Google Maps:如何获取经纬度值的国家,州/省/地区,城市?


107

我需要一个基于经纬度值集合的国家,州和城市的列表。我需要以保留层次结构且无重复的方式存储此信息(例如“美国”,“美国”和“美利坚合众国”是同一国家/地区;我只希望该国家/地区的一个实例在我的数据库中) 。

这可能与Google Map API有关吗?


你省了吗?
Deepak Dholiyan '16

Answers:


135

您正在寻找的被称为反向地理编码。Google通过Google Geocoding API提供了服务器端反向地理编码服务,您应该可以将其用于您的项目。

这是对以下请求的响应的样子:

http://maps.googleapis.com/maps/api/geocode/json?latlng=40.714224,-73.961452&sensor=false

响应:

{
  "status": "OK",
  "results": [ {
    "types": [ "street_address" ],
    "formatted_address": "275-291 Bedford Ave, Brooklyn, NY 11211, USA",
    "address_components": [ {
      "long_name": "275-291",
      "short_name": "275-291",
      "types": [ "street_number" ]
    }, {
      "long_name": "Bedford Ave",
      "short_name": "Bedford Ave",
      "types": [ "route" ]
    }, {
      "long_name": "New York",
      "short_name": "New York",
      "types": [ "locality", "political" ]
    }, {
      "long_name": "Brooklyn",
      "short_name": "Brooklyn",
      "types": [ "administrative_area_level_3", "political" ]
    }, {
      "long_name": "Kings",
      "short_name": "Kings",
      "types": [ "administrative_area_level_2", "political" ]
    }, {
      "long_name": "New York",
      "short_name": "NY",
      "types": [ "administrative_area_level_1", "political" ]
    }, {
      "long_name": "United States",
      "short_name": "US",
      "types": [ "country", "political" ]
    }, {
      "long_name": "11211",
      "short_name": "11211",
      "types": [ "postal_code" ]
    } ],
    "geometry": {
      "location": {
        "lat": 40.7142298,
        "lng": -73.9614669
      },
      "location_type": "RANGE_INTERPOLATED",
      "viewport": {
        "southwest": {
          "lat": 40.7110822,
          "lng": -73.9646145
        },
        "northeast": {
          "lat": 40.7173774,
          "lng": -73.9583193
        }
      }
    }
  },

  ... Additional results[] ...

您还可以选择以XML而不是json接收响应,只需在请求URI中用json代替xml即可:

http://maps.googleapis.com/maps/api/geocode/xml?latlng=40.714224,-73.961452&sensor=false

据我所知,Google还将为地址部分返回相同的名称,尤其是对于诸如国家名称和城市名称之类的高级名称。不过,请记住,尽管对于大多数应用程序来说结果非常准确,但是您仍然会发现偶尔的拼写错误或模棱两可的结果。


谢谢!我拥有的经/纬度集合实际上与数据库中的用户个人资料相关联。您知道我如何实现搜索功能,该功能将允许用户查找指定位置内的其他用户(例如,查找纽约布鲁克林的所有用户)吗?记住,我所有的都是经/纬度。
StackOverflowNewbie

1
@StackOverflowNewbie:您可能想对所有经纬度进行地理编码,然后在数据库中填写“ city”,“ state”,“ country”字段。然后,只需对数据库中的这些字段进行过滤即可。
丹尼尔·瓦萨洛

1
或者,如果您使用MS Sql 2008,并且需要查找某个点附近的位置,则可以使用地理等空间数据类型
GibboK 2012年

1
您如何确定响应中城市和国家的索引号?它不断变化,例如,如果某个区域具有子区域,则索引键会变化
Khan Shahrukh

4
怎么sensor=false办?
CENT1PEDE '16

21

您在这里有一个基本的答案: 使用地理位置获取城市名称

但是对于您正在寻找的东西,我会推荐这种方式。

仅当您还需要Administrative_area_level_1来为美国德克萨斯州的巴黎和法国法兰西岛的巴黎存储不同的东西并提供手动后备时:

-

米哈尔(Michal)的方式存在一个问题,那就是它取得了第一个结果,而不是一个特定的结果。他使用结果[0]。我认为合适的方式(我刚刚修改了他的代码)是仅获取类型为“ locality”的结果,该结果始终存在,即使在最终的手动回退中,以防浏览器不支持地理位置。

他的方式:获取结果不同于使用 http://maps.googleapis.com/maps/api/geocode/json?address=bucharest&sensor=false 与使用 http://maps.googleapis.com/maps/api/geocode /json?latlng=44.42514,26.10540&sensor=false (按名称搜索/按lat&lng搜索)

这样:获取相同的结果。

<!DOCTYPE html> 
<html> 
<head> 
<meta name="viewport" content="initial-scale=1.0, user-scalable=no"/> 
<meta http-equiv="content-type" content="text/html; charset=UTF-8"/> 
<title>Reverse Geocoding</title> 

<script type="text/javascript" src="http://maps.googleapis.com/maps/api/js?sensor=false"></script> 
<script type="text/javascript"> 
  var geocoder;

  if (navigator.geolocation) {
    navigator.geolocation.getCurrentPosition(successFunction, errorFunction);
} 
//Get the latitude and the longitude;
function successFunction(position) {
    var lat = position.coords.latitude;
    var lng = position.coords.longitude;
    codeLatLng(lat, lng)
}

function errorFunction(){
    alert("Geocoder failed");
}

  function initialize() {
    geocoder = new google.maps.Geocoder();



  }

  function codeLatLng(lat, lng) {

    var latlng = new google.maps.LatLng(lat, lng);
    geocoder.geocode({'latLng': latlng}, function(results, status) {
      if (status == google.maps.GeocoderStatus.OK) {
      //console.log(results);
        if (results[1]) {
        var indice=0;
        for (var j=0; j<results.length; j++)
        {
            if (results[j].types[0]=='locality')
                {
                    indice=j;
                    break;
                }
            }
        alert('The good number is: '+j);
        console.log(results[j]);
        for (var i=0; i<results[j].address_components.length; i++)
            {
                if (results[j].address_components[i].types[0] == "locality") {
                        //this is the object you are looking for City
                        city = results[j].address_components[i];
                    }
                if (results[j].address_components[i].types[0] == "administrative_area_level_1") {
                        //this is the object you are looking for State
                        region = results[j].address_components[i];
                    }
                if (results[j].address_components[i].types[0] == "country") {
                        //this is the object you are looking for
                        country = results[j].address_components[i];
                    }
            }

            //city data
            alert(city.long_name + " || " + region.long_name + " || " + country.short_name)


            } else {
              alert("No results found");
            }
        //}
      } else {
        alert("Geocoder failed due to: " + status);
      }
    });
  }
</script> 
</head> 
<body onload="initialize()"> 

</body> 
</html> 

这可以节省我的一天
Andi AR

4

我以这个问题作为自己解决方案的起点。认为回馈我的代码是适当的,因为它比tabacitu的代码小

依存关系:

码:

if(geoPosition.init()){  

    var foundLocation = function(city, state, country, lat, lon){
        //do stuff with your location! any of the first 3 args may be null
        console.log(arguments);
    }

    var geocoder = new google.maps.Geocoder(); 
    geoPosition.getCurrentPosition(function(r){
        var findResult = function(results, name){
            var result =  _.find(results, function(obj){
                return obj.types[0] == name && obj.types[1] == "political";
            });
            return result ? result.short_name : null;
        };
        geocoder.geocode({'latLng': new google.maps.LatLng(r.coords.latitude, r.coords.longitude)}, function(results, status) {
            if (status == google.maps.GeocoderStatus.OK && results.length) {
                results = results[0].address_components;
                var city = findResult(results, "locality");
                var state = findResult(results, "administrative_area_level_1");
                var country = findResult(results, "country");
                foundLocation(city, state, country, r.coords.latitude, r.coords.longitude);
            } else {
                foundLocation(null, null, null, r.coords.latitude, r.coords.longitude);
            }
        });
    }, { enableHighAccuracy:false, maximumAge: 1000 * 60 * 1 });
}

3

当我将其包含在我的jsp文件中时,发现GeoCoder javascript有点bug。

您也可以尝试以下操作:



    var lat = "43.7667855" ;
    var long = "-79.2157321" ;
    var url = "https://maps.googleapis.com/maps/api/geocode/json?latlng="
       +lat+","+long+"&sensor=false";
    $.get(url).success(function(data) {
       var loc1 = data.results[0];
       var county, city;
         $.each(loc1, function(k1,v1) {
            if (k1 == "address_components") {
               for (var i = 0; i < v1.length; i++) {
                  for (k2 in v1[i]) {
                     if (k2 == "types") {
                        var types = v1[i][k2];
                        if (types[0] =="sublocality_level_1") {
                            county = v1[i].long_name;
                            //alert ("county: " + county);
                        } 
                        if (types[0] =="locality") {
                           city = v1[i].long_name;
                           //alert ("city: " + city);
                       } 
                     }

                  }          

               }

            }

         });
         $('#city').html(city); 
    }); 


进行一些修复,更改后$.get(url).success(function(data)即可 $.get(url, function(data)正常使用
珍贵的汤姆(Tom),汤姆(Tom),

3

我编写了此函数,该函数根据address_componentsgmaps API返回的内容提取您要查找的内容。例如,这是城市。

export const getAddressCity = (address, length) => {
  const findType = type => type.types[0] === "locality"
  const location = address.map(obj => obj)
  const rr = location.filter(findType)[0]

  return (
    length === 'short'
      ? rr.short_name
      : rr.long_name
  )
}

更改localityadministrative_area_level_1为国家等。

在我的js代码中,我像这样使用:

const location =`${getAddressCity(address_components, 'short')}, ${getAddressState(address_components, 'short')}`

将返回: Waltham, MA


0

只需尝试此代码,此代码即可与我一起使用

var posOptions = {timeout: 10000, enableHighAccuracy: false};
$cordovaGeolocation.getCurrentPosition(posOptions).then(function (position) {
var lat = position.coords.latitude;
var long = position.coords.longitude;
 //console.log(lat +"          "+long);
$http.get('https://maps.googleapis.com/maps/api/geocode/json?latlng=' + lat + ',' + long + '&key=your key here').success(function (output) {
//console.log( JSON.stringify(output.results[0]));
//console.log( JSON.stringify(output.results[0].address_components[4].short_name));
var results = output.results;
if (results[0]) {
//console.log("results.length= "+results.length);
//console.log("hi "+JSON.stringify(results[0],null,4));
for (var j = 0; j < results.length; j++){
 //console.log("j= "+j);
//console.log(JSON.stringify(results[j],null,4));
for (var i = 0; i < results[j].address_components.length; i++){
 if(results[j].address_components[i].types[0] == "country") {
 //this is the object you are looking for
  country = results[j].address_components[i];
 }
 }
 }
 console.log(country.long_name);
 console.log(country.short_name);
 } else {
 alert("No results found");
 console.log("No results found");
 }
 });
 }, function (err) {
 });

0

我创建了一个小的映射器函数:

private getAddressParts(object): Object {
    let address = {};
    const address_components = object.address_components;
    address_components.forEach(element => {
        address[element.types[0]] = element.short_name;
    });
    return address;
}

这是Angular 4的解决方案,但我想您会明白的。

用法:

geocoder.geocode({ 'location' : latlng }, (results, status) => {
    if (status === google.maps.GeocoderStatus.OK) {
        const address = {
            formatted_address: results[0].formatted_address,
            address_parts: this.getAddressParts(results[0])
        };
        (....)
    }

这样,address对象将是这样的:

address: {
    address_parts: {
        administrative_area_level_1: "NY",
        administrative_area_level_2: "New York County",
        country: "US",
        locality: "New York",
        neighborhood: "Lower Manhattan",
        political: "Manhattan",
        postal_code: "10038",
        route: "Beekman St",
        street_number: "90",
    },
    formatted_address: "90 Beekman St, New York, NY 10038, USA"
}

希望能帮助到你!


0
 <div id="location"></div>
        <script>
            window.onload = function () {
                var startPos;
                var geoOptions = {
                    maximumAge: 5 * 60 * 1000,
                    timeout: 10 * 1000,
                    enableHighAccuracy: true
                }


                var geoSuccess = function (position) {
                    startPos = position;
                    geocodeLatLng(startPos.coords.latitude, startPos.coords.longitude);

                };
                var geoError = function (error) {
                    console.log('Error occurred. Error code: ' + error.code);
                    // error.code can be:
                    //   0: unknown error
                    //   1: permission denied
                    //   2: position unavailable (error response from location provider)
                    //   3: timed out
                };

                navigator.geolocation.getCurrentPosition(geoSuccess, geoError, geoOptions);
            };
            function geocodeLatLng(lat, lng) {
                var geocoder = new google.maps.Geocoder;
                var latlng = {lat: parseFloat(lat), lng: parseFloat(lng)};
                geocoder.geocode({'location': latlng}, function (results, status) {
                    if (status === 'OK') {
                        console.log(results)
                        if (results[0]) {
                            document.getElementById('location').innerHTML = results[0].formatted_address;
                            var street = "";
                            var city = "";
                            var state = "";
                            var country = "";
                            var zipcode = "";
                            for (var i = 0; i < results.length; i++) {
                                if (results[i].types[0] === "locality") {
                                    city = results[i].address_components[0].long_name;
                                    state = results[i].address_components[2].long_name;

                                }
                                if (results[i].types[0] === "postal_code" && zipcode == "") {
                                    zipcode = results[i].address_components[0].long_name;

                                }
                                if (results[i].types[0] === "country") {
                                    country = results[i].address_components[0].long_name;

                                }
                                if (results[i].types[0] === "route" && street == "") {

                                    for (var j = 0; j < 4; j++) {
                                        if (j == 0) {
                                            street = results[i].address_components[j].long_name;
                                        } else {
                                            street += ", " + results[i].address_components[j].long_name;
                                        }
                                    }

                                }
                                if (results[i].types[0] === "street_address") {
                                    for (var j = 0; j < 4; j++) {
                                        if (j == 0) {
                                            street = results[i].address_components[j].long_name;
                                        } else {
                                            street += ", " + results[i].address_components[j].long_name;
                                        }
                                    }

                                }
                            }
                            if (zipcode == "") {
                                if (typeof results[0].address_components[8] !== 'undefined') {
                                    zipcode = results[0].address_components[8].long_name;
                                }
                            }
                            if (country == "") {
                                if (typeof results[0].address_components[7] !== 'undefined') {
                                    country = results[0].address_components[7].long_name;
                                }
                            }
                            if (state == "") {
                                if (typeof results[0].address_components[6] !== 'undefined') {
                                    state = results[0].address_components[6].long_name;
                                }
                            }
                            if (city == "") {
                                if (typeof results[0].address_components[5] !== 'undefined') {
                                    city = results[0].address_components[5].long_name;
                                }
                            }

                            var address = {
                                "street": street,
                                "city": city,
                                "state": state,
                                "country": country,
                                "zipcode": zipcode,
                            };

                            document.getElementById('location').innerHTML = document.getElementById('location').innerHTML + "<br/>Street : " + address.street + "<br/>City : " + address.city + "<br/>State : " + address.state + "<br/>Country : " + address.country + "<br/>zipcode : " + address.zipcode;
                            console.log(address);
                        } else {
                            window.alert('No results found');
                        }
                    } else {
                        window.alert('Geocoder failed due to: ' + status);
                    }
                });
            }
        </script>

        <script async defer
                src="https://maps.googleapis.com/maps/api/js?key=YOUR_API_KEY">
        </script>

0

@Szkíta通过创建一个函数来获取命名数组中的地址部分,这是一个很好的解决方案。这是为那些希望使用纯JavaScript的人提供的已编译解决方案。

将结果转换为命名数组的函数:

function getAddressParts(obj) {

    var address = [];

    obj.address_components.forEach( function(el) {
        address[el.types[0]] = el.short_name;
    });

    return address;

} //getAddressParts()

对LAT / LNG值进行地址解析:

geocoder.geocode( { 'location' : latlng }, function(results, status) {

    if (status == google.maps.GeocoderStatus.OK) {
        var addressParts =  getAddressParts(results[0]);

        // the city
        var city = addressParts.locality;

        // the state
        var state = addressParts.administrative_area_level_1;
    }

});
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