这将返回以某种类型定义的所有扩展方法的列表,包括通用方法:
public static IEnumerable<KeyValuePair<Type, MethodInfo>> GetExtensionMethodsDefinedInType(this Type t)
{
if (!t.IsSealed || t.IsGenericType || t.IsNested)
return Enumerable.Empty<KeyValuePair<Type, MethodInfo>>();
var methods = t.GetMethods(BindingFlags.Public | BindingFlags.Static)
.Where(m => m.IsDefined(typeof(ExtensionAttribute), false));
List<KeyValuePair<Type, MethodInfo>> pairs = new List<KeyValuePair<Type, MethodInfo>>();
foreach (var m in methods)
{
var parameters = m.GetParameters();
if (parameters.Length > 0)
{
if (parameters[0].ParameterType.IsGenericParameter)
{
if (m.ContainsGenericParameters)
{
var genericParameters = m.GetGenericArguments();
Type genericParam = genericParameters[parameters[0].ParameterType.GenericParameterPosition];
foreach (var constraint in genericParam.GetGenericParameterConstraints())
pairs.Add(new KeyValuePair<Type, MethodInfo>(parameters[0].ParameterType, m));
}
}
else
pairs.Add(new KeyValuePair<Type, MethodInfo>(parameters[0].ParameterType, m));
}
}
return pairs;
}
唯一的问题是:返回的类型与typeof(..)所期望的不同,因为它是通用参数类型。为了找到给定类型的所有扩展方法,您必须比较所有基本类型的GUID和Type的接口,例如:
public List<MethodInfo> GetExtensionMethodsOf(Type t)
{
List<MethodInfo> methods = new List<MethodInfo>();
Type cur = t;
while (cur != null)
{
TypeInfo tInfo;
if (typeInfo.TryGetValue(cur.GUID, out tInfo))
methods.AddRange(tInfo.ExtensionMethods);
foreach (var iface in cur.GetInterfaces())
{
if (typeInfo.TryGetValue(iface.GUID, out tInfo))
methods.AddRange(tInfo.ExtensionMethods);
}
cur = cur.BaseType;
}
return methods;
}
要完成:
我保留了一个类型信息对象的字典,该对象是在迭代所有程序集的所有类型时构建的:
private Dictionary<Guid, TypeInfo> typeInfo = new Dictionary<Guid, TypeInfo>();
其中TypeInfo
定义为:
public class TypeInfo
{
public TypeInfo()
{
ExtensionMethods = new List<MethodInfo>();
}
public List<ConstructorInfo> Constructors { get; set; }
public List<FieldInfo> Fields { get; set; }
public List<PropertyInfo> Properties { get; set; }
public List<MethodInfo> Methods { get; set; }
public List<MethodInfo> ExtensionMethods { get; set; }
}