我有一个Python代码,该代码可以使用Google STT引擎识别语音并将结果返回给我,但结果以带引号的字符串形式出现。我不希望在我的代码中加上引号,因为我将使用它来运行许多命令,但它不起作用。到目前为止,我还没有尝试过任何东西!这是python代码中的可识别语音的函数:
def recog():
p = subprocess.Popen(['./speech-recog.sh'], stdout=subprocess.PIPE,
stderr=subprocess.PIPE)
global out,err
out, err = p.communicate()
print out
这是speech-recog.sh:
#!/bin/bash
hardware="plughw:1,0"
duration="3"
lang="en"
hw_bool=0
dur_bool=0
lang_bool=0
for var in "$@"
do
if [ "$var" == "-D" ] ; then
hw_bool=1
elif [ "$var" == "-d" ] ; then
dur_bool=1
elif [ "$var" == "-l" ] ; then
lang_bool=1
elif [ $hw_bool == 1 ] ; then
hw_bool=0
hardware="$var"
elif [ $dur_bool == 1 ] ; then
dur_bool=0
duration="$var"
elif [ $lang_bool == 1 ] ; then
lang_bool=0
lang="$var"
else
echo "Invalid option, valid options are -D for hardware and -d for duration"
fi
done
arecord -D $hardware -f S16_LE -t wav -d $duration -r 16000 | flac - -f --best --sample-rate 16000 -o /dev/shm/out.flac 1>/dev/shm/voice.log 2>/dev/shm/voice.log; curl -X POST --data-binary @/dev/shm/out.flac --user-agent 'Mozilla/5.0' --header 'Content-Type: audio/x-flac; rate=16000;' "https://www.google.com/speech-api/v2/recognize?output=json&lang=$lang&key=key&client=Mozilla/5.0" | sed -e 's/[{}]/''/g' | awk -F":" '{print $4}' | awk -F"," '{print $1}' | tr -d '\n'
rm /dev/shm/out.flac
这取材于史蒂文·希克森(Steven Hickson)为Raspberry Pi开发的语音命令程序