我们能否拥有一个SQL查询,该查询基本上可以帮助查看SQl Server中的表和索引大小。
SQL Server如何维护表/索引的内存使用情况?
我们能否拥有一个SQL查询,该查询基本上可以帮助查看SQl Server中的表和索引大小。
SQL Server如何维护表/索引的内存使用情况?
Answers:
在exec sp_spaceused
无参数显示为整个数据库中的概要。foreachtable解决方案为每个表生成一个结果集-如果表太多,SSMS可能无法处理该结果集。
我创建了一个脚本,该脚本通过收集表信息sp_spaceused
并在单个记录集中显示摘要,并按大小排序。
create table #t
(
name nvarchar(128),
rows varchar(50),
reserved varchar(50),
data varchar(50),
index_size varchar(50),
unused varchar(50)
)
declare @id nvarchar(128)
declare c cursor for
select '[' + sc.name + '].[' + s.name + ']' FROM sysobjects s INNER JOIN sys.schemas sc ON s.uid = sc.schema_id where s.xtype='U'
open c
fetch c into @id
while @@fetch_status = 0 begin
insert into #t
exec sp_spaceused @id
fetch c into @id
end
close c
deallocate c
select * from #t
order by convert(int, substring(data, 1, len(data)-3)) desc
drop table #t
#
。
sp_spaceused提供了所有合并索引的大小。
如果您想要一个表的每个索引的大小,请使用以下两个查询之一:
SELECT
i.name AS IndexName,
SUM(s.used_page_count) * 8 AS IndexSizeKB
FROM sys.dm_db_partition_stats AS s
JOIN sys.indexes AS i
ON s.[object_id] = i.[object_id] AND s.index_id = i.index_id
WHERE s.[object_id] = object_id('dbo.TableName')
GROUP BY i.name
ORDER BY i.name
SELECT
i.name AS IndexName,
SUM(page_count * 8) AS IndexSizeKB
FROM sys.dm_db_index_physical_stats(
db_id(), object_id('dbo.TableName'), NULL, NULL, 'DETAILED') AS s
JOIN sys.indexes AS i
ON s.[object_id] = i.[object_id] AND s.index_id = i.index_id
GROUP BY i.name
ORDER BY i.name
结果通常略有不同,但在1%以内。
Msg 102, Level 15, State 1, Line 5 - Incorrect syntax near '('.
了我,但是我看不到语法有任何问题。任何想法?
--Gets the size of each index for the specified table
DECLARE @TableName sysname = N'SomeTable';
SELECT i.name AS IndexName
,8 * SUM(s.used_page_count) AS IndexSizeKB
FROM sys.indexes AS i
INNER JOIN sys.dm_db_partition_stats AS s
ON i.[object_id] = s.[object_id] AND i.index_id = s.index_id
WHERE s.[object_id] = OBJECT_ID(@TableName, N'U')
GROUP BY i.name
ORDER BY i.name;
SELECT i.name AS IndexName
,8 * SUM(a.used_pages) AS IndexSizeKB
FROM sys.indexes AS i
INNER JOIN sys.partitions AS p
ON i.[object_id] = p.[object_id] AND i.index_id = p.index_id
INNER JOIN sys.allocation_units AS a
ON p.partition_id = a.container_id
WHERE i.[object_id] = OBJECT_ID(@TableName, N'U')
GROUP BY i.name
ORDER BY i.name;
这是最成功答案的更紧凑的版本:
create table #tbl(
name nvarchar(128),
rows varchar(50),
reserved varchar(50),
data varchar(50),
index_size varchar(50),
unused varchar(50)
)
exec sp_msforeachtable 'insert into #tbl exec sp_spaceused [?]'
select * from #tbl
order by convert(int, substring(data, 1, len(data)-3)) desc
drop table #tbl
自从创建此帖子以来已经有很长时间了,但是我想分享我的脚本:
WITH CteIndex
AS
(
SELECT
reservedpages = (reserved_page_count)
,usedpages = (used_page_count)
,pages = (
CASE
WHEN (s.index_id < 2) THEN (in_row_data_page_count + lob_used_page_count + row_overflow_used_page_count)
ELSE lob_used_page_count + row_overflow_used_page_count
END
)
,s.object_id
,i.index_id
,i.type_desc AS IndexType
,i.name AS indexname
FROM sys.dm_db_partition_stats s
INNER JOIN sys.indexes i ON s.[object_id] = i.[object_id] AND s.index_id = i.index_id
)
SELECT DISTINCT
DB_NAME(DB_ID()) AS DatabaseName
,o.name AS TableName
,o.object_id
,ct.indexname
,ct.IndexType
,ct.index_id
, IndexSpace = LTRIM (STR ((CASE WHEN usedpages > pages THEN CASE WHEN ct.index_id < 2 THEN pages ELSE (usedpages - pages) END ELSE 0 END) * 8, 15, 0) + ' KB')
FROM CteIndex ct
INNER JOIN sys.objects o ON o.object_id = ct.object_id
INNER JOIN sys.dm_db_index_physical_stats (DB_ID(), NULL, NULL, NULL , NULL) ps ON ps.object_id = o.object_id
AND ps.index_id = ct.index_id
ORDER BY name ASC
它适用于:
有一个扩展的存储过程sp_spaceused
可以获取此信息。从数据字典执行此操作相当费时,但是此链接会扩展到执行此操作的脚本。 这个stackoverflow问题对基础数据结构的信息有一些扇出,您可以使用这些数据来构造用于容量规划的表和索引大小的估计。
该查询来自其他两个答案:
,但我将其增强为通用。它使用sys.objects
字典:
SELECT
s.NAME as SCHEMA_NAME,
t.NAME AS OBJ_NAME,
t.type_desc as OBJ_TYPE,
i.name as indexName,
sum(p.rows) as RowCounts,
sum(a.total_pages) as TotalPages,
sum(a.used_pages) as UsedPages,
sum(a.data_pages) as DataPages,
(sum(a.total_pages) * 8) / 1024 as TotalSpaceMB,
(sum(a.used_pages) * 8) / 1024 as UsedSpaceMB,
(sum(a.data_pages) * 8) / 1024 as DataSpaceMB
FROM
sys.objects t
INNER JOIN
sys.schemas s ON t.SCHEMA_ID = s.SCHEMA_ID
INNER JOIN
sys.indexes i ON t.OBJECT_ID = i.object_id
INNER JOIN
sys.partitions p ON i.object_id = p.OBJECT_ID AND i.index_id = p.index_id
INNER JOIN
sys.allocation_units a ON p.partition_id = a.container_id
WHERE
t.NAME NOT LIKE 'dt%' AND
i.OBJECT_ID > 255 AND
i.index_id <= 1
GROUP BY
s.NAME, t.NAME, t.type_desc, i.object_id, i.index_id, i.name
ORDER BY
sum(a.total_pages) DESC
;
sp_helpdb
有用