151 交叉联接只是两组的笛卡尔乘积。没有明确的联接运算符。 var combo =来自人中的p 从汽车中的c 选择新的 { p。名称, c。制作 c。型号 颜色 }; — 史蒂夫·摩根 source 2 您如何from p in people from c in cars用lambda表示法写出来? — 运动 47 people.SelectMany(p => cars, (p, c) => new { ... }) — 伊恩·加洛韦
38 用同样的事情linq扩展方法: var names = new string[] { "Ana", "Raz", "John" }; var numbers = new int[] { 1, 2, 3 }; var newList=names.SelectMany( x => numbers, (y, z) => { return y + z + " test "; }); foreach (var item in newList) { Console.WriteLine(item); } — 即时通讯 source
25 根据史蒂夫的回答,最简单的表达是: var combo = from Person in people from Car in cars select new {Person, Car}; — 马克·西达德 source
11 A Tuple是笛卡尔积的好类型: public static IEnumerable<Tuple<T1, T2>> CrossJoin<T1, T2>(IEnumerable<T1> sequence1, IEnumerable<T2> sequence2) { return sequence1.SelectMany(t1 => sequence2.Select(t2 => Tuple.Create(t1, t2))); } — 阿莫斯 source
6 扩展方式: public static IEnumerable<Tuple<T1, T2>> CrossJoin<T1, T2>(this IEnumerable<T1> sequence1, IEnumerable<T2> sequence2) { return sequence1.SelectMany(t1 => sequence2.Select(t2 => Tuple.Create(t1, t2))); } 并使用像: vals1.CrossJoin(vals2) — 丹尼斯 source
from p in people from c in cars
用lambda表示法写出来?