)
  • 迅捷5
  • Alamofire 4.8.2

import Alamofire

struct BodyStringEncoding: ParameterEncoding {

    private let body: String

    init(body: String) { self.body = body }

    func encode(_ urlRequest: URLRequestConvertible, with parameters: Parameters?) throws -> URLRequest {
        guard var urlRequest = urlRequest.urlRequest else { throw Errors.emptyURLRequest }
        guard let data = body.data(using: .utf8) else { throw Errors.encodingProblem }
        urlRequest.httpBody = data
        return urlRequest
    }
}

extension BodyStringEncoding {
    enum Errors: Error {
        case emptyURLRequest
        case encodingProblem
    }
}

extension BodyStringEncoding.Errors: LocalizedError {
    var errorDescription: String? {
        switch self {
            case .emptyURLRequest: return "Empty url request"
            case .encodingProblem: return "Encoding problem"
        }
    }
}

用法

Alamofire.request(url, method: .post, parameters: nil, encoding: BodyStringEncoding(body: text), headers: headers).responseJSON { response in
     print(response)
}

Спасибовамбольшое!
ИсмаилХасбулатов

2
func paramsFromJSON(json: String) -> [String : AnyObject]?
{
    let objectData: NSData = (json.dataUsingEncoding(NSUTF8StringEncoding))!
    var jsonDict: [ String : AnyObject]!
    do {
        jsonDict = try NSJSONSerialization.JSONObjectWithData(objectData, options: .MutableContainers) as! [ String : AnyObject]
        return jsonDict
    } catch {
        print("JSON serialization failed:  \(error)")
        return nil
    }
}

let json = Mapper().toJSONString(loginJSON, prettyPrint: false)

Alamofire.request(.POST, url + "/login", parameters: paramsFromJSON(json!), encoding: .JSON)

什么是Mapper?
Ahmadreza

2

我的案例,发布的Alamofire的内容类型为:“ Content-Type”:“ application / x-www-form-urlencoded”,我不得不更改alampfire发布请求的编码

从:JSONENCODING.DEFAULT到:URLEncoding.httpBody

这里:

let url = ServicesURls.register_token()
    let body = [
        "UserName": "Minus28",
        "grant_type": "password",
        "Password": "1a29fcd1-2adb-4eaa-9abf-b86607f87085",
         "DeviceNumber": "e9c156d2ab5421e5",
          "AppNotificationKey": "test-test-test",
        "RegistrationEmail": email,
        "RegistrationPassword": password,
        "RegistrationType": 2
        ] as [String : Any]


    Alamofire.request(url, method: .post, parameters: body, encoding: URLEncoding.httpBody , headers: setUpHeaders()).log().responseJSON { (response) in

0
let parameters = ["foo": "bar"]
              
    // All three of these calls are equivalent
    AF.request("https://httpbin.org/post", method: .post, parameters: parameters)
    AF.request("https://httpbin.org/post", method: .post, parameters: parameters, encoder: URLEncodedFormParameterEncoder.default)
    AF.request("https://httpbin.org/post", method: .post, parameters: parameters, encoder: URLEncodedFormParameterEncoder(destination: .httpBody))
    
    

-3

Xcode 8.X,Swift 3.X

易于使用;

 let params:NSMutableDictionary? = ["foo": "bar"];
            let ulr =  NSURL(string:"http://mywebsite.com/post-request" as String)
            let request = NSMutableURLRequest(url: ulr! as URL)
            request.httpMethod = "POST"
            request.setValue("application/json", forHTTPHeaderField: "Content-Type")
            let data = try! JSONSerialization.data(withJSONObject: params!, options: JSONSerialization.WritingOptions.prettyPrinted)

            let json = NSString(data: data, encoding: String.Encoding.utf8.rawValue)
            if let json = json {
                print(json)
            }
            request.httpBody = json!.data(using: String.Encoding.utf8.rawValue);


            Alamofire.request(request as! URLRequestConvertible)
                .responseJSON { response in
                    // do whatever you want here
                   print(response.request)  
                   print(response.response) 
                   print(response.data) 
                   print(response.result)

            }
By using our site, you acknowledge that you have read and understand our Cookie Policy and Privacy Policy.
Licensed under cc by-sa 3.0 with attribution required.