删除ID与另一个表不匹配的SQL行

我正在尝试删除mysql表中的孤立条目。

我有2张桌子，像这样：

表files：

| id | ....
------------
| 1  | ....
| 2  | ....
| 7  | ....
| 9  | ....

表blob：

| fileid | ....
------------
| 1  | ....
| 2  | ....
| 3  | ....
| 4  | ....
| 4  | ....
| 4  | ....
| 9  | ....

该fileid和id列可以被用来连接表在一起。

我想删除表blob中所有在表中fileid找不到的行files.id。

因此，使用上面的示例将删除表中的行：3＆4（s）blob。

使用LEFT JOIN / IS NULL：

DELETE b FROM BLOB b 
  LEFT JOIN FILES f ON f.id = b.fileid 
      WHERE f.id IS NULL

使用不存在：

DELETE FROM BLOB 
 WHERE NOT EXISTS(SELECT NULL
                    FROM FILES f
                   WHERE f.id = fileid)

使用NOT IN：

DELETE FROM BLOB
 WHERE fileid NOT IN (SELECT f.id 
                        FROM FILES f)

警告

只要有可能，就在事务中执行DELETE（假设受支持-IE：不在MyISAM上），以便在出现问题时可以使用回滚来还原更改。

DELETE FROM blob 
WHERE fileid NOT IN 
       (SELECT id 
        FROM files 
        WHERE id is NOT NULL/*This line is unlikely to be needed 
                               but using NOT IN...*/
      )

DELETE FROM blob
WHERE NOT EXISTS (
    SELECT *
    FROM files
    WHERE id=blob.id
)

delete from table1 t1 
    WHERE not exists (select id from table2 where related_field_in_t2=t1.id) 
    AND not exists (select id from table3 where related_field_in_t3=t1.id) 
    AND not exists (select id from table4 where related_field_t4=t1.id) 
    AND not exists (select id from table5 where related_field_t5=t1.id);