如何在Java中计算时差?


Answers:


115
String time1 = "16:00:00";
String time2 = "19:00:00";

SimpleDateFormat format = new SimpleDateFormat("HH:mm:ss");
Date date1 = format.parse(time1);
Date date2 = format.parse(time2);
long difference = date2.getTime() - date1.getTime(); 

差异以毫秒为单位。

我修改了sfaizs post


7
那怎么办呢?16:00-19:00?我该如何计算?
Alex Kapustian 2011年

反转变量不会有多大好处。.在此示例中,可以肯定的是,您可以反转它们并采用绝对值或其他值。但是,如果您在午夜(00:00)会怎样?
rj2700 '17

那23:15:00-01:15:00呢?
Oleksandr

今天08:00:00和昨天10:00:00之间的区别是什么?我认为您的建议不是可破解的逻辑。
channae

105

Java 8有一个更干净的解决方案 -即时和持续时间

例:

import java.time.Duration;
import java.time.Instant;
...
Instant start = Instant.now();
//your code
Instant end = Instant.now();
Duration timeElapsed = Duration.between(start, end);
System.out.println("Time taken: "+ timeElapsed.toMillis() +" milliseconds");

我真的很喜欢你的答案。非常优雅!:)
Avinash

因此,这归结为两次导入并System.out.println("Duration: " + String.valueOf(Duration.between(outerstart, Instant.now()).toMillis()));记录了持续时间。如果其他语言可以使用类似以下代码的代码来实现,我不会在Java8中称其为一个不错且干净的解决方案print("Duration: " + str(time.time()-start))
卢克,

3
@Luc的清洁度与简洁度不同。确切地讲,Java 8版本中发生了什么,并且进行调整也更容易,例如,如果您想以毫秒以外的单位或以多个单位(例如1h 15m 3.022s而不是4503022 milliseconds)报告两次瞬时之间的持续时间。
JakeRobb

39

为了获得时间上的差异,

// d1, d2 are dates
long diff = d2.getTime() - d1.getTime();

long diffSeconds = diff / 1000 % 60;
long diffMinutes = diff / (60 * 1000) % 60;
long diffHours = diff / (60 * 60 * 1000) % 24;
long diffDays = diff / (24 * 60 * 60 * 1000);

System.out.print(diffDays + " days, ");
System.out.print(diffHours + " hours, ");
System.out.print(diffMinutes + " minutes, ");
System.out.print(diffSeconds + " seconds.");

非常好的答案
Palanivelraghul,2017年

32

Java 8

DateTimeFormatter formatter = DateTimeFormatter.ofPattern("yyyy-MM-dd HH:mm:ss");

LocalDateTime dateTime1= LocalDateTime.parse("2014-11-25 19:00:00", formatter);
LocalDateTime dateTime2= LocalDateTime.parse("2014-11-25 16:00:00", formatter);

long diffInMilli = java.time.Duration.between(dateTime1, dateTime2).toMillis();
long diffInSeconds = java.time.Duration.between(dateTime1, dateTime2).getSeconds();
long diffInMinutes = java.time.Duration.between(dateTime1, dateTime2).toMinutes();

1
这对于Java SE 6和7作为后端口以及Android也可用。
布赖恩

11

就像其他语言一样;将您的时间段转换为unix时间戳(即自Unix时代以来的秒数),然后简单地减去。然后,将产生的秒数用作新的Unix时间戳,并以所需的任何格式读取格式。

啊,给上面的海报(创世纪)以应有的信誉,代码总是很方便的;)虽然,现在您也有了一个解释:)


8
import java.util.Date;
...
Date d1 = new Date();
...
...
Date d2 = new Date();
System.out.println(d2.getTime()-d1.getTime()); //gives the time difference in milliseconds. 
System.out.println((d2.getTime()-d1.getTime())/1000); //gives the time difference in seconds.

并且,为了以更好的格式显示,您可以使用:

    DecimalFormat myDecimalFormatter = new DecimalFormat("###,###.###");
    System.out.println(myDecimalFormatter.format(((double)d2.getTime()-d1.getTime())/1000));

这将重复另一个答案,并且不会添加任何新内容。除非您确实有新的贡献,否则请不要发布答案。
DavidPostill

@DavidPostill,谢谢您的注意。但是我需要自己解决的问题,而在GENESIS的帖子中却找不到,解决方案是执行两行代码之间的时间差(例如程序的起点和终点,或者在运行方法之前和之后,而不是静态时间) 。我认为这可能会有所帮助。
Alisa 2015年

2

痛苦的方法是转换为毫并进行减法,然后返回到您想要的秒数左右。更好的方法是使用JodaTime


1
我从未提到过unix时间戳。同样众所周知的事实是,Java Date and Time API的吸用不仅仅是偶然的用途。JodaTime更好,并且可能是JSR 310是Java的一部分。sourceforge.net/apps/mediawiki/threeten/...
曼弗雷德·莫泽

@Manfred Moser:也许您应该...默认的Java时间类和Joda都以毫秒为单位给出一个从Unix时代开始的时间。此时,它们变得接近Unix时间戳(一个以毫秒为单位,另一个以秒为单位)。在任何情况下,OP都可以使用默认的Java类简单地完成操作,取自Unix时代以来的毫秒数并减去它们。
SyntaxT3rr0r 2011年

1
当然可以做到这一点。而且,如果您在应用中进行了大量的日期和时间计算,您还可以自己创建许多错误,并重新创建自己的小库,从而再次实现JodaTime的某些部分。对于一个简单的计算可​​能没问题,但对于频繁使用的情况,值得使用一个不错的库。我只是想指出,第一个简单的解决方案可能并没有带您走上最佳道路。怎么了
Manfred Moser

3
@Manfred Moser:实际上,第一个简单的解决方案正确的方法,考虑到OP要求两个时间段之间的差异,而不是原子钟的变化:)
Christian

当然..仅对于此示例和特定问题。虽然不是为了更大的前景。
Manfred Moser

2
import java.text.SimpleDateFormat;
import java.util.Date;
public class Main {
public static void main(String[] args) throws Exception{
    String time1 = "12:00:00";
    String time2 = "12:01:00";
    SimpleDateFormat format = new SimpleDateFormat("HH:mm:ss");
    Date date1 = format.parse(time1);
    Date date2 = format.parse(time2);
    long difference = date2.getTime() - date1.getTime();
    System.out.println(difference/1000);
}}

引发异常句柄解析异常


2

除了最常见的使用Period和Duration对象的方法外,您还可以使用Java处理时间的另一种方式来扩展知识。

高级Java 8库。 差异的ChronoUnit

ChronoUnit是确定两个时间值相隔多远的好方法。时态包括LocalDateLocalTime等。

LocalTime one = LocalTime.of(5,15);
LocalTime two = LocalTime.of(6,30);
LocalDate date = LocalDate.of(2019, 1, 29);

System.out.println(ChronoUnit.HOURS.between(one, two)); //1
System.out.println(ChronoUnit.MINUTES.between(one, two)); //75
System.out.println(ChronoUnit.MINUTES.between(one, date)); //DateTimeException

第一个示例显示了在截断之间而不是舍入之间。

第二个显示了计算不同单位是多么容易。

最后一个例子提醒我们,我们不应该弄乱Java中的日期和时间:)


1

如果采用不同日期的时间,则为备选方法,例如:22:00和01:55。

public static long getDiffTime(Date date1, Date date2){
        if (date2.getTime() - date1.getTime() < 0) {// if for example date1 = 22:00, date2 = 01:55.
            Calendar c = Calendar.getInstance();
            c.setTime(date2);
            c.add(Calendar.DATE, 1);
            date2 = c.getTime();
        } //else for example date1 = 01:55, date2 = 03:55.
        long ms = date2.getTime() - date1.getTime();

        //235 minutes ~ 4 hours for (22:00 -- 01:55).
        //120 minutes ~ 2 hours for (01:55 -- 03:55).
        return TimeUnit.MINUTES.convert(ms, TimeUnit.MILLISECONDS);
    }

1
String start = "12:00:00";
String end = "02:05:00";

SimpleDateFormat format = new SimpleDateFormat("HH:mm:ss"); 

Date date1 = format.parse(start);

Date date2 = format.parse(end);

long difference = date2.getTime() - date1.getTime(); 

int minutes = (int) TimeUnit.MILLISECONDS.toMinutes(difference);

if(minutes<0)minutes += 1440; 

现在,分钟将是两个时间之间的正确持续时间(以分钟为单位)。


1
public class timeDifference {

public static void main(String[] args) {

    try {

        Date startTime = Calendar.getInstance().getTime();
        Thread.sleep(10000);
        Date endTime = Calendar.getInstance().getTime();

        long difference = endTime.getTime() - startTime.getTime();

        long differenceSeconds = difference / 1000 % 60;
        long differenceMinutes = difference / (60 * 1000) % 60;
        long differenceHours = difference / (60 * 60 * 1000) % 24;
        long differenceDays = difference / (24 * 60 * 60 * 1000);

        System.out.println(differenceDays + " days, ");
        System.out.println(differenceHours + " hours, ");
        System.out.println(differenceMinutes + " minutes, ");
        System.out.println(differenceSeconds + " seconds.");

    } catch (Exception e) {
        e.printStackTrace();
    }
}

}


1
import java.sql.*;

class Time3 {

    public static void main(String args[]){ 
        String time1 = "01:03:23";
        String time2 = "02:32:00";
        long difference ;
        Time t1 = Time.valueOf(time1);
        Time t2 = Time.valueOf(time2);
        if(t2.getTime() >= t1.getTime()){
            difference = t2.getTime() - t1.getTime() -19800000;
        }
        else{
            difference = t1.getTime() - t2.getTime() -19800000;
        }

        java.sql.Time time = new java.sql.Time(difference); 
        System.out.println(time);
    } 

} 

1

我发现这更干净。

       Date start = new Date();
        //Waiting for 10 seconds
        Thread.sleep(10000);
        Date end = new Date();
        long diff = end.getTime() - start.getTime();
        String TimeTaken = String.format("[%s] hours : [%s] mins : [%s] secs",
                Long.toString(TimeUnit.MILLISECONDS.toHours(diff)), 
                TimeUnit.MILLISECONDS.toMinutes(diff),
                TimeUnit.MILLISECONDS.toSeconds(diff));
        System.out.println(String.format("Time taken %s", TimeTaken));

输出:花费的时间[0]小时:[0]分钟:[10]秒


0
    /*
 * Total time calculation.
 */
private void getTotalHours() {
    try {
        // TODO Auto-generated method stub
        if (tfTimeIn.getValue() != null && tfTimeOut.getValue() != null) {
            Long min1 = tfTimeOut.getMinutesValue();
            Long min2 = tfTimeIn.getMinutesValue();
            Long hr1 = tfTimeOut.getHoursValue();
            Long hr2 = tfTimeIn.getHoursValue();
            Long hrsTotal = new Long("0");
            Long minTotal = new Long("0");
            if ((hr2 - hr1) == 1) {
                hrsTotal = (long) 1;
                if (min1 != 0 && min2 == 0) {
                    minTotal = (long) 60 - min1;
                } else if (min1 == 0 && min2 != 0) {
                    minTotal = min2;
                } else if (min1 != 0 && min2 != 0) {
                    minTotal = min2;
                    Long minOne = (long) 60 - min1;
                    Long minTwo = min2;
                    minTotal = minOne + minTwo;
                }
                if (minTotal >= 60) {
                    hrsTotal++;
                    minTotal = minTotal % 60;
                }
            } else if ((hr2 - hr1) > 0) {
                hrsTotal = (hr2 - hr1);
                if (min1 != 0 && min2 == 0) {
                    minTotal = (long) 60 - min1;
                } else if (min1 == 0 && min2 != 0) {
                    minTotal = min2;
                } else if (min1 != 0 && min2 != 0) {
                    minTotal = min2;
                    Long minOne = (long) 60 - min1;
                    Long minTwo = min2;
                    minTotal = minOne + minTwo;
                }
                if (minTotal >= 60) {
                    minTotal = minTotal % 60;
                }
            } else if ((hr2 - hr1) == 0) {
                if (min1 != 0 || min2 != 0) {
                    if (min2 > min1) {
                        hrsTotal = (long) 0;
                        minTotal = min2 - min1;
                    } else {
                        Notification.show("Enter A Valid Time");
                        tfTotalTime.setValue("00.00");
                    }
                }
            } else {
                Notification.show("Enter A Valid Time");
                tfTotalTime.setValue("00.00");
            }
            String hrsTotalString = hrsTotal.toString();
            String minTotalString = minTotal.toString();
            if (hrsTotalString.trim().length() == 1) {
                hrsTotalString = "0" + hrsTotalString;
            }
            if (minTotalString.trim().length() == 1) {
                minTotalString = "0" + minTotalString;
            }
            tfTotalTime.setValue(hrsTotalString + ":" + minTotalString);
        } else {
            tfTotalTime.setValue("00.00");
        }
    }
    catch (Exception e) {
        e.printStackTrace();
    }
}

2
尽管此代码可以回答问题,但提供有关此代码为何和/或如何回答问题的其他上下文,可以改善其长期价值。
本杰明·W.

0

class TimeCalculator {字符串updateTime;

     public TimeCalculator(String time)
      {
        // time should be in 24 hours format like 15/06/2016 17:39:20  
        this.updateTime = time;
      }

     public String getTimeDifference()
     {
        String td=null;
       // get Current Time
        SimpleDateFormat sdf = new SimpleDateFormat("dd/MM/yyyy hh:mm:ss");
        Date currentDate = new Date();
        Calendar calendar = new GregorianCalendar();
        calendar.setTime(currentDate);

        int c_year = calendar.get(Calendar.YEAR);
        int c_month = calendar.get(Calendar.MONTH) + 1;
        int c_day = calendar.get(Calendar.DAY_OF_MONTH);

        // get Editing Time

        Date edit_date = sdf.parse(updateTime);
        Calendar edit_calendar = new GregorianCalendar();
        edit_calendar.setTime(edit_date);

        int e_year = edit_calendar.get(Calendar.YEAR);
        int e_month = edit_calendar.get(Calendar.MONTH) + 1;
        int e_day = edit_calendar.get(Calendar.DAY_OF_MONTH);


        if(e_year==c_year&&e_month==c_month&&e_day==c_day)
            {

             int c_hours = calendar.get(Calendar.HOUR_OF_DAY);
             int c_minutes = calendar.get(Calendar.MINUTE);
             int c_seconds = calendar.get(Calendar.SECOND);

             int e_hours = edit_calendar.get(Calendar.HOUR_OF_DAY);
             int e_minutes = edit_calendar.get(Calendar.MINUTE);
             int e_seconds = edit_calendar.get(Calendar.SECOND);

      if(c_hours==e_hours&&c_minutes==e_minutes&&c_seconds==e_seconds)
         {
           td = "just now";
           return td;
          }
      else if(c_hours==e_hours&&c_minutes==e_minutes)
       {
         int d_seconds = c_seconds-e_seconds;
         td = String.valueOf(d_seconds);
         td = td+" seconds ago";
         return td;
       }
      else if(c_hours==e_hours&&c_minutes!=e_minutes)
       {
         int d_minutes = c_minutes-e_minutes;
         int d_seconds;
         if(c_seconds>e_seconds)
           {
             d_seconds = c_seconds-e_seconds;
           }else{
             d_seconds = e_seconds-c_seconds;
       }
          td = "00:"+String.valueOf(d_minutes)+":"+String.valueOf(d_seconds)+" ago";
        return td;
  }
    else
       {
        int d_minutes,d_seconds,d_hours;
        d_hours=c_hours-e_hours;
        if(c_minutes>e_minutes)
       {
         d_minutes = c_minutes-e_minutes;
       }else{
         d_minutes = e_minutes-c_minutes;
       }
        if(c_seconds>e_seconds)
          {
            d_seconds = c_seconds-e_seconds;
          }else{
            d_seconds = e_seconds-c_seconds;
          }

      td = String.valueOf(d_hours)+":"+String.valueOf(d_minutes)+":"+String.valueOf(d_seconds)+" ago";
     return td;
  }
}
 else if(e_year==c_year&&e_month==c_month&&c_day==e_day+1){
   td = "yesterday";
   return td;
 }
 else{
    td = updateTime;
    return td;
     }
}}

0

试试这个:

public String timeDifference8(String startTime, String endTime) {
    LocalTime initialTime = LocalTime.parse(startTime);
    LocalTime finalTime =LocalTime.parse(endTime);
    StringJoiner joiner = new StringJoiner(":");
    long hours = initialTime.until( finalTime, ChronoUnit.HOURS);
    initialTime = initialTime.plusHours( hours );
    long minutes = initialTime.until(finalTime, ChronoUnit.MINUTES);
    initialTime = initialTime.plusMinutes( minutes );
    long seconds = initialTime.until( finalTime, ChronoUnit.SECONDS);
    joiner.add(String.valueOf(hours));
    joiner.add(String.valueOf(minutes));
    joiner.add(String.valueOf(seconds));
    return joiner.toString();
}
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