试试这个我曾经理解过的await
/async
有希望的测试程序。
程序#1:不保证不会按顺序运行
function functionA() {
console.log('functionA called');
setTimeout(function() {
console.log('functionA timeout called');
return 10;
}, 15000);
}
function functionB(valueA) {
console.log('functionB called');
setTimeout(function() {
console.log('functionB timeout called = ' + valueA);
return 20 + valueA;
}, 10000);
}
function functionC(valueA, valueB) {
console.log('functionC called');
setTimeout(function() {
console.log('functionC timeout called = ' + valueA);
return valueA + valueB;
}, 10000);
}
async function executeAsyncTask() {
const valueA = await functionA();
const valueB = await functionB(valueA);
return functionC(valueA, valueB);
}
console.log('program started');
executeAsyncTask().then(function(response) {
console.log('response called = ' + response);
});
console.log('program ended');
计划2:承诺
function functionA() {
return new Promise((resolve, reject) => {
console.log('functionA called');
setTimeout(function() {
console.log('functionA timeout called');
return resolve(10);
}, 15000);
});
}
function functionB(valueA) {
return new Promise((resolve, reject) => {
console.log('functionB called');
setTimeout(function() {
console.log('functionB timeout called = ' + valueA);
return resolve(20 + valueA);
}, 10000);
});
}
function functionC(valueA, valueB) {
return new Promise((resolve, reject) => {
console.log('functionC called');
setTimeout(function() {
console.log('functionC timeout called = ' + valueA);
return resolve(valueA + valueB);
}, 10000);
});
}
async function executeAsyncTask() {
const valueA = await functionA();
const valueB = await functionB(valueA);
return functionC(valueA, valueB);
}
console.log('program started');
executeAsyncTask().then(function(response) {
console.log('response called = ' + response);
});
console.log('program ended');