我发现自己通过自定义,手工编码,值几次进行反向查找,并提出了以下方法。
使enum
s实现一个共享接口:
interface Codified<out T : Serializable> {
val code: T
}
enum class Alphabet(val value: Int) : Codified<Int> {
A(1),
B(2),
C(3);
override val code = value
}
该接口(尽管名称很奇怪:))将某个值标记为显式代码。目标是能够编写:
val a = Alphabet::class.decode(1) //Alphabet.A
val d = Alphabet::class.tryDecode(4) //null
可以使用以下代码轻松实现:
interface Codified<out T : Serializable> {
val code: T
object Enums {
private val enumCodesByClass = ConcurrentHashMap<Class<*>, Map<Serializable, Enum<*>>>()
inline fun <reified T, TCode : Serializable> decode(code: TCode): T where T : Codified<TCode>, T : Enum<*> {
return decode(T::class.java, code)
}
fun <T, TCode : Serializable> decode(enumClass: Class<T>, code: TCode): T where T : Codified<TCode> {
return tryDecode(enumClass, code) ?: throw IllegalArgumentException("No $enumClass value with code == $code")
}
inline fun <reified T, TCode : Serializable> tryDecode(code: TCode): T? where T : Codified<TCode> {
return tryDecode(T::class.java, code)
}
@Suppress("UNCHECKED_CAST")
fun <T, TCode : Serializable> tryDecode(enumClass: Class<T>, code: TCode): T? where T : Codified<TCode> {
val valuesForEnumClass = enumCodesByClass.getOrPut(enumClass as Class<Enum<*>>, {
enumClass.enumConstants.associateBy { (it as T).code }
})
return valuesForEnumClass[code] as T?
}
}
}
fun <T, TCode> KClass<T>.decode(code: TCode): T
where T : Codified<TCode>, T : Enum<T>, TCode : Serializable
= Codified.Enums.decode(java, code)
fun <T, TCode> KClass<T>.tryDecode(code: TCode): T?
where T : Codified<TCode>, T : Enum<T>, TCode : Serializable
= Codified.Enums.tryDecode(java, code)