Swift 5提供了许多从相似对象数组中获取属性值数组的方法。根据您的需要,您可以选择以下六个Playground代码示例之一来解决您的问题。
1.使用map
方法
使用Swift,符合Sequence
协议的类型具有map(_:)
方法。以下示例代码显示了如何使用它:
class Employee {
let id: Int, firstName: String, lastName: String
init(id: Int, firstName: String, lastName: String) {
self.id = id
self.firstName = firstName
self.lastName = lastName
}
}
let employeeArray = [
Employee(id: 1, firstName: "Jon", lastName: "Skeet"),
Employee(id: 2, firstName: "Darin", lastName: "Dimitrov"),
Employee(id: 4, firstName: "Hans", lastName: "Passant")
]
let idArray = employeeArray.map({ (employee: Employee) -> Int in
employee.id
})
// let idArray = employeeArray.map { $0.id } // also works
print(idArray) // prints [1, 2, 4]
2.使用for
循环
class Employee {
let id: Int, firstName: String, lastName: String
init(id: Int, firstName: String, lastName: String) {
self.id = id
self.firstName = firstName
self.lastName = lastName
}
}
let employeeArray = [
Employee(id: 1, firstName: "Jon", lastName: "Skeet"),
Employee(id: 2, firstName: "Darin", lastName: "Dimitrov"),
Employee(id: 4, firstName: "Hans", lastName: "Passant")
]
var idArray = [Int]()
for employee in employeeArray {
idArray.append(employee.id)
}
print(idArray) // prints [1, 2, 4]
3.使用while
循环
请注意,在Swift的幕后,for
循环只是while
在sequence
迭代器上的循环(有关更多详细信息,请参见IteratorProtocol)。
class Employee {
let id: Int, firstName: String, lastName: String
init(id: Int, firstName: String, lastName: String) {
self.id = id
self.firstName = firstName
self.lastName = lastName
}
}
let employeeArray = [
Employee(id: 1, firstName: "Jon", lastName: "Skeet"),
Employee(id: 2, firstName: "Darin", lastName: "Dimitrov"),
Employee(id: 4, firstName: "Hans", lastName: "Passant")
]
var idArray = [Int]()
var iterator = employeeArray.makeIterator()
while let employee = iterator.next() {
idArray.append(employee.id)
}
print(idArray) // prints [1, 2, 4]
4.使用struct
符合IteratorProtocol
和Sequence
协议的
class Employee {
let id: Int, firstName: String, lastName: String
init(id: Int, firstName: String, lastName: String) {
self.id = id
self.firstName = firstName
self.lastName = lastName
}
}
struct EmployeeSequence: Sequence, IteratorProtocol {
let employeeArray: [Employee]
private var index = 0
init(employeeArray: [Employee]) {
self.employeeArray = employeeArray
}
mutating func next() -> Int? {
guard index < employeeArray.count else { return nil }
defer { index += 1 }
return employeeArray[index].id
}
}
let employeeArray = [
Employee(id: 1, firstName: "Jon", lastName: "Skeet"),
Employee(id: 2, firstName: "Darin", lastName: "Dimitrov"),
Employee(id: 4, firstName: "Hans", lastName: "Passant")
]
let employeeSequence = EmployeeSequence(employeeArray: employeeArray)
let idArray = Array(employeeSequence)
print(idArray) // prints [1, 2, 4]
5.使用Collection
协议扩展和AnyIterator
class Employee {
let id: Int, firstName: String, lastName: String
init(id: Int, firstName: String, lastName: String) {
self.id = id
self.firstName = firstName
self.lastName = lastName
}
}
extension Collection where Iterator.Element: Employee {
func getIDs() -> Array<Int> {
var index = startIndex
let iterator: AnyIterator<Int> = AnyIterator {
defer { index = self.index(index, offsetBy: 1) }
return index != self.endIndex ? self[index].id : nil
}
return Array(iterator)
}
}
let employeeArray = [
Employee(id: 1, firstName: "Jon", lastName: "Skeet"),
Employee(id: 2, firstName: "Darin", lastName: "Dimitrov"),
Employee(id: 4, firstName: "Hans", lastName: "Passant")
]
let idArray = employeeArray.getIDs()
print(idArray) // prints [1, 2, 4]
请注意,此示例需要class Employee
从继承NSObject
。
import Foundation
class Employee: NSObject {
@objc let id: Int, firstName: String, lastName: String
init(id: Int, firstName: String, lastName: String) {
self.id = id
self.firstName = firstName
self.lastName = lastName
}
}
let employeeArray = [
Employee(id: 1, firstName: "Jon", lastName: "Skeet"),
Employee(id: 2, firstName: "Darin", lastName: "Dimitrov"),
Employee(id: 4, firstName: "Hans", lastName: "Passant")
]
let employeeNSArray = employeeArray as NSArray
if let idArray = employeeNSArray.value(forKeyPath: #keyPath(Employee.id)) as? [Int] {
print(idArray) // prints [1, 2, 4]
}
map
这样-将的数组转换Employee
为Int
,由id
字段填充的数组。这等效于说“从所有实例中提取id字段Employee
并将它们放入数组中”