Django错误：render_to_response（）获得了意外的关键字参数“ context_instance”

升级到Django 1.10后，出现错误render_to_response() got an unexpected keyword argument 'context_instance'。

我的看法如下：

from django.shortcuts import render_to_response
from django.template import RequestContext

def my_view(request):
    context = {'foo': 'bar'}
    return render_to_response('my_template.html', context, context_instance=RequestContext(request))

这是完整的回溯：

Traceback:

File "/Users/alasdair/.virtualenvs/django110/lib/python2.7/site-packages/django/core/handlers/exception.py" in inner
  39.             response = get_response(request)

File "/Users/alasdair/.virtualenvs/django110/lib/python2.7/site-packages/django/core/handlers/base.py" in _get_response
  187.                 response = self.process_exception_by_middleware(e, request)

File "/Users/alasdair/.virtualenvs/django110/lib/python2.7/site-packages/django/core/handlers/base.py" in _get_response
  185.                 response = wrapped_callback(request, *callback_args, **callback_kwargs)

File "/Users/alasdair/dev/rtr/rtr/urls.py" in my_view
  26.     return render_to_response('my_template.html', context,  context_instance=RequestContext(request))

 Exception Type: TypeError at /
Exception Value: render_to_response() got an unexpected keyword argument 'context_instance'

中的context_instance参数在Django 1.8中render_to_response已弃用，在Django 1.10中已删除。

解决方案是切换到render快捷方式，该快捷方式会自动使用RequestContext。

更新您的导入并按如下所示进行查看。注意，render将request对象作为其第一个参数。

from django.shortcuts import render

def my_view(request):
    context = {'foo': 'bar'}
    return render(request, 'my_template.html', context)

该render快捷方式是Django 1.3中引入的，因此此更改与Django的较早版本兼容。

在Django 1.8中兼容：

from django.shortcuts import render_to_response
from django.template import RequestContext

def my_view(request):
    context = {'foo': 'bar'}
    return render_to_response('my_template.html', {'context':context}, context_instance=RequestContext(request))

在Django 1.11中

from django.shortcuts import render
from django.template import RequestContext

def my_view(request):
    context = {'foo': 'bar'}
    return render(request, 'my_template.html', context)

Django 2.0.7 Python 3.5

在project / urls.py中

handler404 = 'project.views.not_found'
handler500 = 'project.views.server_error'

在project / views.py中

def not_found(request, exception=None):
response = render(request, '404.html', {})
response.status_code = 404
return response

def server_error(request, exception=None):
response = render(request, '500.html', {})
response.status_code = 500
return response

exception = None不传递，因为否则会引发TypeError：server_error（）缺少1个必需的位置参数：'exception'