输入inputType
numberDecimal
中EditText
使用点“。”。作为小数点分隔符。在欧洲,通常使用逗号','代替。即使我的语言环境设置为德语,小数点分隔符仍为“。”。
有没有办法将逗号作为小数点分隔符?
输入inputType
numberDecimal
中EditText
使用点“。”。作为小数点分隔符。在欧洲,通常使用逗号','代替。即使我的语言环境设置为德语,小数点分隔符仍为“。”。
有没有办法将逗号作为小数点分隔符?
Answers:
一种解决方法(直到Google修复此错误)是使用EditText
with android:inputType="numberDecimal"
和android:digits="0123456789.,"
。
然后使用以下afterTextChanged将TextChangedListener添加到EditText:
public void afterTextChanged(Editable s) {
double doubleValue = 0;
if (s != null) {
try {
doubleValue = Double.parseDouble(s.toString().replace(',', '.'));
} catch (NumberFormatException e) {
//Error
}
}
//Do something with doubleValue
}
此处提供的“数字”解决方案的一种变体:
char separator = DecimalFormatSymbols.getInstance().getDecimalSeparator();
input.setKeyListener(DigitsKeyListener.getInstance("0123456789" + separator));
考虑到语言环境分隔符。
,
的键盘上没有按键。示例:三星键盘(KitKat)。
EditText的以下代码货币掩码($ 123,125.155)
Xml布局
<EditText
android:inputType="numberDecimal"
android:layout_height="wrap_content"
android:layout_width="200dp"
android:digits="0123456789.,$" />
码
EditText testFilter=...
testFilter.addTextChangedListener( new TextWatcher() {
boolean isEdiging;
@Override public void onTextChanged(CharSequence s, int start, int before, int count) { }
@Override public void beforeTextChanged(CharSequence s, int start, int count, int after) { }
@Override public void afterTextChanged(Editable s) {
if(isEdiging) return;
isEdiging = true;
String str = s.toString().replaceAll( "[^\\d]", "" );
double s1 = Double.parseDouble(str);
NumberFormat nf2 = NumberFormat.getInstance(Locale.ENGLISH);
((DecimalFormat)nf2).applyPattern("$ ###,###.###");
s.replace(0, s.length(), nf2.format(s1));
isEdiging = false;
}
});
如果您以编程方式实例化EditText,Martins的答案将不起作用。我继续并修改了DigitsKeyListener
API 14中的包含类,以允许逗号和句点作为小数点分隔符。
要使用此功能,调用setKeyListener()
的EditText
,比如
// Don't allow for signed input (minus), but allow for decimal points
editText.setKeyListener( new MyDigitsKeyListener( false, true ) );
但是,在TextChangedListener
用逗号替换逗号的过程中,仍然需要使用马丁的技巧
import android.text.InputType;
import android.text.SpannableStringBuilder;
import android.text.Spanned;
import android.text.method.NumberKeyListener;
import android.view.KeyEvent;
class MyDigitsKeyListener extends NumberKeyListener {
/**
* The characters that are used.
*
* @see KeyEvent#getMatch
* @see #getAcceptedChars
*/
private static final char[][] CHARACTERS = new char[][] {
new char[] { '0', '1', '2', '3', '4', '5', '6', '7', '8', '9' },
new char[] { '0', '1', '2', '3', '4', '5', '6', '7', '8', '9', '-' },
new char[] { '0', '1', '2', '3', '4', '5', '6', '7', '8', '9', '.', ',' },
new char[] { '0', '1', '2', '3', '4', '5', '6', '7', '8', '9', '-', '.', ',' },
};
private char[] mAccepted;
private boolean mSign;
private boolean mDecimal;
private static final int SIGN = 1;
private static final int DECIMAL = 2;
private static MyDigitsKeyListener[] sInstance = new MyDigitsKeyListener[4];
@Override
protected char[] getAcceptedChars() {
return mAccepted;
}
/**
* Allocates a DigitsKeyListener that accepts the digits 0 through 9.
*/
public MyDigitsKeyListener() {
this(false, false);
}
/**
* Allocates a DigitsKeyListener that accepts the digits 0 through 9,
* plus the minus sign (only at the beginning) and/or decimal point
* (only one per field) if specified.
*/
public MyDigitsKeyListener(boolean sign, boolean decimal) {
mSign = sign;
mDecimal = decimal;
int kind = (sign ? SIGN : 0) | (decimal ? DECIMAL : 0);
mAccepted = CHARACTERS[kind];
}
/**
* Returns a DigitsKeyListener that accepts the digits 0 through 9.
*/
public static MyDigitsKeyListener getInstance() {
return getInstance(false, false);
}
/**
* Returns a DigitsKeyListener that accepts the digits 0 through 9,
* plus the minus sign (only at the beginning) and/or decimal point
* (only one per field) if specified.
*/
public static MyDigitsKeyListener getInstance(boolean sign, boolean decimal) {
int kind = (sign ? SIGN : 0) | (decimal ? DECIMAL : 0);
if (sInstance[kind] != null)
return sInstance[kind];
sInstance[kind] = new MyDigitsKeyListener(sign, decimal);
return sInstance[kind];
}
/**
* Returns a DigitsKeyListener that accepts only the characters
* that appear in the specified String. Note that not all characters
* may be available on every keyboard.
*/
public static MyDigitsKeyListener getInstance(String accepted) {
// TODO: do we need a cache of these to avoid allocating?
MyDigitsKeyListener dim = new MyDigitsKeyListener();
dim.mAccepted = new char[accepted.length()];
accepted.getChars(0, accepted.length(), dim.mAccepted, 0);
return dim;
}
public int getInputType() {
int contentType = InputType.TYPE_CLASS_NUMBER;
if (mSign) {
contentType |= InputType.TYPE_NUMBER_FLAG_SIGNED;
}
if (mDecimal) {
contentType |= InputType.TYPE_NUMBER_FLAG_DECIMAL;
}
return contentType;
}
@Override
public CharSequence filter(CharSequence source, int start, int end,
Spanned dest, int dstart, int dend) {
CharSequence out = super.filter(source, start, end, dest, dstart, dend);
if (mSign == false && mDecimal == false) {
return out;
}
if (out != null) {
source = out;
start = 0;
end = out.length();
}
int sign = -1;
int decimal = -1;
int dlen = dest.length();
/*
* Find out if the existing text has '-' or '.' characters.
*/
for (int i = 0; i < dstart; i++) {
char c = dest.charAt(i);
if (c == '-') {
sign = i;
} else if (c == '.' || c == ',') {
decimal = i;
}
}
for (int i = dend; i < dlen; i++) {
char c = dest.charAt(i);
if (c == '-') {
return ""; // Nothing can be inserted in front of a '-'.
} else if (c == '.' || c == ',') {
decimal = i;
}
}
/*
* If it does, we must strip them out from the source.
* In addition, '-' must be the very first character,
* and nothing can be inserted before an existing '-'.
* Go in reverse order so the offsets are stable.
*/
SpannableStringBuilder stripped = null;
for (int i = end - 1; i >= start; i--) {
char c = source.charAt(i);
boolean strip = false;
if (c == '-') {
if (i != start || dstart != 0) {
strip = true;
} else if (sign >= 0) {
strip = true;
} else {
sign = i;
}
} else if (c == '.' || c == ',') {
if (decimal >= 0) {
strip = true;
} else {
decimal = i;
}
}
if (strip) {
if (end == start + 1) {
return ""; // Only one character, and it was stripped.
}
if (stripped == null) {
stripped = new SpannableStringBuilder(source, start, end);
}
stripped.delete(i - start, i + 1 - start);
}
}
if (stripped != null) {
return stripped;
} else if (out != null) {
return out;
} else {
return null;
}
}
}
您可以将以下内容用于不同的语言环境
private void localeDecimalInput(final EditText editText){
DecimalFormat decFormat = (DecimalFormat) DecimalFormat.getInstance(Locale.getDefault());
DecimalFormatSymbols symbols=decFormat.getDecimalFormatSymbols();
final String defaultSeperator=Character.toString(symbols.getDecimalSeparator());
editText.addTextChangedListener(new TextWatcher() {
@Override
public void beforeTextChanged(CharSequence s, int start, int count, int after) {
}
@Override
public void onTextChanged(CharSequence s, int start, int before, int count) {
}
@Override
public void afterTextChanged(Editable editable) {
if(editable.toString().contains(defaultSeperator))
editText.setKeyListener(DigitsKeyListener.getInstance("0123456789"));
else
editText.setKeyListener(DigitsKeyListener.getInstance("0123456789" + defaultSeperator));
}
});
}
您可以使用以下变通办法将逗号作为有效输入包括在内:
通过XML:
<EditText
android:inputType="number"
android:digits="0123456789.," />
以编程方式:
EditText input = new EditText(THE_CONTEXT);
input.setKeyListener(DigitsKeyListener.getInstance("0123456789.,"));
这样,Android系统将显示数字的键盘并允许输入逗号。希望这能回答问题:)
您可以执行以下操作:
DecimalFormatSymbols d = DecimalFormatSymbols.getInstance(Locale.getDefault());
input.setFilters(new InputFilter[] { new DecimalDigitsInputFilter(5, 2) });
input.setKeyListener(DigitsKeyListener.getInstance("0123456789" + d.getDecimalSeparator()));
然后,您可以使用输入过滤器:
public class DecimalDigitsInputFilter implements InputFilter {
Pattern mPattern;
public DecimalDigitsInputFilter(int digitsBeforeZero, int digitsAfterZero) {
DecimalFormatSymbols d = new DecimalFormatSymbols(Locale.getDefault());
String s = "\\" + d.getDecimalSeparator();
mPattern = Pattern.compile("[0-9]{0," + (digitsBeforeZero - 1) + "}+((" + s + "[0-9]{0," + (digitsAfterZero - 1) + "})?)||(" + s + ")?");
}
@Override
public CharSequence filter(CharSequence source, int start, int end, Spanned dest, int dstart, int dend) {
Matcher matcher = mPattern.matcher(dest);
if (!matcher.matches())
return "";
return null;
}
}
恕我直言,解决此问题的最佳方法是仅使用InputFilter。一个不错的主旨是DecimalDigitsInputFilter。然后,您可以:
editText.setInputType(TYPE_NUMBER_FLAG_DECIMAL | TYPE_NUMBER_FLAG_SIGNED | TYPE_CLASS_NUMBER)
editText.setKeyListener(DigitsKeyListener.getInstance("0123456789,.-"))
editText.setFilters(new InputFilter[] {new DecimalDigitsInputFilter(5,2)});
本地化您的输入使用:
char sep = DecimalFormatSymbols.getInstance().getDecimalSeparator();
然后添加:
textEdit.setKeyListener(DigitsKeyListener.getInstance("0123456789" + sep));
别忘了将“,”替换为“。”。因此Float或Double可以正确解析它。
这里的所有其他帖子都存在重大漏洞,因此,以下解决方案将:
在XML中:
<EditText
...
android:inputType="numberDecimal"
... />
类变量:
private boolean isDecimalSeparatorComma = false;
在onCreate中,找到当前语言环境中使用的分隔符:
if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.N) {
NumberFormat nf = NumberFormat.getInstance();
if (nf instanceof DecimalFormat) {
DecimalFormatSymbols sym = ((DecimalFormat) nf).getDecimalFormatSymbols();
char decSeparator = sym.getDecimalSeparator();
isDecimalSeparatorComma = Character.toString(decSeparator).equals(",");
}
}
同样在onCreate上,如果要加载当前值,请使用此命令进行更新:
// Replace editText with commas or periods as needed for viewing
String editTextValue = getEditTextValue(); // load your current value
if (editTextValue.contains(".") && isDecimalSeparatorComma) {
editTextValue = editTextValue.replaceAll("\\.",",");
} else if (editTextValue.contains(",") && !isDecimalSeparatorComma) {
editTextValue = editTextValue.replaceAll(",",".");
}
setEditTextValue(editTextValue); // override your current value
同样在onCreate上,添加侦听器
editText.addTextChangedListener(editTextWatcher);
if (isDecimalSeparatorComma) {
editText.setKeyListener(DigitsKeyListener.getInstance("0123456789,"));
} else {
editText.setKeyListener(DigitsKeyListener.getInstance("0123456789."));
}
editTextWatcher
TextWatcher editTextWatcher = new TextWatcher() {
@Override
public void beforeTextChanged(CharSequence s, int start, int count, int after) { }
@Override
public void onTextChanged(CharSequence s, int start, int before, int count) { }
@Override
public void afterTextChanged(Editable s) {
String editTextValue = s.toString();
// Count up the number of commas and periods
Pattern pattern = Pattern.compile("[,.]");
Matcher matcher = pattern.matcher(editTextValue);
int count = 0;
while (matcher.find()) {
count++;
}
// Don't let it put more than one comma or period
if (count > 1) {
s.delete(s.length()-1, s.length());
} else {
// If there is a comma or period at the end the value hasn't changed so don't update
if (!editTextValue.endsWith(",") && !editTextValue.endsWith(".")) {
doSomething()
}
}
}
};
doSomething()示例,转换为标准时间以进行数据处理
private void doSomething() {
try {
String editTextStr = editText.getText().toString();
if (isDecimalSeparatorComma) {
editTextStr = editTextStr.replaceAll(",",".");
}
float editTextFloatValue = editTextStr.isEmpty() ?
0.0f :
Float.valueOf(editTextStr);
... use editTextFloatValue
} catch (NumberFormatException e) {
Log.e(TAG, "Error converting String to Double");
}
}
Android具有内置的数字格式化程序。
您可以将其添加EditText
到允许小数点和逗号的位置:
android:inputType="numberDecimal"
和android:digits="0123456789.,"
然后在代码中的某个位置,当用户单击“保存”或在输入文本后(使用侦听器)。
// Format the number to the appropriate double
try {
Number formatted = NumberFormat.getInstance().parse(editText.getText().toString());
cost = formatted.doubleValue();
} catch (ParseException e) {
System.out.println("Error parsing cost string " + editText.getText().toString());
cost = 0.0;
}
我决定只在编辑时将逗号更改为点。这是我棘手且相对简单的解决方法:
editText.setOnFocusChangeListener(new View.OnFocusChangeListener() {
@Override
public void onFocusChange(View v, boolean hasFocus) {
EditText editText = (EditText) v;
String text = editText.getText().toString();
if (hasFocus) {
editText.setText(text.replace(",", "."));
} else {
if (!text.isEmpty()) {
Double doubleValue = Double.valueOf(text.replace(",", "."));
editText.setText(someDecimalFormatter.format(doubleValue));
}
}
}
});
someDecimalFormatter将使用逗号还是点号取决于语言环境
我的解决方案是:
在主要活动中:
char separator =DecimalFormatSymbols.getInstance().getDecimalSeparator();
textViewPitchDeadZone.setKeyListener(DigitsKeyListener.getInstance("0123456789" + separator));
在xml文件中:
android:imeOptions="flagNoFullscreen"
android:inputType="numberDecimal"
我将editText中的double用作字符串。
已经过去8年多了,令我感到惊讶的是,这个问题尚未解决。。。
我为这个简单的问题而苦恼,因为@Martin的最高评价答案允许键入多个分隔符,即用户可以键入“ 12 ,,, ,,, 12,1,,21,2,“,
此外,第二个要注意的是,在某些设备上,数字键盘上没有显示逗号(或要求多次按下点按钮)
这是我的解决方法,它可以解决上述问题并允许用户键入“。”。和',',但是在EditText中,他将看到唯一与当前语言环境相对应的小数点分隔符:
editText.apply { addTextChangedListener(DoubleTextChangedListener(this)) }
和文本观察器:
open class DoubleTextChangedListener(private val et: EditText) : TextWatcher {
init {
et.inputType = InputType.TYPE_CLASS_NUMBER or InputType.TYPE_NUMBER_FLAG_DECIMAL
et.keyListener = DigitsKeyListener.getInstance("0123456789.,")
}
private val separator = DecimalFormatSymbols.getInstance().decimalSeparator
override fun beforeTextChanged(s: CharSequence?, start: Int, count: Int, after: Int) {
//empty
}
@CallSuper
override fun onTextChanged(s: CharSequence, start: Int, before: Int, count: Int) {
et.run {
removeTextChangedListener(this@DoubleTextChangedListener)
val formatted = toLocalizedDecimal(s.toString(), separator)
setText(formatted)
setSelection(formatted.length)
addTextChangedListener(this@DoubleTextChangedListener)
}
}
override fun afterTextChanged(s: Editable?) {
// empty
}
/**
* Formats input to a decimal. Leaves the only separator (or none), which matches [separator].
* Examples:
* 1. [s]="12.12", [separator]=',' -> result= "12,12"
* 2. [s]="12.12", [separator]='.' -> result= "12.12"
* 4. [s]="12,12", [separator]='.' -> result= "12.12"
* 5. [s]="12,12,,..,,,,,34..,", [separator]=',' -> result= "12,1234"
* 6. [s]="12.12,,..,,,,,34..,", [separator]='.' -> result= "12.1234"
* 7. [s]="5" -> result= "5"
*/
private fun toLocalizedDecimal(s: String, separator: Char): String {
val cleared = s.replace(",", ".")
val splitted = cleared.split('.').filter { it.isNotBlank() }
return when (splitted.size) {
0 -> s
1 -> cleared.replace('.', separator).replaceAfter(separator, "")
2 -> splitted.joinToString(separator.toString())
else -> splitted[0]
.plus(separator)
.plus(splitted.subList(1, splitted.size - 1).joinToString(""))
}
}
}
简单的解决方案,使自定义控件。(这是在Xamarin android中制作的,但应轻松移植到Java)
public class EditTextDecimalNumber:EditText
{
readonly string _numberFormatDecimalSeparator;
public EditTextDecimalNumber(Context context, IAttributeSet attrs) : base(context, attrs)
{
InputType = InputTypes.NumberFlagDecimal;
TextChanged += EditTextDecimalNumber_TextChanged;
_numberFormatDecimalSeparator = System.Threading.Thread.CurrentThread.CurrentUICulture.NumberFormat.NumberDecimalSeparator;
KeyListener = DigitsKeyListener.GetInstance($"0123456789{_numberFormatDecimalSeparator}");
}
private void EditTextDecimalNumber_TextChanged(object sender, TextChangedEventArgs e)
{
int noOfOccurence = this.Text.Count(x => x.ToString() == _numberFormatDecimalSeparator);
if (noOfOccurence >=2)
{
int lastIndexOf = this.Text.LastIndexOf(_numberFormatDecimalSeparator,StringComparison.CurrentCulture);
if (lastIndexOf!=-1)
{
this.Text = this.Text.Substring(0, lastIndexOf);
this.SetSelection(this.Text.Length);
}
}
}
}
我认为此解决方案比此处编写的其他解决方案复杂:
<EditText
android:inputType="numberDecimal"
android:digits="0123456789," />
这样,当您按“。”时。在软键盘上什么也没有发生。仅允许使用数字和逗号。