如何快速在从JSON检索的数字中添加逗号。
Example
31908551587 to
31,908,551,587
我很困惑,我不知道该怎么办。
如何快速在从JSON检索的数字中添加逗号。
Example
31908551587 to
31,908,551,587
我很困惑,我不知道该怎么办。
Answers:
你可以做到 NSNumberFormatter
斯威夫特4
let largeNumber = 31908551587
let numberFormatter = NumberFormatter()
numberFormatter.numberStyle = .decimal
let formattedNumber = numberFormatter.string(from: NSNumber(value:largeNumber))
迅捷3
let largeNumber = 31908551587
let numberFormatter = NumberFormatter()
numberFormatter.numberStyle = NumberFormatter.Style.decimal
let formattedNumber = numberFormatter.string(from: NSNumber(value:largeNumber))
迅捷2
let largeNumber = 31908551587
let numberFormatter = NSNumberFormatter()
numberFormatter.numberStyle = NSNumberFormatterStyle.DecimalStyle
let formattedNumber = numberFormatter.stringFromNumber(largeNumber)
扩展ÖzgürErsil的答案,您可以通过扩展Int来隔离功能:
extension Int {
func withCommas() -> String {
let numberFormatter = NumberFormatter()
numberFormatter.numberStyle = .decimal
return numberFormatter.string(from: NSNumber(value:self))!
}
}
然后在您的代码上使用以下代码:
largeNumber.withCommas()
在扩展胡安·弗兰·希门尼斯的答案的同时,我建议将格式化程序置于单例中,因为实例化格式化程序通常是相对昂贵的操作。(如果您要在用户写操作时进行格式化,这可能会影响性能。)
extension Int {
private static var commaFormatter: NumberFormatter = {
let formatter = NumberFormatter()
formatter.numberStyle = .decimal
return formatter
}()
internal var commaRepresentation: String {
return Int.commaFormatter.string(from: NSNumber(value: self)) ?? ""
}
}
一个简单的扩展名下降,它将通过扩展名提供一个变量Int
。
正如朱利安(Julien)的回答所述,出于性能原因,此方法使用了静态格式化程序。
extension Int {
private static var numberFormatter: NumberFormatter = {
let numberFormatter = NumberFormatter()
numberFormatter.numberStyle = .decimal
return numberFormatter
}()
var delimiter: String {
return Int.numberFormatter.string(from: NSNumber(value: self)) ?? ""
}
}
要使用它:
let number = 31908551587
print(number.delimiter) // 31,908,551,587
internal var
而你只有var
。您的答案对对话有什么帮助?另外,我会说您的变量delimiter
具有误导性。Julien'scommaRepresentation
有用得多。
这是设置逗号位置的另一种方法。假设我希望将数字10000000打印为“ 1,00,00,000”
let numberFormatter = NumberFormatter()
numberFormatter.numberStyle = .decimal
numberFormatter.groupingSize = 3
numberFormatter.secondaryGroupingSize = 2
numberFormatter.string(from: 10000000)
我为金额文本字段创建了一个类。只需将其设置为您的textfield类。例如,输入1234567。它将转换为1,234,567。也适用于十进制输入,十进制后为两位。
class AmountField: UITextField {
private var isFirstDecimal : Bool = true
override func willMove(toSuperview newSuperview: UIView?) {
addTarget(self, action: #selector(editingChanged), for: .editingChanged)
keyboardType = .decimalPad
textAlignment = .left
placeholder = "0.0"
editingChanged()
}
override func deleteBackward() {
var currentText = self.text ?? ""
currentText = String(currentText.dropLast())
self.text = currentText
editingChanged(self)
}
@objc func editingChanged(_ textField: UITextField? = nil) {
var doubleStr = textField?.text ?? "00"
let decimalCount = doubleStr.components(separatedBy: ".")
if decimalCount.count > 2 {
var currentText = self.text ?? ""
currentText = String(currentText.dropLast())
self.text = currentText
return
}
if doubleStr.contains(".") && isFirstDecimal == true {
self.text = doubleStr
isFirstDecimal = false
return
}
else if !(doubleStr.contains(".")) {
isFirstDecimal = true
}
let doubleStrTemp = doubleStr.replacingOccurrences(of: ",", with: "")
if doubleStrTemp != "" {
if let n = Decimal(string: doubleStrTemp )?.significantFractionalDecimalDigits {
if n > 2 {
var currentText = self.text ?? ""
currentText = String(currentText.dropLast())
self.text = currentText
return
}
}
}
doubleStr = doubleStr.replacingOccurrences(of: ",", with: "")
let doube = Double(doubleStr)
let numberFormatter = NumberFormatter()
numberFormatter.numberStyle = NumberFormatter.Style.decimal
if doube != nil {
let formattedNumber = numberFormatter.string(from: NSNumber(value:doube!))
self.text = formattedNumber
}
}}
extension Decimal {
var significantFractionalDecimalDigits: Int {
return max(-exponent, 0)
}}