Answers:
您需要用于sp_addlinkedserver
创建服务器链接。有关用法,请参见参考文档。建立服务器链接后,您将像平常一样构造查询,只需在数据库名称前加上其他服务器即可。IE浏览器:
-- FROM DB1
SELECT *
FROM [MyDatabaseOnDB1].[dbo].[MyTable] tab1
INNER JOIN [DB2].[MyDatabaseOnDB2].[dbo].[MyOtherTable] tab2
ON tab1.ID = tab2.ID
建立链接后,您还可以OPENQUERY
用来在远程服务器上执行SQL语句,并且仅将数据传输回给您。这可能会更快一些,它将使远程服务器优化您的查询。如果您DB1
在上面的示例中将数据缓存到临时(或内存中)表中,则可以像联接标准表一样对其进行查询。例如:
-- Fetch data from the other database server
SELECT *
INTO #myTempTable
FROM OPENQUERY([DB2], 'SELECT * FROM [MyDatabaseOnDB2].[dbo].[MyOtherTable]')
-- Now I can join my temp table to see the data
SELECT * FROM [MyDatabaseOnDB1].[dbo].[MyTable] tab1
INNER JOIN #myTempTable tab2 ON tab1.ID = tab2.ID
查看OPENQUERY的文档以查看更多示例。上面的示例非常人为。我肯定会在此特定示例中使用第一种方法,但是OPENQUERY
如果您使用查询过滤掉一些数据,则第二种使用方法可以节省一些时间和性能。
试试这个:
SELECT tab2.column_name
FROM [DB1.mdf].[dbo].[table_name_1] tab1 INNER JOIN [DB2.mdf].[dbo].[table_name_2] tab2
ON tab1.col_name = tab2.col_name
我在下面尝试了这段代码,它工作正常
SELECT TimeTrackEmployee.StaffID
FROM dbo.tblGBSTimeCard AS GBSTimeCard INNER JOIN
TimeTrak.dbo.tblEmployee AS TimeTrackEmployee ON GBSTimeCard.[Employee Number] = TimeTrackEmployee.GBSStaffID
当我在连接这两个表时遇到麻烦时,我无法通过同时打开两个远程数据库来完成我想要的事情。MySQL 5.6(php 7.1)和其他MySQL 5.1(php 5.6)
//Open a new connection to the MySQL server
$mysqli1 = new mysqli('server1','user1','password1','database1');
$mysqli2 = new mysqli('server2','user2','password2','database2');
//Output any connection error
if ($mysqli1->connect_error) {
die('Error : ('. $mysqli1->connect_errno .') '. $mysqli1->connect_error);
} else {
echo "DB1 open OK<br>";
}
if ($mysqli2->connect_error) {
die('Error : ('. $mysqli2->connect_errno .') '. $mysqli2->connect_error);
} else {
echo "DB2 open OK<br><br>";
}
如果屏幕上显示这两个确定,则两个数据库都已打开并准备就绪。然后,您可以继续进行查询。
$results = $mysqli1->query("SELECT * FROM video where video_id_old is NULL");
while($row = $results->fetch_array()) {
$theID = $row[0];
echo "Original ID : ".$theID." <br>";
$doInsert = $mysqli2->query("INSERT INTO video (...) VALUES (...)");
$doGetVideoID = $mysqli2->query("SELECT video_id, time_stamp from video where user_id = '".$row[13]."' and time_stamp = ".$row[28]." ");
while($row = $doGetVideoID->fetch_assoc()) {
echo "New video_id : ".$row["video_id"]." user_id : ".$row["user_id"]." time_stamp : ".$row["time_stamp"]."<br>";
$sql = "UPDATE video SET video_id_old = video_id, video_id = ".$row["video_id"]." where user_id = '".$row["user_id"]."' and video_id = ".$theID.";";
$sql .= "UPDATE video_audio SET video_id = ".$row["video_id"]." where video_id = ".$theID.";";
// Execute multi query if you want
if (mysqli_multi_query($mysqli1, $sql)) {
// Query successful do whatever...
}
}
}
// close connection
$mysqli1->close();
$mysqli2->close();
我试图进行一些连接,但是由于我打开了这两个数据库,因此可以通过更改连接$mysqli1
或来回查询。$mysqli2
它对我有用,希望对您有帮助...