如何水平打印数组的内容？

Question 1

为什么控制台窗口不水平而不是垂直打印阵列内容？

有办法改变吗？

如何使用a而不是垂直显示数组内容Console.WriteLine()？

例如：

int[] numbers = new int[100]
for(int i; i < 100; i++)
{
    numbers[i] = i;
}

for (int i; i < 100; i++)
{
    Console.WriteLine(numbers[i]);
}

Question 2

您可能正在使用Console.WriteLine打印阵列。

int[] array = new int[] { 1, 2, 3 };
foreach(var item in array)
{
    Console.WriteLine(item.ToString());
}

如果您不想将所有项目都放在单独的行中，请使用Console.Write：

int[] array = new int[] { 1, 2, 3 };
foreach(var item in array)
{
    Console.Write(item.ToString());
}

或string.Join<T>（在.NET Framework 4或更高版本中）：

int[] array = new int[] { 1, 2, 3 };
Console.WriteLine(string.Join(",", array));

Question 3

我会建议：

foreach(var item in array)
  Console.Write("{0}", item);

如上所述，但如果一项是，则不会引发例外null。

Console.Write(string.Join(" ", array));

如果数组是一个将是完美的string[]。

Question 4

只需遍历数组，然后使用Write而不是将项目写入控制台WriteLine：

foreach(var item in array)
    Console.Write(item.ToString() + " ");

只要您的商品没有换行符，就会产生一行。

...或者，如乔恩·斯基特（Jon Skeet）所说，为您的问题提供了更多背景信息。

Question 5

如果您需要漂亮地打印数组数组，则可以使用以下方法：.NET C＃中的漂亮打印数组数组

public string PrettyPrintArrayOfArrays(int[][] arrayOfArrays)
{
  if (arrayOfArrays == null)
    return "";

  var prettyArrays = new string[arrayOfArrays.Length];

  for (int i = 0; i < arrayOfArrays.Length; i++)
  {
    prettyArrays[i] = "[" + String.Join(",", arrayOfArrays[i]) + "]";
  }

  return "[" + String.Join(",", prettyArrays) + "]";
}

示例输出：

[[2,3]]

[[2,3],[5,4,3]]

[[2,3],[5,4,3],[8,9]]

Question 6

foreach(var item in array)
Console.Write(item.ToString() + "\t");

Question 7

namespace ReverseString
{
    class Program
    {
        static void Main(string[] args)
        {
            string stat = "This is an example of code" +
                          "This code has written in C#\n\n";

            Console.Write(stat);

            char[] myArrayofChar = stat.ToCharArray();

            Array.Reverse(myArrayofChar);

            foreach (char myNewChar in myArrayofChar)
                Console.Write(myNewChar); // You just need to write the function
                                          // Write instead of WriteLine
            Console.ReadKey();
        }
    }
}

这是输出：

#C ni nettirw sah edoc sihTedoc fo elpmaxe na si sihT

Question 8

以下解决方案是最简单的解决方案：

Console.WriteLine("[{0}]", string.Join(", ", array));

输出： [1, 2, 3, 4, 5]

另一个简短的解决方案：

Array.ForEach(array,  val => Console.Write("{0} ", val));

输出：1 2 3 4 5。或者，如果您需要添加add ,，请使用以下命令：

int i = 0;
Array.ForEach(array,  val => Console.Write(i == array.Length -1) ? "{0}" : "{0}, ", val));

输出： 1, 2, 3, 4, 5

Question 9

int[] n=new int[5];

for (int i = 0; i < 5; i++)
{
    n[i] = i + 100;
}

foreach (int j in n)
{
    int i = j - 100;

    Console.WriteLine("Element [{0}]={1}", i, j);
    i++;
}

Question 10

public static void Main(string[] args)
{
    int[] numbers = new int[10];

    Console.Write("index ");

    for (int i = 0; i < numbers.Length; i++)
    {
        numbers[i] = i;
        Console.Write(numbers[i] + " ");
    }

    Console.WriteLine("");
    Console.WriteLine("");
    Console.Write("value ");

    for (int i = 0; i < numbers.Length; i++)
    {
        numbers[i] = numbers.Length - i;
        Console.Write(numbers[i] + " ");
    }

    Console.ReadKey();
}

Question 11

仅当该线程是唯一写入控制台的线程时，才能使用Console.Write，否则您的输出可能会与可能插入或未插入换行符的其他输出以及其他不需要的字符散布。为确保完整打印阵列，请使用Console.WriteLine写入一个字符串。使用.NET 4.0之前可用的非通用Join，大多数对象数组都可以水平打印（取决于类型的ToString（）方法）：

        int[] numbers = new int[100];
        for(int i= 0; i < 100; i++)
        {
            numbers[i] = i;
        }

        //For clarity
        IEnumerable strings = numbers.Select<int, string>(j=>j.ToString());
        string[] stringArray = strings.ToArray<string>();
        string output = string.Join(", ", stringArray);
        Console.WriteLine(output);

        //OR 

        //For brevity
        Console.WriteLine(string.Join(", ", numbers.Select<int, string>(j => j.ToString()).ToArray<string>()));

Question 12

我已经写了一些扩展以适应几乎所有需求。
使用Separator，String.Format和IFormatProvider可以扩展扩展名。

例：

var array1 = new byte[] { 50, 51, 52, 53 };
var array2 = new double[] { 1.1111, 2.2222, 3.3333 };
var culture = CultureInfo.GetCultureInfo("ja-JP");

Console.WriteLine("Byte Array");
//Normal print 
Console.WriteLine(array1.StringJoin());
//Format to hex values
Console.WriteLine(array1.StringJoin("-", "0x{0:X2}"));
//Comma separated 
Console.WriteLine(array1.StringJoin(", "));
Console.WriteLine();

Console.WriteLine("Double Array");
//Normal print 
Console.WriteLine(array2.StringJoin());
//Format to Japanese culture
Console.WriteLine(array2.StringJoin(culture));
//Format to three decimals 
Console.WriteLine(array2.StringJoin(" ", "{0:F3}"));
//Format to Japanese culture and two decimals
Console.WriteLine(array2.StringJoin(" ", "{0:F2}", culture));
Console.WriteLine();

Console.ReadLine();

扩充功能：

using System;
using System.Collections;
using System.Collections.Generic;
using System.Globalization;
using System.Linq;
using System.Text;
using System.Threading.Tasks;

namespace Extensions
{
    /// <summary>
    /// IEnumerable Utilities. 
    /// </summary>
    public static partial class IEnumerableUtilities
    {
        /// <summary>
        /// String.Join collection of items using custom Separator, String.Format and FormatProvider. 
        /// </summary>
        public static string StringJoin<T>(this IEnumerable<T> Source)
        {
            return Source.StringJoin(" ", string.Empty, null);
        }

        /// <summary>
        /// String.Join collection of items using custom Separator, String.Format and FormatProvider. 
        /// </summary>
        public static string StrinJoin<T>(this IEnumerable<T> Source, string Separator)
        {
            return Source.StringJoin(Separator, string.Empty, null);
        }

        /// <summary>
        /// String.Join collection of items using custom Separator, String.Format and FormatProvider. 
        /// </summary>
        public static string StringJoin<T>(this IEnumerable<T> Source, string Separator, string StringFormat)
        {
            return Source.StringJoin(Separator, StringFormat, null);
        }

        /// <summary>
        /// String.Join collection of items using custom Separator, String.Format and FormatProvider. 
        /// </summary>
        public static string StringJoin<T>(this IEnumerable<T> Source, string Separator, IFormatProvider FormatProvider)
        {
            return Source.StringJoin(Separator, string.Empty, FormatProvider);
        }

        /// <summary>
        /// String.Join collection of items using custom Separator, String.Format and FormatProvider. 
        /// </summary>
        public static string StringJoin<T>(this IEnumerable<T> Source, IFormatProvider FormatProvider)
        {
            return Source.StringJoin(" ", string.Empty, FormatProvider);
        }

        /// <summary>
        /// String.Join collection of items using custom Separator, String.Format and FormatProvider. 
        /// </summary>
        public static string StringJoin<T>(this IEnumerable<T> Source, string Separator, string StringFormat, IFormatProvider FormatProvider)
        {
            //Validate Source
            if (Source == null)
                return string.Empty;
            else if (Source.Count() == 0)
                return string.Empty;

            //Validate Separator
            if (String.IsNullOrEmpty(Separator))
                Separator = " ";

            //Validate StringFormat
            if (String.IsNullOrWhitespace(StringFormat))
                StringFormat = "{0}";

            //Validate FormatProvider 
            if (FormatProvider == null)
                FormatProvider = CultureInfo.CurrentCulture;

            //Convert items 
            var convertedItems = Source.Select(i => String.Format(FormatProvider, StringFormat, i));

            //Return 
            return String.Join(Separator, convertedItems);
        }
    }
}

Question 13

private int[,] MirrorH(int[,] matrix)               //the method will return mirror horizintal of matrix
{
    int[,] MirrorHorizintal = new int[4, 4];
    for (int i = 0; i < 4; i++)
    {
        for (int j = 0; j < 4; j ++)
        {
            MirrorHorizintal[i, j] = matrix[i, 3 - j];
        }
    }
    return MirrorHorizintal;
}