我在brew上遇到openssl和python @ 2的问题,这里已经解释了(未解决)。已记录的重新安装Python和openssl的解决方法无法正常工作,因此我决定卸载并重新安装Python。
问题是,当您尝试通过brew安装Python 2时,会收到以下消息:
brew install python@2
Error: No available formula with the name "python@2"
==> Searching for a previously deleted formula (in the last month)...
Warning: homebrew/core is shallow clone. To get complete history run:
git -C "$(brew --repo homebrew/core)" fetch --unshallow
python@2 was deleted from homebrew/core in commit 028f11f9e:
python@2: delete (https://github.com/Homebrew/homebrew-core/issues/49796)
EOL 1 January 2020.
We gave it 1 month more to live so that people had time to migrate.
All in all, developers had 11 years to do their migration.
You can use the `brew extract` command and maintain python@2 in your own
tap if necessary:
https://docs.brew.sh/How-to-Create-and-Maintain-a-Tap
To show the formula before removal run:
git -C "$(brew --repo homebrew/core)" show 028f11f9e^:Formula/python@2.rb
If you still use this formula consider creating your own tap:
https://docs.brew.sh/How-to-Create-and-Maintain-a-Tap
不幸的是,我仍然有许多取决于Brew的python @ 2的brew公式。这些包括awscli
,letsencrypt
,PR sshuttle
例如
aws
zsh: /usr/local/bin/aws: bad interpreter: /usr/local/opt/python@2/bin/python2.7: no such file or directory
我不知道如何使用brew extract
他们记录的命令重新安装Python @ 2。它需要一个公式和一个水龙头。我想公式会是python@2
。我不确定水龙头将是什么。
此外,重新安装水龙头,例如aws
或letsencrypt
效果也不佳。
重新安装awscli
(brew reinstall awscli
)后,运行aws命令仍然会出现错误。
aws
/usr/local/Cellar/awscli/2.0.0/libexec/lib/python3.8/site-packages/jmespath/visitor.py:32: SyntaxWarning: "is" with a literal. Did you mean "=="?
if x is 0 or x is 1:
/usr/local/Cellar/awscli/2.0.0/libexec/lib/python3.8/site-packages/jmespath/visitor.py:32: SyntaxWarning: "is" with a literal. Did you mean "=="?
if x is 0 or x is 1:
/usr/local/Cellar/awscli/2.0.0/libexec/lib/python3.8/site-packages/jmespath/visitor.py:34: SyntaxWarning: "is" with a literal. Did you mean "=="?
elif y is 0 or y is 1:
/usr/local/Cellar/awscli/2.0.0/libexec/lib/python3.8/site-packages/jmespath/visitor.py:34: SyntaxWarning: "is" with a literal. Did you mean "=="?
elif y is 0 or y is 1:
/usr/local/Cellar/awscli/2.0.0/libexec/lib/python3.8/site-packages/jmespath/visitor.py:260: SyntaxWarning: "is" with a literal. Did you mean "=="?
if original_result is 0:
usage: aws [options] <command> <subcommand> [<subcommand> ...] [parameters]
To see help text, you can run:
aws help
aws <command> help
aws <command> <subcommand> help
aws: error: the following arguments are required: command